=(3/4+16/4)+(5/7+2/7)-2

=(3/4+1/4)+(5/7+2/7)-2

= 1+1-2

=0

A = 1 + 2 +  2x2 + 2x2x2 + 2x2x2x2 + ... + 2x2x...x2 _{^{9 lần số 2}}

=> 2xA = 2 + 2x2 + 2x2x2 + ... + 2x2x...x2 _{^{( 10 lần số 2)}}

=> 2xA - A = 2 + 2x2 + 2x2x2 + ... + 2x2x...x2 _{^{10 lần số 2}} - ( 1 + 2 +  2x2 + 2x2x2 + 2x2x2x2 + ... + 2x2x...x2 _{^{9 lần số 2}} )

=> A = 2x2x2x...x2 - 1_{^{10 lần số 2}} = 512x2 - 1 = 1024 - 1 = 1023

[1+3+...+13+15] x[16 x2+4x16-32x3]                                                                                                                                                                =[1+3+...+13+15] x 0                                                                                                                                                                        =0

( 1 + 3 + .... + 13 + 15 ) x ( 16 * 2 + 4 * 16 - 32 * 3 )

= ( 1+ 3 + ... + 13 + 15) x ( 16 * 2 + 4 * 16 - 16 * 2 * 3)

= ( 1 + 3 + ...+ 13 + 15) x { [ 16 * ( 2 + 4 -  2 * 3 ) ] }

= ( 1 + 3 + ... + 13 + 15 ) x  16 * 0

= ( 1 + 3 + .... +13 +15 ) x 0

=0

=A x (16-9-7): (2+4+6+8+...+20)

=(A x 0): (2+4+6+8+...+20)

=0 x (2+4+6+8+...+20)

=0

Bài làm

\(\frac{\left(1+\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}\right)}{\left(1-\frac{1}{2}+\frac{1}{4}-\frac{1}{8}+\frac{1}{16}\right)}\)

\(=\frac{\left(\frac{2}{2}+\frac{1}{2}+\frac{1}{2^2}+\frac{1}{2^3}+\frac{1}{2^4}\right)}{\left(\frac{2}{2}-\frac{1}{2}+\frac{1}{2^2}-\frac{1}{2^3}+\frac{1}{2^4}\right)}\)

\(=\frac{\frac{1}{2}\left(2+1+\frac{1}{2}+\frac{1}{2^2}+\frac{1}{2^3}\right)}{\frac{1}{2}\left(2-1+\frac{1}{2}-\frac{1}{2^2}+\frac{1}{2^3}\right)}\)

\(=\frac{3+\frac{1}{2}+\frac{1}{2^2}+\frac{1}{2^3}}{1+\frac{1}{2}-\frac{1}{2^2}+\frac{1}{2^3}}\)

\(=\frac{\frac{24}{8}+\frac{4}{8}+\frac{2}{8}+\frac{1}{8}}{\frac{8}{8}+\frac{4}{8}-\frac{2}{8}+\frac{1}{8}}\)

\(=\frac{31}{8}\div\frac{11}{8}\)

\(=\frac{31}{8}\cdot\frac{8}{11}\)

\(=\frac{31}{11}\)

P/S: Trông không thuận tiện lắm :/

Hawy tính giúp mình nha mình cho đúng

Nhanh lên giúp tớ

1413/160

\(A=\dfrac{49}{5}-\left(\dfrac{1}{2}+\dfrac{1}{4}+\dfrac{1}{8}+\dfrac{1}{16}+\dfrac{1}{32}\right)\)

\(A=\dfrac{49}{5}-\left(1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{8}+\dfrac{1}{8}-\dfrac{1}{16}+\dfrac{1}{16}-\dfrac{1}{32}\right)\)

\(A=\dfrac{49}{5}-\left(1-\dfrac{1}{32}\right)=\text{​​}\dfrac{49}{5}-\dfrac{31}{32}\text{​​}\)

\(A=\dfrac{1413}{160}\text{​​}\)

302 x 16 + 302 x 4

= 302 x ( 16 +4)

= 302 x 20 = 6040