x+(x+1)+(x+2)+...+(x+100)=5353
x + ( x + 1 ) + ( x + 2 ) + ( x + 3 ) + ......... + ( x + 100 ) = 5353
\(x+\left(x+1\right)+\left(x+2\right)+\left(x+3\right)+....+\left(x+100\right)=5353\)
\(x+\left(x+x+x+...+x\right)+\left(1+2+3+...+100\right)=5353\)
\(101x+\frac{\left(1+100\right)\times100}{2}=5353\)
\(101x+5050=5353\)
\(101x=5353-5050\)
\(101x=303\)
\(\Rightarrow x=3\)
x + ( x + 1 ) + ( x + 2 ) + ( x + 3 ) + ......... + ( x + 100 ) = 535
101 x + ( 1 + 2 + ... + 100 ) = 535
101x + 5050 = 535
101x = -4515
\(\Rightarrow x=-\frac{4545}{101}\)
x + ( x + 1 ) + ( x + 2 ) + ( x + 3 ) + ......... + ( x + 100 ) = 5353
(x+x+x+x+...+x)+(1+2+3+...+100)=5353
101x + 5050 =5353
101x =5353 - 5050
101x =303
x =303 : 101
x = 3
Vậy ...
tìm x : x+(x+1)+(x+2)+...+x=5353
Đề bài có vấn đề nhé bạn! Chỗ cuối x+? thì mình mới làm được
Bài 1:So sánh mà không tính giá trị cụ thể:
a) M=35.53-18 và N=35+53.34
b) A=1995.1995 và B=1994.1996
Bài 2: Tìm x
x+(x+1)+(x+2)+...+(x+100)=5353
Giải cụ thể nha. Thanks
a.4674 x 3545
4563 x 5353
b.4521 x 3254
.4387 x 5684
c.4436 x 5235
5242 x 5436
d.3646 x 3452
3252 x 4255
a. 16 569 330
24 425 739
b. 14 711 334
24 935 708
c. 23 222 460
28 495 512
d. 12 585 992
13 837 260
a.4674 x 3545
4563 x 5353
b.4521 x 3254 = 14711334
.4387 x 5684 = 24958869
c.4436 x 5235 = 23222460
5242 x 5436 = 28495512
d.3646 x 3452 = 12585992
3252 x 4255 = 13837260
Học tốt
a 4674x3545=16569330
4563x5353=244258739
b 4521x3254=14711334
4387x5684=24935708
c 4436x5235=23666060
5242x5436=28495512
d 3646x 3452=12585992
3252x4255=13837260
~hok tốt ~
|x-1|+|x-2|+...|x-100|=2500
+ xét trường hợp x\geq 0
\Rightarrow |x-1|+|x-2|+...|x-100|=2500
hay x-1+x-2+.................+x-100=2500
\Rightarrow 100x-5050=2500
\Rightarrow x=755
+ xét trường hợp x<0
\Rightarrow |x-1|+|x-2|+...|x-100|=2500
hay 1-x+2-x+.............+100-x=2500
\Rightarrow 5050-100x=2500
\Rightarrow x=255
\(\frac{3737\cdot53-5353\cdot37}{1^2+2^2+3^2+.....+100^2}\)
Tử số = 37.101.53 - 53.101.37 = 0
=> Phân số = 0
\(\frac{3737.53-5353.37}{1^2+2^2+...+100^2}\)
\(=\frac{37.101.53-53.101.37}{1^2+2^2+..+100^2}\)
\(=\frac{0}{1^2+2^2+...+100^2}\)
\(=0\)
\(\frac{3737\cdot53-5353\cdot37}{1^2+2^2+3^2+...+100^2}\)
\(< =>\frac{198061-198061}{1\cdot1+2\cdot2+3\cdot3+...+100\cdot100}\)
\(< =>\frac{0}{1\cdot\left(2-1\right)+2\cdot\left(3-1\right)+3\cdot\left(4-1\right)+...+100\cdot\left(101-1\right)}\)
\(< =>1\cdot2-1+2\cdot3-2+3\cdot4-3+...+100\cdot101-100\)
\(< =>\left(1\cdot2+2\cdot3+3\cdot4+...+100\cdot101\right)-\left(1+2+3+...+100\right)\)
\(< =>\frac{100\cdot101\cdot102}{3}-\frac{100\cdot101}{2}\)
\(< =>343400-5050\)
\(< =>338350\)
chuc ban hoc tot nhe >.<
tính: a)(-1)x(-1)^2x(-1)^3x(-1)^4x...x(-1)^9x(-1)^10
b)[1/100-1^2]x[1/100-(1/2)^2]x[1/100-(1/3)^2]x...x[1/100-(1/20)^2]
Bài 6 Tìm x
1) ( x+1 ) + ( x+2 ) + ( x+3 ) + ... + ( x+100 ) = 5750
2) ( 2x-1 ) + ( 4x-2 ) + ... + ( 200x - 100 ) = 5050
3) ( x+2 ) + ( x+4 ) + ( x+6 ) + ... + ( x + 100) = 2650
( 100-1 ) x X + ( 100-2 ) x X + X + 2 x X = ?????????????????????