Tính hợp lý

\(A= (\dfrac{92-\dfrac{1}{9}-\dfrac{2}{10}-\dfrac{3}{11}-...-\dfrac{91}{99}-\dfrac{92}{100}}{\dfrac{1}{45}+\dfrac{1}{50}+\dfrac{1}{55}+...+\dfrac{1}{495}+\dfrac{1}{500}}\) B= \(\dfrac{\dfrac{1}{2}+\dfrac{1}{3}+\dfrac{1}{4}+...+\dfrac{1}{8}+\dfrac{1}{9}+\dfrac{1}{10}}{\dfrac{1}{9}+\dfrac{2}{8}+\dfrac{3}{7}+...+\dfrac{8}{2}+\dfrac{9}{1}})\)

Tính hợp lí:

A= \(\dfrac{92-\dfrac{1}{9}-\dfrac{2}{10}-\dfrac{3}{11}-...-\dfrac{91}{99}-\dfrac{92}{100}}{\dfrac{1}{45}+\dfrac{1}{50}+\dfrac{1}{55}+...+\dfrac{1}{495}+\dfrac{1}{500}}\)

B= \(\dfrac{\dfrac{1}{2}+\dfrac{1}{3}+\dfrac{1}{4}+...+\dfrac{1}{8}+\dfrac{1}{9}+\dfrac{1}{10}}{\dfrac{1}{9}+\dfrac{2}{8}+\dfrac{3}{7}+...+\dfrac{8}{2}+\dfrac{9}{1}}\)

(92-1/9-2/10-3/11-...-92/100)/(1/45+1/50+1/55+...+1/500)

[92-1/9-2/10-3/11-....-92/100]:[1/45+1/50+1/55+....1/500]

Tính:(92-1/9-2/10-3/11-.......-92/100):(1/45+1/50+1/55+...+1/500)

tính [92-1/9-2/10-3/11-...-92/100]:[1/45+/50+1/55+...+1/500]

a) So sánh: -22/45 và -51/103

b) Tính:

( 92 - 1/9 - 2/10 - 3/11 - ... - 92/100 ) : ( 1/45 + 1/50 + 1/55 + ... + 1/500 )

92-1/9-2/10-3/11-....-92/100

------------------------------------

1/45+1/50+1/55+......+1/500

[92--1/9-2/10-3/11-4/12-92/100] :[1/45+1/50+1/55+1/60+1/500]