a) \(435-\left(x+16\right)=425:17\)

\(435-\left(x+16\right)=25\)

\(x+16=435-25\)

\(x+16=410\)

\(x=410-16\)

\(x=394\)

b) \(\left(x+\frac{3}{4}\right)\times\frac{7}{4}+\frac{7}{6}=5\)

\(\left(x+\frac{3}{4}\right)\times\frac{7}{4}=5-\frac{7}{6}\)

\(\left(x+\frac{3}{4}\right)\times\frac{7}{4}=\frac{23}{6}\)

\(x+\frac{3}{4}=\frac{23}{6}:\frac{7}{4}\)

\(x+\frac{3}{4}=\frac{46}{21}\)

\(x=\frac{46}{21}-\frac{3}{4}\)

\(x=\frac{121}{84}\)

435 - ( x + 16 ) = 425 : 17

435 - ( x + 16 ) = 25

           x + 16   = 435 - 25

           x + 16   = 410

           x           = 410 - 16

           x           = 394

\(435-\left(x+16\right)=425\div17\)

\(435-\left(x+16\right)=25\)

\(x+16=435-25\)

\(x+16=410\)

\(x=410-16\)

\(x=394\)

\(\left(x+\frac{3}{4}\right)\times\frac{7}{4}+\frac{7}{6}=5\)

\(\left(x+\frac{3}{4}\right)\times\frac{7}{4}=5-\frac{7}{6}\)

\(\left(x\times\frac{3}{4}\right)\times\frac{7}{4}=\frac{23}{6}\)

\(x+\frac{3}{4}=\frac{23}{6}\div\frac{7}{4}\)

\(x\times\frac{3}{4}=\frac{46}{21}\)

\(x=\frac{46}{21}-\frac{3}{4}\)

\(x=\frac{121}{84}\)

\(\)

\(2\frac{3}{4}.\frac{1}{2}-\frac{1}{2}.\frac{3}{7}+\frac{1}{3}\)

\(=\frac{11}{4}.\frac{1}{2}-\frac{1}{2}.\frac{3}{7}+\frac{1}{3}\)

\(=\frac{11}{8}-\frac{3}{14}+\frac{1}{3}\)

\(=\frac{251}{168}\)

Bài 1 : a, thực hiện phép tính : 

\(2\frac{3}{4}×\frac{1}{2}-\frac{1}{2}×\frac{3}{7}+\frac{1}{3}\)

\(=\frac{11}{4}×\frac{1}{2}-\frac{1}{2}×\frac{3}{7}+\frac{1}{3}\)

\(=\frac{1}{2}×\left(\frac{11}{4}-\frac{3}{7}\right)+\frac{1}{3}\)

\(=\frac{1}{2}×\frac{65}{28}+\frac{1}{3}\)

\(=\frac{65}{56}+\frac{1}{3}\)

\(=\frac{251}{168}\)

b , Tìm x biết : 

a, 435- ( x + 16 ) = 425 : 17 

435 - ( x + 16 ) = 25 

x + 16 = 435 - 25 

x + 16 = 410 

x  = 410 - 16 

x = 394 

Vậy x = 394 

b, ( x + 3/4 ) × 7/4 = 5 - 7/6 

( x + 3/4 ) × 7/4 = 23/6 

x + 3/4 = 23/6 : 7/4 

x + 3/4 = 23/6 × 4/7 

x + 3/4 = 46/21 

x = 46/21 - 3/4 

x = 121/84

Vậy x = 121/84 

435 - ( x + 16 ) = 25

( x + 16 ) =435-25

( x+ 16) = 410

x = 410 -16 

x = 394

minh chi tra loi cau a thoi nhe

435-(x+16)=425:17

=435-(x+16)=25

=x+16=435-25

x+16=410

x=410-16

x=394

5,5 + \(\dfrac{3}{4}\) - 5 + \(\dfrac{1}{4}\)

(5,5 - 5) + (\(\dfrac{3}{4}\) + \(\dfrac{1}{4}\))

= 0,5  + 1

= 1,5 

\(\dfrac{5}{2}\) x  \(\dfrac{2}{3}\) + \(\dfrac{1}{4}\) : \(\dfrac{3}{2}\)

= \(\dfrac{5}{2}\) x \(\dfrac{2}{3}\) + \(\dfrac{1}{4}\) x \(\dfrac{2}{3}\)

=  (\(\dfrac{5}{2}\) + \(\dfrac{1}{4}\)) x \(\dfrac{2}{3}\)

