a) (10-x)²:3+3=-9

    (10-x)²:3=-9-3

    (10-x)²:3=-11

    (10-x)²=-11.3

    (10-x)²=-33

 Vô lí vì -33 ko chuyển đc mũ 2 

Vậy x e 0

b) |x-6|.7-4=31

    |x-6|=(31+4):7

    |x-6|=5

\(\Rightarrow\orbr{\begin{cases}x-6=5\Rightarrow5+6=11\\x-6=-5\Rightarrow x=-5+6=1\end{cases}}\)

Vậy.....................................................

a) \(\frac{\left(10-x\right)^2}{3}+3=-9\)

\(\Leftrightarrow\frac{\left(10-x\right)^2}{3}=-12\)

\(\Leftrightarrow\left(10-x\right)^2=-36\)( vô nghiệm vì (10-x)² \(\ge\)0 với mọi x thuộc Z)

b) |x-6|.7-(-2)²=-8+39

<=> |x-6|.7-4=31

<=> |x-6|.7=35

<=> |x-6|=5

\(\Leftrightarrow\orbr{\begin{cases}x-6=5\\x-6=-5\end{cases}\Leftrightarrow\orbr{\begin{cases}x=11\\x=1\end{cases}}}\)

a/  8.6+288:(X-3)²=50

48+288:(x-3)²=50

288:(x-3)²=50-48=2

(x-3)²=288:2=144

(x-3)²=12²

x-3=12

x=12+3=15

b/ (x² - (6²-(8²-9.7)²- 5.3)³= 1

(x² - (6²-(64-9.7)²- 5.3)³= 1

(x² - (6²-(64-63)²- 5.3)³= 1

(x² - (6²-1²- 5.3)³= 1

(x² - (36-1- 15)³= 1

x² - 20³= 1

x² - 8000= 1

x²=1+8000=8001

x²=................(de sai

b) 

{ x² - [ 6² - ( 8² - 9.7)³ - 7.5]³ - 5.3 }³ = 1

{ x² + [ 36 - (64 - 63)³ - 35]³ - 15}³ = 1

[ x² - ( 36 - 1³ - 35 ) - 15 ]³ = 1

[ x² - ( 36 - 1 - 35 ) - 15]³ = 1

[ x² - ( 35 - 35 ) - 15]³ = 1

[ x² - 0 - 15]³ = 1

( x² - 15 )³ = 1

<=> ( x² - 15)³ = 1³

=> x² - 15 = 1

<=> x² = 16

=> x = 4

ta có : \(\dfrac{-3}{6}=\dfrac{x}{-2}=\dfrac{-18}{y}=\dfrac{3}{24}\)

\(\Rightarrow\dfrac{-3}{6}=\dfrac{3}{24}\) (vô lí)

\(\Rightarrow\) đề sai