1. \(x^6-2x^3+1=0\Leftrightarrow\left(x^3-1\right)^2=0\Leftrightarrow x=1\)

2. \(x^6+\dfrac{1}{4}x^3+\dfrac{1}{64}=0\Leftrightarrow\left(x^3\right)^2+2.x^3.\dfrac{1}{8}+\left(\dfrac{1}{8}\right)^2=0\Leftrightarrow\left(x+\dfrac{1}{8}\right)^2=0\Leftrightarrow x=-\dfrac{1}{2}\)4. \(x^3-10x^2+25x=0\Leftrightarrow x^3-5x^2-5x^2+25x=0\)

\(\Leftrightarrow x^2\left(x-5\right)-5x\left(x-5\right)=0\)

\(\Leftrightarrow x\left(x-5\right)^2=0\Leftrightarrow x=5\)

5. \(\dfrac{1}{4}x^3-3x^2+9x=0\)

\(\Leftrightarrow x\left(\dfrac{1}{4}x^2-3x+9\right)=0\)

\(\Leftrightarrow x\left[\left(\dfrac{1}{2}x\right)^2-2.\dfrac{1}{2}x.3+3^2\right]=0\)

\(\Leftrightarrow x\left(\dfrac{1}{2}x-3\right)^2=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x=6\end{matrix}\right.\)

6. \(x^5-16x=0\Leftrightarrow x\left(x^4-16\right)=0\Leftrightarrow x\left(x^2-4\right)\left(x^2+4\right)=0\)

\(\Leftrightarrow x\left(x-2\right)\left(x+2\right)\left(x^2+4\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x=2\\x=-2\\x^2=-4\left(l\right)\end{matrix}\right.\)

7. \(4x^2+4x-3=0\Leftrightarrow4x^2-2x^2-6x-3=0\)

\(\Leftrightarrow2x\left(2x-1\right)-3\left(2x-1\right)=0\)

\(\Leftrightarrow\left(2x-1\right)\left(2x+3\right)=0\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{1}{2}\\x=-\dfrac{3}{2}\end{matrix}\right.\)

8. \(4x^2+28x+48=0\Leftrightarrow4x^2+12x+14x+48=0\)

\(\Leftrightarrow4x\left(x+3\right)+12\left(x+4\right)=0\)

\(\Leftrightarrow\left(4x+12\right)\left(x+3\right)=0\Leftrightarrow\left[{}\begin{matrix}x=-3\\x=-4\end{matrix}\right.\)

9. \(9x^2-12x+3=0\Leftrightarrow9x^2-9x-3x+3=0\Leftrightarrow9x\left(x-1\right)-3\left(x-1\right)=0\Leftrightarrow\left(x-1\right)\left(9x-3\right)=0\Leftrightarrow\left[{}\begin{matrix}x=1\\x=\dfrac{1}{3}\end{matrix}\right.\)

|2 - x|² + 6x - 3 = 0

<=> (x - 2)² + 6x - 3 = 0

<=> x² - 4x + 4 + 6x - 3 = 0

<=> x² + 2x + 1 = 0

<=> (x + 1)² = 0

<=> x + 1 = 0

<=> x = -1

Bắt phải thể hiện -_-

nhiều thê

sbn gủi từng câu

một thôi thì

trả lời dễ hơn đó

thôi kệ mình lỡ rồi bạn giúp mình nhé

  Bài 1:

2^\(x\) = 4

2\(^x\) = 2²

 \(x=2\)

Vậy \(x=2\)

Bài 2:

2\(^x\) = 8

2\(^x\) = 2³

\(x=3\)

Vậy \(x=3\)

Bài 3

2\(^x\) = 16

2\(^x\) = 2⁴

  \(x=4\)

Vậy \(x=4\)

2^x = 64

⇒ 2^x = 2⁶

⇒ x = 6.

7^x = 7¹⁰ : 7⁵

⇒ 7^x = 7⁵

⇒ x = 5.

3^x = 3¹⁵ : 243

⇒ 3^x = 3¹⁵ : 3⁵

⇒ 3^x = 3¹⁰

⇒ x = 10.

