1/15

giup minh voi, di ma

\(\dfrac{1}{2}\times\left(\dfrac{1}{3}-\dfrac{1}{5}\right)=\dfrac{1}{2}\times\left(\dfrac{5}{15}-\dfrac{3}{15}\right)=\dfrac{1}{2}\times\dfrac{2}{15}=\dfrac{1}{15}\)

\(2x-\left(x-3\right)=\frac{1}{2}\)

\(\Leftrightarrow2x-x+3=\frac{1}{2}\)

\(\Leftrightarrow2x-x=\frac{1}{2}-3\)

\(\Leftrightarrow x\left(2-1\right)=\frac{1}{2}-\frac{6}{2}\)

\(\Leftrightarrow x=\frac{-5}{2}\)

\(2x-\left(x-3\right)=\frac{1}{2}\)

\(\Leftrightarrow2x-x+3=\frac{1}{2}\)

\(\Leftrightarrow x=\frac{1}{2}-3\)

\(\Leftrightarrow x=\frac{1}{2}-\frac{6}{2}=-\frac{5}{2}\)

2x- x + 3 = 1/2

x = 1/2 - 3 

x=- 5 /2

sr cac ban nha ket qua cu day tinh do la 3021

\(a=0\)

Nếu sai thì mk làm lại

(x+1)²-(x+1)=0

<=> (x+1)² hoặc x+1=0

(x+1)²=0 => x=-1

x+1=0 => x=-1

Vậy x=-1

b) 5x²-13x=0

x(5x-13)=0

<=> x=0 hoặc 5x-13=0

5x-13=0 => 5x=13 => x=13/5

Vậy x=13/5

c) x²-7x³=0

<=> x(x-7x²)=0

=> x=0 hoặc

\(3-\frac{x}{5}-x=\frac{x}{x-1}\)

\(\Rightarrow\frac{15\left(x-1\right)}{5\left(x-1\right)}-\frac{x\left(x-1\right)}{5\left(x-1\right)}-\frac{5x\left(x-1\right)}{5\left(x-1\right)}=\frac{5x}{5\left(x-1\right)}\)

\(\Rightarrow15\left(x+1\right)-x\left(x-1\right)-5x\left(x-1\right)=5x\)

\(\Rightarrow15x+15-x^2+x-5x^2+5x=5x\)

Bạn tự làm tiếp theo ha

\(\frac{3-x}{5-x}=\frac{x}{x+1}\)

\(\left(3-x\right)\left(x+1\right)=\left(5-x\right)x\)

\(3\left(x+1\right)-x\left(x+1\right)=5x-x^2\)

\(3x+3-x^2-x=5x-x^2\)

\(2x+3-x^2=5x-x^2\)

\(2x+3=5x\)

\(3=5x-2x\)

\(3x=3\)

\(x=1\)

Vậy x = 1

......................?

mik ko biết

mong bn thông cảm 

nha ................