\(\dfrac{2\times x-4,36}{0,125}=0,25\times42,9-11,7\times0,25+0,25\times0,8\)

\(\dfrac{2\times x-4,36}{0,125}=0,25\times\left(42,9-11,7+0,8\right)\)

\(\dfrac{2\times x-4,36}{0,125}=0,25\times32=8\)

\(2\times x-4,36=8\times0,125=1\)

\(2\times x=1+4,36=5,36\)

      \(x=5,36\div2\)

      \(x=2,68\)

#)Giải :

a) \(\frac{2xX-4,36}{0,125}=\)0,25 x 42,9 - 11,7 x 0,25 + 0,25 x 0,8

\(\frac{2xX-4,36}{0,125}=\)0,25 x ( 42,9 - 11,7 + 0,8 )

\(\frac{2xX-4,36}{0,125}=\)0,25 x 32

\(\frac{2xX-4,36}{0,125}=8\)

\(2xX-4,36=8x0,125\)

\(2xX-4,36=1\)

\(2xX=1+4,36\)

\(2xX=5,36\)

\(X=5,36:2\)

\(X=2,68\)

              #~Will~be~Pens~#

#)Next : 

b) 104,5 x X - 14,1 x X + 9,6 x X = 25

   ( 104,5 - 14,1 + 9,6 ) x X          = 25

   100 x X                                   = 25

            X                                   = 25 : 100

            X                                   = 0,25

                #~Will~be~Pens~#

b,

104,5.x-14,1.x+9,6.x=25

x(104,5-14,1+9,6)=25

x.100=25

x=25:100

x=0,25

\(\frac{2x-4.36}{0.125}=0.25\cdot42.9-11.7\cdot0.25+0.25\cdot0.8\)

\(\frac{2x-4.36}{0.125}=0.25\left(42.9-11.7+0.8\right)\)

\(\frac{2x-4.36}{0.125}=0.25\cdot32\)

\(\frac{2x-4.36}{0.125}=8\)

2x - 4.36 = 8 * 0.125 = 1

2x = 1 + 4.36 = 5.36

x = 5.36 : 2 = 2.68 

\(2x-\frac{4.36}{0.125}=0.15\times42.9-11.7\times0,25\times0.8\)

\(2x-\frac{872}{25}=\frac{819}{200}\)

\(2x=\frac{819}{200}+\frac{872}{25}=\frac{1559}{40}\)

\(x=\frac{1559}{40}\times\frac{1}{2}=\frac{1559}{80}\)

2xX+X:0,125=10

2xX+Xx1/8=10

Xx(2+1/8)=10

Xx2,125=10

X=10:2,125

X=80/17

x:0,125=10-2xX

X        =1,25-0,25xX

x+0,25xX=1,25

x            =1

có đúng không?

\(\frac{4}{7}.x+0,125=1\frac{1}{8}+x\)

=>\(\frac{4}{7}.x+\frac{1}{8}=1+x+\frac{1}{8}\)

=>\(\frac{4}{7}.x=1+x\)

=>\(\frac{4}{7}.x-x=1\)

=>\(\left(\frac{4}{7}-1\right)x=1\)

=>\(\frac{-3}{7}.x=1\)

=>\(x=1:\frac{-3}{7}=\frac{1.7}{-3}=-\frac{7}{3}\)

\(\frac{2x-4,36}{0,125}=0,25.42,9-11,7.0,25+0,25.0,8\)

\(\Leftrightarrow\frac{2x-4,36}{0,125}=0,25.\left(42,9-11.7+0,8\right)\)

\(\Leftrightarrow\frac{2x-4,36}{0,125}=0,25.32\)

\(\Leftrightarrow\frac{2x-4,36}{0,125}=8\)

\(\Leftrightarrow2x-4,36=1\)

\(\Leftrightarrow2x=5,36\)

\(\Leftrightarrow x=2,68\)

b) \(N=\frac{1}{1.5}+\frac{1}{5.10}+\frac{1}{10.15}+\frac{1}{15.20}+...+\frac{1}{2005.2010}\)

\(\Leftrightarrow N=\frac{1}{5}\left(1-\frac{1}{5}+\frac{1}{5}-\frac{1}{10}+\frac{1}{10}-\frac{1}{15}+\frac{1}{15}-\frac{1}{20}+...+\frac{1}{2005}-\frac{1}{2010}\right)\)

\(\Leftrightarrow N=\frac{1}{5}\left(1-\frac{1}{2010}\right)\)

\(\Leftrightarrow N=\frac{1}{5}.\frac{2009}{2010}=\frac{2009}{10050}\)

Bài 1:

a)\(\frac{2\cdot x-4,36}{0,125}=0,25\cdot42,9-11,7\cdot0,25+0,25\cdot0,8\)

\(\frac{2\cdot x-4,36}{0,125}=0,25\cdot\left(42,9-11,7+0,8\right)\)

\(\frac{2\cdot x-4,36}{0,125}=0,25\cdot32\)

\(\frac{2\cdot x-4,36}{0,125}=8\)

\(2\cdot x-4,36=8\cdot0,125\)

\(2\cdot x-4,36=1\)

\(2\cdot x=1+4,36\)

\(2\cdot x=5,36\)

\(x=\frac{5,36}{2}=2,68\)

b) \(N=\frac{1}{1\cdot5}+\frac{1}{5\cdot10}+\frac{1}{10\cdot15}+\frac{1}{15\cdot20}+...+\frac{1}{2005\cdot2010}\)

\(4N=\frac{4}{1\cdot5}+\frac{4}{5\cdot10}+\frac{4}{10\cdot15}+\frac{4}{15\cdot20}+...+\frac{4}{2005\cdot2010}\)

\(4N=1-\frac{1}{5}+\frac{1}{5}-\frac{1}{10}+\frac{1}{10}-\frac{1}{15}+\frac{1}{15}-\frac{1}{20}+...+\frac{1}{2005}-\frac{1}{2010}\)

\(4N=1-\frac{1}{2010}=\frac{2009}{2010}\)

\(N=\frac{2009}{2010}\div4=\frac{2009}{8040}\)

Bài 2:

a) ( x + 5,2 ) : 3,2 = 4,7 ( dư 0,5 )

\(x+5,2=4,7\cdot3,2+0,5\)

\(x+5,2=15,54\)

\(x=15,54-5,2=10,34\)

b)\(A=\frac{4047991-2010\cdot2009}{4050000-2011\cdot2009}\)

\(A=\frac{4047991-2010\cdot2009}{4050000-2009-2010\cdot2009}\)

\(A=\frac{4047991-2010\cdot2009}{4047991-2010\cdot2009}=1\)

Bài 3:

a) \(104,5\cdot x-14,1\cdot x+9,6\cdot x=25\)

\(x\cdot\left(104,5-14,1+9,6\right)=25\)

\(x\cdot100=25\)

\(x=\frac{25}{100}=\frac{1}{4}=0,25\)

b) \(T=\frac{2009\cdot2010+2000}{2011\cdot2010-2020}\)

\(T=\frac{2009\cdot2010+2000}{2009\cdot2010+4020-2020}\)

\(T=\frac{2009\cdot2010+2000}{2009\cdot2010+2000}=1\)