\(2^x=64=2^6\Rightarrow x=6\\ ---\\ 7^x=7^{10}:7^5=7^5\Rightarrow x=5\\ ----\\ 3^x=3^{15}:243=3^{15}:3^5=3^{10}\Rightarrow x=10\)

2^x= 64 => x = 6

7^x= 7¹⁰: 7⁵ => x=10 - 5 =5

3^x==3¹⁵: 243 = 3¹⁵- 3⁵=> x = 15-5 =10

Thêm nữa câu a) Tính: M(x) + N(x)+ P(x)

B) Tính M(x) - N (x) - P(x)

ok rồi giúp mình với nha

a) \(\left(6x-5y\right)^2=36x^2-60xy+25y^2\)

b) \(\left(4x-1\right)^2=16x^2-8x+1\)

c) \(\left(x+2\right)^2=x^2+4x+4\)

d) \(x^2-64=\left(x-8\right)\left(x+8\right)\)

e) \(4x^2-64=\left(2x-8\right)\left(2x+8\right)\)

f) \(25x^2-4=\left(5x-2\right)\left(5x+2\right)\)

g) \(\left(x+1\right)^3=x^3+3x^2+3x+1\)

h) \(\left(x-3\right)^3=x^3-9x^2+27x-27\)

k) \(x^3+8=\left(x+2\right)\left(x^2-2x+4\right)\)

l) \(x^3-125=\left(x-5\right)\left(x^2+5x+25\right)\)

y) \(27y^3-1=\left(3y-1\right)\left(9y^2+3y+1\right)\)

^{ai Giúp mình với}

ko có đề bài hả bn

a) \(5.3^x=405\)

\(\Rightarrow3^x=405:5\)

\(\Rightarrow3^x=81=3^4\)

\(\Rightarrow x=4\)

b) \(\left(x-2\right)^5=243\)

\(\Rightarrow\left(x-2\right)^5=3^5\)

\(\Rightarrow x-2=3\)

\(\Rightarrow x=5\)

c) \(2^x+2^{x+4}=272\)

\(\Rightarrow2^x.\left(1+2^4\right)=272\)

\(\Rightarrow2^x.17=272\)

\(\Rightarrow2^x=272:17=16\)

\(\Rightarrow2^x=2^4\)

\(\Rightarrow x=4\)

d) Từ x + 1 đến x + 2 có số số hạng là: (30 - 1) : 1 + 1 = 30 (số)

\(\left(x+1\right)+\left(x+2\right)+...+\left(x+30\right)=795\)

\(\Rightarrow30x+\frac{\left(30+1\right).30}{2}=795\)

\(\Rightarrow30x+465=795\)

\(\Rightarrow30x=330\)

\(\Rightarrow x=330:30\)

\(\Rightarrow x=11\)

a) \(5.3^x=405\)

         \(3^x=\frac{405}{5}=81\)

          \(3^x=3^4\)

Vậy x = 4

b ) \(\left(x-2\right)^5=243\)

      \(\left(x-2\right)^5=3^5\)

\(\Rightarrow x-2=3\)

\(\Rightarrow x=3+2=5\)

     Vậy x = 5

a, 5.3 ^x =405

3^x=405:5

3^x=81

=> x=4

b, (x-2)⁵=243

(x-2)⁵=3⁵

vì 5=5

nên x -2=3

<=> x=3+2

=>x=5

c, 2x  +   2x+4  =  272 

2^x+2^x+2⁴=272

2^x(1+2⁴)=272

2^x.17=272

2^x=272:17

2^x=16

vì 16=2⁴

=>x=4

d, (x+1)+(x+2)+(x+3)+.....+(x+30)=795

(x+x+x+..+x)+(1+2+3+..+30)=795

30x+456=795

30x=795-456

30x=330

x=330:30

x=11

vậy x=11

hc tốt

may cai bai day ma cung khong biet oc cho

a) 89-(73-x)=20

=>73-x=89-20

=>73-x=69

=>x=73-69

=>x=4

Dài quá bn ơi, vs lại mấy cái này cx ko khó lắm đâu (nếu ko lm đc đăng mỗi lần một ít thui chứ dài quá mk đọc cn lười chứ đừng ns là làm)