\(\left|x+\frac{4}{15}\right|-\left|-3,75\right|=-\left|-2,15\right|\)

\(\Rightarrow\left|x+\frac{4}{15}\right|-3,75=-2,15\)

\(\Rightarrow\left|x+\frac{4}{15}\right|=-2,15+3,75\)

\(\Rightarrow\left|x+\frac{4}{15}\right|=1,6=\frac{8}{5}\)

\(\Rightarrow\left[\begin{array}{nghiempt}x+\frac{4}{15}=\frac{8}{5}\\x+\frac{4}{15}=\frac{-8}{5}\end{array}\right.\)\(\Rightarrow\left[\begin{array}{nghiempt}x=\frac{4}{3}\\x=\frac{-28}{15}\end{array}\right.\)

Vậy \(\left[\begin{array}{nghiempt}x=\frac{4}{3}\\x=\frac{-28}{15}\end{array}\right.\)

| x + 4/15 | - | - 3,75 | = - | - 2,15 |

| x + 4/15 | - 3,75      = - 2,15

| x + 4/15 |               = - 2,15 + 3,75

| x + 4/15 |               = 1,6

Trường hợp 1 :  x + 4/15 = 1,6   suy ra x = 4/3

Trương hợp 2:  x + 4/15 = - 1,6 suy ra x = -28/15

b) | x + 415 | - | -3,75| = -(-2,15)

x+4/15=-1.6

\(\left|x+\frac{4}{15}\right|-\left|-3,75\right|=-\left|-2,15\right|\)

\(\Rightarrow\left|x+\frac{4}{15}\right|-3,75=-2,15\)

\(\Rightarrow\left|x+\frac{4}{15}\right|=-2,15+3,75\)

\(\Rightarrow\left|x+\frac{4}{15}\right|=1,6\)

\(\Rightarrow\left|x+\frac{4}{15}\right|=\frac{8}{5}\)

\(\Rightarrow\left[\begin{array}{nghiempt}x+\frac{4}{15}=\frac{8}{5}\\x+\frac{4}{15}=-\frac{8}{5}\end{array}\right.\)

\(\Rightarrow\left[\begin{array}{nghiempt}x=\frac{4}{3}\\x=-\frac{28}{15}\end{array}\right.\)

Ta có : \(\left|x+\frac{4}{15}\right|-\left|-3,75\right|=-\left|-2,15\right|\)

\(\Leftrightarrow\left|x+\frac{4}{15}\right|=3,75-2,15=\frac{8}{5}\)

\(\Rightarrow\left[\begin{array}{nghiempt}x+\frac{4}{15}=\frac{8}{5}\\-x-\frac{4}{15}=\frac{8}{5}\end{array}\right.\)

\(\Leftrightarrow\left[\begin{array}{nghiempt}x=\frac{4}{3}\\x=-\frac{28}{15}\end{array}\right.\)

| x + 4/15 | - | - 3,75 | = - | - 2,15 |
\(\Rightarrow\)| x + 4/15 | -  3,75  = - 2,15 |

\(\Rightarrow\)| x + 4/15 | =  3,75  +  (- 2,15)

\(\Rightarrow\)| x + 4/15 | =1,6

\(\Rightarrow\)x+4/15=1,6 hoặc x+4/15=-1,6

Ta xét các trường hợp

TH1: x+4/15=1,6\(\Rightarrow\)x=4/3

TH2:x+4/15=-1,6 \(\Rightarrow\)x=-28/15

Vậy x=4/3 hoặc -28/15

|x + 4/15| - |-3,75| = -|- 2,15|

=> |x + 4/15| - 3,75 = 2,15

=> |x + 4/15| = 59/10

=> \(\orbr{\begin{cases}x+\frac{4}{15}=\frac{59}{10}\\x+\frac{4}{15}=-\frac{59}{10}\end{cases}}\Rightarrow\orbr{\begin{cases}x=\frac{169}{30}\\x=\frac{-185}{30}\end{cases}}\)

\(\left|x+\frac{4}{15}\right|-\left|-3,75\right|=-\left|-2,15\right|\)

\(\left|x+\frac{4}{15}\right|-3,75=-2,15\)

\(\left|x+\frac{4}{15}\right|=-2,15+3,75\)

\(\left|x+\frac{4}{15}\right|=1,6\)

\(\left|x+\frac{4}{15}\right|=\frac{8}{5}\)

