x-3nhan x-2=0
\
2nhan(x-4)+4nhan(x-3)-x+1=3nhan(2x-3)-7
\(72-3nhan\left|x+1\right|=9\)
Ta có:
\(72-3\left|x+1\right|=9.\)
\(\Rightarrow\) \(3\left|x+1\right|=72-9.\)
\(3\left|x+1\right|=63.\)
\(\Rightarrow\left|x+1\right|=63:3.\)
\(\left|x+1\right|=21.\)
\(\Leftrightarrow\left[{}\begin{matrix}x+1=21\\x+1=-21\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=21-1=20\in Z.\\x=-21-1=-22\in Z.\end{matrix}\right.\)
Vậy: \(\left[{}\begin{matrix}x=21.\\x=-22.\end{matrix}\right.\)
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72-3.\(|x+1|\)=9
=>\(|x+1|\)=72-9
=>\(|x+1|\)=63
=>x+1=63 hoặc x+1=-63
=>x=63-1 hoặc x=-63 -1
=>x=62 hoặc x=-64
Vậy x\(\in\left\{62,-64\right\}\)
\(72-3\left|x+1\right|=9\)
\(3\left|x+1\right|=72-9\)
\(3\left|x+1\right|=63\)
\(\left|x+1\right|=\dfrac{63}{3}\)
\(\left|x+1\right|=21\)
\(\circledast\)TH1: \(x+1=21\\ x=21-1\\ x=20\)
\(\circledast\)TH2: \(x+1=-21\\ x=-21-1\\ x=-22\)
Vậy \(x\in\left\{20;-22\right\}\)
cho A =3nhan 3nhan 3...3nhan 3 nhan 3(co 2012 chu so 3)
tim tap xac dinh cua ham so
y=3nhan x binh phuong -x tren cho( gia tri tuyet doi cua x binh phuog -x) +(giá tri tuyet doi cua x-1)
y=(can x+2)+(can 3-2x) tren cho (gia tri tuyet doi cua x) -1
Tìm số nguyên X biết
a |18-2nhan | -X + 5 || = 12
b 12-2nhan (-X+3)2= -38
c -20+3nhan(2X+1)3= -101
tìm abc biết 1/3nhan a=3nhan c
1va1\3nhan 1va1\3nhan 1va14 nhan1va1\5 1va1\5 nhan1va1\6nhan1va1\7nhan1va1\8
minh khong hieu ban giai thich cho minh di
1/2 chia 3nhan 1/4
Bai toan 1
x+1+x+1+x+1+x+1+x+1+x+1+3nhan x+3=189585.
Bai toan 2
Tim 5 phan so lon hon phan so 4/5 va be hon phan so 5/6.
Bai toan 3
Moi chuyen xe khach cho duoc 40 nguoi (ke ca nguoi lai xe).Hoi co 400 khach thi phai can it nhat bao nhieu xe de cho het so khach do?
Bai toan 4
x+1+x+1+x+1+x+1+x+1+x+1+3 nhan x+3=189585
Bài 1 và 4:21064
Bài 2:41/5; 42/5; 43/5; 44/5; 45/5
Bài 3:10 xe