\(\left(\frac{1}{25.26}+\frac{1}{26.27}+...+\frac{1}{29.30}\right)\cdot150+1,03\div\left[1,03\cdot\left(y-1\right)\right]\text{ }=22\)

\(\Rightarrow\left(\frac{1}{25}-\frac{1}{26}+\frac{1}{26}-\frac{1}{27}+...+\frac{1}{29}-\frac{1}{30}\right)\cdot150+1,03\div\left[1,03\cdot\left(y-1\right)\right]=22\)

\(\Rightarrow\left(\frac{1}{25}-\frac{1}{30}\right)\cdot150+1,03\div\left[1,03\cdot\left(y-1\right)\right]=22\)

\(\Rightarrow\frac{1}{150}\cdot150+1,03\div\left[1,03\left(y-1\right)\right]=22\)

\(\Rightarrow1+1,03\div\left[1,03\left(y-1\right)\right]=22\)

\(\Rightarrow1,03\left(y-1\right)=1,03\div\left(22-1\right)\)

\(\Rightarrow1,03y-1,03=1,03\div21\)

\(\Rightarrow1,03y=\frac{103}{2100}+1,03\)

\(\Rightarrow1,03y=\frac{1133}{1050}\)

\(\Rightarrow y=\frac{1133}{1050}\div\frac{103}{100}=\frac{1133}{1050}\cdot\frac{100}{103}=\frac{22}{21}\)

Vậy y = \(\frac{22}{21}\)

Dấu " . " là dấu nhân nhé 

\(\left(\frac{1}{25\times26}+\cdot\cdot\cdot+\frac{1}{29\times30}\right)\times150+1\frac{3}{100}:[1\frac{3}{100}\times(y-1)]=22\)

\(\Rightarrow\left(\frac{1}{25}-\frac{1}{26}+\cdot\cdot\cdot+\frac{1}{29}-\frac{1}{30}\right)\times150:\left(y+1\right)=22\)

\(\Rightarrow\left(\frac{1}{25}-\frac{1}{30}\right)\times150:\left(y+1\right)=22\)

\(\Rightarrow\frac{1}{150}\times150:\left(y+1\right)=22\)

\(\Rightarrow1:\left(y+1\right)=22\)

\(\Rightarrow y+1=\frac{1}{22}\)

\(\Rightarrow y=\frac{1}{22}-1=\frac{-21}{22}\)

[ 1/ 25 x 26 + 1/26x27+....+ 1/29x30] x 150 + 103; 1,03 x ( x -1 ) =22

[ 1/25x26 + 1/26x27 + 1/27x28 + 1/28x29 + 1/29x30] x 150 + 103;1,03 x (x-1)=22

[ 1/650 + 1/702 + 1/756 + 1/812 + 1/870] x 150 + 103 ; 1,03 x (x-1) =22

(1/24x25 + 1/25x26 + ... + 1/29x30) x 120 + y : 1/3 = -4

(1/24 - 1/25 + 1/25 - 1/26 + ... + 1/29 - 1/30) x 120 + y x 3 = -4

(1/24 - 1/30) x 120 + y x 3 = -4

1/120 x 120 + y x 3 = -4

=> 1 + y x 3 = -4

=> y x 3 = -4 - 1

=> y x 3 = -5

=> y = -5/3

Vậy x = -5/3

Ủng hộ mk nha ^_-

(1/24x25 + 1/25x26 + ... + 1/29x30) x 120 + y : 1/3 = -4

(1/24 - 1/25 + 1/25 - 1/26 + ... + 1/29 - 1/30) x 120 + y x 3 = -4

(1/24 - 1/30) x 120 + y x 3 = -4

1/120 x 120 + y x 3 = -4

=> 1 + y x 3 = -4

=> y x 3 = -4 - 1

=> y x 3 = -5

=> y = -5/3

Vậy x = -5/3

T_I_C_K mk nha

\(\frac{5}{3\times4}+\frac{5}{4\times5}+\frac{5}{5\times6}+...+\frac{5}{25\times26}+\frac{5}{26\times27}\)

\(=\frac{4-3}{3\times4}+\frac{5-4}{4\times5}+\frac{6-5}{5\times6}+...+\frac{26-25}{25\times26}+\frac{27-26}{26\times27}\)

\(=5\times\left(\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+....+\frac{1}{25}-\frac{1}{26}+\frac{1}{26}-\frac{1}{27}\right)\)

\(=5\times\left(\frac{1}{3}-\frac{1}{27}\right)\)

\(=5\times\frac{8}{27}=\frac{40}{27}\)

\(\frac{5}{3.4}+\frac{5}{4.5}+\frac{5}{5.6}+...+\frac{5}{25.26}+\frac{5}{26.27}\)

\(=5\left(\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+...+\frac{1}{25}-\frac{1}{26}+\frac{2}{26}-\frac{1}{27}\right)\)

\(=5\left(\frac{1}{3}-\frac{1}{27}\right)\)

\(=\frac{40}{27}\)

Thank you!

Đặt A = 1x2+2x3+3x4+...+25x26+26x27

3A = 1 x 2 x 3 - 1 x 2 x 3 + 2 x 3 x 4  -2 x 3 x 4 + ..... + 26 x 27 x 28

3A = 26 x 27 x 28

A= \(\text{ }\frac{\text{26 x 27 x 28}}{3}=6552\)

Cậu học cấp 2 rồi còn giải bài cấp 1 làm chi.

giải chi tiết giúp mình