\(\Rightarrow\hept{\begin{cases}x+\frac{4}{15}=\frac{8}{5}\\x+\frac{4}{15}=\frac{-8}{5}\end{cases}\Rightarrow\hept{\begin{cases}x=\frac{8}{5}-\frac{4}{15}=\frac{4}{3}\\x=\frac{-8}{5}-\frac{4}{15}=\frac{-28}{15}\end{cases}}}\)

\(\left|x+\frac{4}{15}\right|-\left|-3,75\right|=-\left|-2,15\right|\)

\(\left|x+\frac{4}{15}\right|-3,75=-2,15\)

\(\left|x+\frac{4}{15}\right|=1,6\)

\(\orbr{\begin{cases}x+\frac{4}{15}=1,6\\x+\frac{4}{15}=-1,6\end{cases}}\)

Còn lại bn tự làm nha 

\(\left|x+\dfrac{4}{15}\right|-\left|-3,75\right|=-\left|-2,15\right|\)

\(\Leftrightarrow\left|x+\dfrac{4}{15}\right|=-2,15+3,75\)

\(\Leftrightarrow\left|x+\dfrac{4}{15}\right|=\dfrac{8}{5}\)

\(\Leftrightarrow\left[{}\begin{matrix}x+\dfrac{4}{15}=\dfrac{8}{5}\\x+\dfrac{4}{15}=-\dfrac{8}{5}\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{4}{3}\\x=-\dfrac{28}{15}\end{matrix}\right.\)

\(\Rightarrow\left|x+\dfrac{4}{15}\right|-3,75=-2,15\\ \Rightarrow\left|x+\dfrac{4}{15}\right|=1,6=\dfrac{8}{5}\\ \Rightarrow\left[{}\begin{matrix}x+\dfrac{4}{15}=\dfrac{8}{5}\\x+\dfrac{4}{15}=-\dfrac{8}{5}\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=\dfrac{4}{3}\\x=-\dfrac{28}{15}\end{matrix}\right.\)

            Bài làm :

Ta có :

\(\left|x+\frac{4}{15}\right|-\left|3,75\right|=-\left|2,15\right|\)

\(\Leftrightarrow\left|x+\frac{4}{15}\right|-3,75=-2,15\)

\(\Leftrightarrow\left|x+\frac{4}{15}\right|=1,6\)

\(\Leftrightarrow\orbr{\begin{cases}x+\frac{4}{15}=1,6\\x+\frac{4}{15}=-1,6\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=\frac{4}{3}\\x=-\frac{28}{15}\end{cases}}\)

Vậy x=4/3 hoặc x=-28/15

cảm ơn ~~

\(\left|x+\frac{4}{15}\right|-\left|-3,75\right|=-\left|-2,15\right|\)

=> \(\left|x+\frac{4}{15}\right|-3,75=-2,15\)

=> \(\left|x+\frac{4}{15}\right|=-2,15+3,75\)

=> \(\left|x+\frac{4}{15}\right|=1,6=\frac{8}{5}\)

=> \(\orbr{\begin{cases}x+\frac{4}{15}=\frac{8}{5}\\x+\frac{4}{15}=\frac{-8}{5}\end{cases}}\)=> \(\orbr{\begin{cases}x=\frac{4}{3}\\x=\frac{-28}{15}\end{cases}}\)

| x+ 4/15| - |-3,75| = - |- 2,15|

|x + 4/15| - 3,75 = - 2,15

|x + 4/15| = 8/5

Th1: x+4/15 = -8/5

x= -8/5 - 4/15

x= -28/15

Th2: x + 4/15 = 8/5

x= 8/5 - 4/15 

x= 4/3

Vậy x= -28/15 ; 4/3

\(\left|x+\frac{4}{15}\right|-\left|-3,75\right|=-\left|2-,15\right|\)

\(\left|x+\frac{4}{15}\right|-3,75=-2,15\)

\(\left|x+\frac{4}{15}\right|\)                = \(-2,15+3,75\)

\(\left|x+\frac{4}{15}\right|\)                = \(1,6\)

Th1  : \(\left|x+\frac{4}{15}\right|\)     = 1,6 => x = \(\frac{4}{3}\)

Th2 : \(\left|x+\frac{4}{15}\right|\)      = -1,6 => x = -28/15

|x+4/15|-|-3,75|=-|-2,15|

|x+4/15|-3,75=-2,15

|x+4/15|=-2,15+3,75

|x+4/15|= 1,6 hoặc -1,6

Với x+4/15= 1,6 => x = 1,6-4/15 = 4/3

Với x+4/15= -1,6 => x = -1,6-4/15= -28/15

Vậy x= 4/3 hoặc x = -28/15