2P = 24.(5^2 + 1 )(5^4 + 1) ... (5^16 + 1)

2P = (5^2 - 1) (5^2 + 1) (5^4 + 1)  .. (5^16+1)

2P = (5^4 - 1 )(5^4 + 1 ) (5^8 + 1)

2P = (5^8 - 1 ) (5^8 + 1) (5^16 + 1)

2P = ( 5^ 16 - 1 ) 5^ 16 + 1)

2P = 5^32 - 1

P = (5^32 - 1) : 2

\(P=12.\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\)

\(\Rightarrow2P=24\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\)

\(\Leftrightarrow2P=\left(5^2-1\right)\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\)

\(\Leftrightarrow2P=\left(5^4-1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\)

\(\Leftrightarrow2P=\left(5^8-1\right)\left(5^8+1\right)\left(5^{16}+1\right)\)

\(\Leftrightarrow2P=\left(5^{16}-1\right)\left(5^{16}+1\right)\)

\(\Leftrightarrow2P=5^{32}-1\)

\(\Leftrightarrow P=\frac{5^{32}-1}{2}\)

2P = 24.(5^2 + 1 )(5^4 + 1) ... (5^16 + 1)

2P = (5^2 - 1) (5^2 + 1) (5^4 + 1)  .. (5^16+1)

2P = (5^4 - 1 )(5^4 + 1 ) (5^8 + 1)

2P = (5^8 - 1 ) (5^8 + 1) (5^16 + 1)

2P = ( 5^ 16 - 1 ) 5^ 16 + 1)

2P = 5^32 - 1

P = (5^32 - 1) : 2

đúng nha

đặt A=12(5^2+1)(5^4+1)(5^8+1)(5^16+1)

=>2a=24(5^2+1)(5^4-1)(5^8+1)(5^16+1)

=(5^4-1)(5^4+1)(5^8+1)(5^16+1)

=(5^16-1)(5^16+1)

=>A=(5^32-1)/2=1/2(5^32-1)

chúc bạn học toots^..^

\(C=12\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\)

\(=\frac{1}{2}\left(5^2-1\right)\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\)

\(=\frac{1}{2}\left(5^4-1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\)

\(=\frac{1}{2}\left(5^8-1\right)\left(5^8+1\right)\left(5^{16}+1\right)\)

\(=\frac{1}{2}\left(5^{16}-1\right)\left(5^{16}+1\right)\)

\(=\frac{1}{2}\left(5^{32}-1\right)\)

\(=\frac{5^{32}-1}{2}\)

Đinh Đức Hùng lấy 5² -1 ở đâu đấy

Lấy xong rồi thì phải chia lại chứ

Ta có:

P=12(5²+1)(5⁴+1)(5⁸+1)(5¹⁶+1)

P=(5²-1)(5²+1)(5⁴+1)(5⁸+1)(5¹⁶+1):2

P=(5^4-1)(5⁴+1)(5⁸+1)(5¹⁶+1):2

P=(5^8-1)(5⁸+1)(5¹⁶+1):2

P=(5¹⁶-1)(5¹⁶+1):2

P=(5³²-1):2

\(P=12\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\)

\(=\frac{1}{2}\left(5^2-1\right)\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\)

\(=\frac{1}{2}\left(5^4-1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\)

\(=\frac{1}{2}\left(5^8-1\right)\left(5^8+1\right)\left(5^{16}+1\right)\)

\(=\frac{1}{2}\left(5^{16}-1\right)\left(5^{16}+1\right)=\frac{5^{32}-1}{2}\)

\(12.\left(5^2+1\right).\left(5^4+1\right).\left(5^8+1\right).\left(5^{16}+1\right)\)

\(=\frac{24}{2}.\left(5^2+1\right).\left(5^4+1\right).\left(5^8+1\right).\left(5^{16}+1\right)\)

\(=\frac{5^2-1}{2}.\left(5^2+1\right).\left(5^4+1\right).\left(5^8+1\right).\left(5^{16}+1\right)\)

\(=\frac{5^4-1}{2}.\left(5^4+1\right).\left(5^8+1\right).\left(5^{16}+1\right)\)

\(=\frac{5^8-1}{2}.\left(5^8+1\right).\left(5^{16}+1\right)\)

\(=\frac{5^{16}-1}{2}.\left(5^{16}+1\right)\)

\(=\frac{5^{32}-1}{2}\)

P= 12(5^2+1)(5^4+1)(5^8+1)(5^16+1) 
=> 2P = 24(5^2+1)(5^4+1)(5^8+1)(5^16+1) 
=(5^2-1)(5^2+1)(5^4+1)(5^8+1)(5^16+1) 
=(5^4-1)(5^4+1)(5^8+1)(5^16+1) 
=(5^8-1)(5^8+1)(5^16+1) 
=(5^16-1)(5^16+1) 
=5^32-1 
=> P = (5^32-1)/2 

idonno

giupminhdi