S= 3 + 3/2 + 3/2^2 + 3/2^3 + ... + 3/2^9
Tính S:
S = 3 + 3/2 + 3/2^2 + 3/2^3 + ... + 3/2^9
tinh tong S= 3/2 +3/2^2 +3/2^3+......+3/2^9
\(2S=3+\frac{3}{2}+\frac{3}{2^2}+...+\frac{3}{2^8}\)
\(S=2S-S=3-\frac{3}{2^9}\)
Có S= 3/2 + 3/22 + 3/23 + ...+ 3/29 =>S*1/3 = 1/2 + 1/22 + 1/23 +...+ 1/29 =>S*1/3*2 = 1 + 1/2 + 1/22 +...+ 1/28 = S*2/3 => 2/3S - 1/3S = 1 + 1/2 + 1/22 +...+ 1/28 -(1/2 + 1/22 +...+ 1/29) => 1/3S = 1 + 1/2 + 1/22 +...+ 1/28 - 1/2 - 1/22 -...- 1/29 =>1/3S = 1 - 1/29 => S = 3 - 3/29
S=3+3/2+3/2^2+...+3/2^9
\(S=3+\frac{3}{2}+\frac{3}{2^2}+....+\frac{3}{2^9}\)
\(2S=6+3+\frac{3}{2}+....+\frac{3}{2^8}\)
=>\(2S-S=\left(6+3+\frac{3}{2}+...+\frac{3}{2^8}\right)-\left(3+\frac{3}{2}+\frac{3}{2^2}+....+\frac{3}{2^9}\right)\)
=>\(S=6-\frac{3}{2^9}=\frac{3069}{512}\)
tính tổng:
S=3+3/2+3/2^2+3/2^3+.....+3/2^9
Tinh gia tri cua S:
S=3+3/2+3/2^2+.....+3/2^9
Tính tổng S=3+3/2+3/2^2+3/2^3+...3/2^9
Ta có: S = 3+3/2+3/2^2+3/2^3+...+3/2^9
1/2.S = 3/2+3/2^2+3/2^3+3/2^4+...+3/2^10
\(\Rightarrow\) S-1/2.S = 3 - 3/2^10
\(\Rightarrow\) 1/2.S = 3 - 3/2^10
\(\Rightarrow\) S = (3 - 3/2^10) : 1/2
\(\Rightarrow\) S = 6 - 6/2^10
Nếu đúng thì cho mk biết nha
ban duc nguyen ngoc lam dung day
tính S=3+3/2+3/2^2+...+3/2^9
Ta có:
S=3+3/2+3/2^2+3/2^3+...+3/2^9
2S=6+3+3/2+3/2^2+...+3/2^8
2S-S=(6+3+3/2+3/2^2+...+3/2^8)-(3+3/2+3/2^2+...+3/2^9)
S=6-2/512
S=3069/512
S=
S=3+3/2+3/22+3/23+3/24+.............+3/28+3/29
Tính S giúp mik nhé!
\(\Rightarrow2S=6+3+\frac{3}{2}+...+\frac{3}{2^8}\)
\(\Rightarrow2S-S=\left(6+3+\frac{3}{2}+...+\frac{3}{2^8}\right)-\left(3+\frac{3}{2}+...+\frac{3}{2^9}\right)\)
\(\Rightarrow S=6-\frac{3}{2^9}\)
Tính tổng S :
S=3/2+3/2^2+...+3/2^9
ta có :
2.S=\(\frac{3}{2^2}+\frac{3}{2^3}+...+\frac{3}{2^{10}}\)
2.S-S=\(\left(\frac{3}{2^2}+\frac{3}{2^3}+...+\frac{3}{2^{10}}\right)-\left(\frac{3}{2}+\frac{3}{2^2}+...+\frac{3}{2^9}\right)\)
=>S=\(\frac{3}{2^{10}}-\frac{3}{2}\)