tim x: x^3=343
Tim x biết: x^3=343
x^3=-27/343.Tim x
Có x3 = \(\left(-\frac{3}{7}\right)^3\) => x - -3/7
tim x sao cho (x+1)^3 = -343
(x+1)3=-343
(x+1)3=-73
x+1=-7
x=-7-1
x=-8
Vì: (-7)3 = -343
=> x + 1 = -7
x = -7 - 1
x = -8
ta co : (x + 1)^3 = -343 (x + 1)^3 = -7^3 suy ra (x + 1) = -7 x = -7 + 1 x = -6 vay x = -6 , tick minh nha Pham Thi Ha
tim x sao cho : (x+1)^3 =-343
Tim x sao cho (x+1)^3=-343
Trả lời:x=
(x+1)3 = -343
<=> (x+1)3 = (-7)3
<=> x+1 = -7
<=> x = -7 - 1
=> x = -8
(x+1)^3=(-7)^3 =>x=6 tk nha mk trc đó làm bài hộ
\(\left(x+1\right)^3=-343\)
\(\left(x+1\right)^3=\left(-7\right)^3\)
\(\Rightarrow x+1=-7\)
\(\Rightarrow x=-8\)
Vậy x=-8
tim x :a.x^3=343;b.x^8/243=27;c.(1/2)^2xX=(1/2)^5;d.(1/3)^3xX=1/81;e.8/2^x=2
Tim x.
52x -1 =343
DAM NGOC ANH ko có số x thõa mãn đề bài bn nhé!!!
tim so tu nhien x thoa man
a.\(25\le5^x\le125\)
b. \(7.7^{x+1}=343\)
c.
a) \(25\le5^x\le125\)
\(\Rightarrow5^2\le5^x\le5^3\)
\(\Rightarrow x\in\left\{2;3\right\}\)
b) \(7.7^{x+1}=343\)
\(\Rightarrow7^{x+1}=343\div7\)
\(\Rightarrow7^{x+1}=49\)
\(\Rightarrow7^{x+1}=7^2\)
\(\Rightarrow x+1=2\)
\(\Rightarrow x=2-1\)
\(\Rightarrow x=1\)
tim x
a ,343:(23-22+32.x)=7
b,21+2+2x+1-2x=160
giup minh voi cac ban
cac ban lam ra ho minh
cam on cac ban
a, \(343\text{ : }\left(2^3-2^2+3^2\cdot x\right)=7\)
\(343\text{ : }\left(8-4+9\cdot x\right)=7\)
\(343\text{ : }\left(4+9\cdot x\right)=7\)
\(4+9\cdot x=343\text{ : }7\)
\(4+9\cdot x=49\)
\(9\cdot x=49-4\)
\(9\cdot x=45\)
\(x=45\text{ : }9\)
\(x=5\)
b, \(2^{1+2}+2^{x+1}-2^x=160\)
\(2^3+2^x\left(2-1\right)=160\)
\(8+2^x\cdot1=160\)
\(2^x=160-8\)
\(2^x=152\)
\(2^x=2^9\)
\(\Rightarrow\text{ }x=9\)
\(a,\text{ }343\text{ : }\left(2^3-2^2+3^2\cdot x\right)=7\)
\(343\text{ : }\left(8-4+9\cdot x\right)=7\)
\(343\text{ : }\left(4+9\cdot x\right)=7\)
\(4+9\cdot x=343\text{ : }7\)
\(4+9\cdot x=49\)
\(9\cdot x=49-4\)
\(9\cdot x=45\)
\(x=45\text{ : }9\)
\(x=5\)