= (\(\dfrac{10}{4}\) + \(\dfrac{1}{4}\)) x \(\dfrac{2}{3}\)

= \(\dfrac{11}{4}\) x \(\dfrac{2}{3}\)

= \(\dfrac{11}{6}\) 

Tính \(x\): 

  435  - [\(x\) + 16] = 425 : 17

  435 - [\(x\) + 16] = 25

          [\(x\) + 16] = 435 - 25

           \(x\) + 16 = 410

           \(x\)        = 410 - 16

          \(x\)         = 394

\(x\) x \(\dfrac{1}{4}\) - \(\dfrac{3}{4}\) = 6 : \(\dfrac{3}{4}\)

\(x\) \(\times\) \(\dfrac{1}{4}\) - \(\dfrac{3}{4}\) = 6 x \(\dfrac{4}{3}\)

\(x\) x \(\dfrac{1}{4}\) - \(\dfrac{3}{4}\)  = 8

\(x\) x \(\dfrac{1}{4}\)        = 8 + \(\dfrac{3}{4}\)

\(x\) x \(\dfrac{1}{4}\)        = \(\dfrac{32}{4}\) + \(\dfrac{3}{4}\)

\(x\) x \(\dfrac{1}{4}\)       = \(\dfrac{35}{4}\)

\(x\)              =  \(\dfrac{35}{4}\) : \(\dfrac{1}{4}\)

\(x\)              = \(\dfrac{35}{4}\) x 4

\(x\)             = 35

bài2 \(x\times\dfrac{15}{16}-x\times\dfrac{4}{16}=2\) 

     \(x\times\dfrac{11}{16}=2\) 

     \(x=2:\dfrac{11}{16}\) 

    \(x=\dfrac{32}{11}\)

Bài 1 : 

 \(\dfrac{x}{16}\times\left(2017-1\right)=2\)

          \(\dfrac{x}{16}\times2016=2\)

                      \(\dfrac{x}{16}=\dfrac{2}{2016}\)

                         \(x=\dfrac{2}{2016}\times16\)

                         \(x=\dfrac{1}{63}\)

1- (5\(\dfrac{4}{9}\) +x+7\(\dfrac{7}{18}\)) : 15\(\dfrac{3}{4}\) = 0 

1- (\(\dfrac{49}{9}+x+\dfrac{133}{18}\)) : \(\dfrac{63}{4}=0\) 

 (\(\dfrac{49}{9}+\dfrac{133}{18}\)+\(x\) ) : \(\dfrac{63}{4}\) = 1 - 0 

       (\(\dfrac{77}{6}\) + \(x\) ) : \(\dfrac{63}{4}\) = 1

         \(\dfrac{77}{6}+x\)         = 1 x \(\dfrac{63}{4}\) 

          \(\dfrac{77}{6}\) + \(x\)          = \(\dfrac{63}{4}\)

                  \(x\)            = \(\dfrac{63}{4}\) - \(\dfrac{77}{6}\)

                  \(x=\) \(\dfrac{35}{12}\)

a) \(\Rightarrow72-20x-36x+84=30x-240-6x-84\)

\(\Rightarrow80x=480\Rightarrow x=6\)

b) \(\Rightarrow15x+25-8x+12=5x+6x+36+1\)

\(\Rightarrow4x=0\Rightarrow x=0\)

c) \(\Rightarrow10x-16-12x+15=12x-16+11\)

\(\Rightarrow14x=4\Rightarrow x=\dfrac{2}{7}\)

Bài 1 :

a. 4497

b. 11484

Bài 2 :

a. 5425

b. Ko rõ dấu thứ 2 nếu dấu trừ thì đ/á ra âm ( lớp 5 chưa học )

Còn lại dấu cộng và đ/á là 100

Bài 3 :

a. x = 17 . 5 . ( 111 - 99 ) = 1020

b. x = ( 509 + 355 ) : ( 840 : 35 ) = 36

Bài 4 :

Gọi số cần tìm là ab \(\left(a,b\inℕ|9\ge a>0,9\ge b\ge0\right)\)

→ số mới là 5ab

Ta có vì số mới gấp 26 lần số ban đầu nên ta đc :

5ab : ab = 26

→ ( 500 + ab ) : ab = 26

→ 500 : ab + ab : ab = 26

→ 500 : ab + 1 = 26

→ 500 : ab = 25

→ ab = 20 ( thỏa mãn điều kiện )

Thử lại ta đc 520 : 20 = 26 ( luôn đúng )

Vậy số cần tìm là 20.

Xin tick ạ !!!