a) \(\frac{X}{2}-\frac{11}{5}=\frac{7}{8}\cdot\frac{64}{49}\)

\(\Rightarrow\frac{x}{2}-\frac{11}{5}=\frac{8}{7}\)

\(\Rightarrow\frac{x}{2}=\frac{8}{7}+\frac{11}{5}\)

\(\Rightarrow\frac{x}{2}=\frac{117}{35}\)\(\Rightarrow x=\frac{117}{35}\cdot2=\frac{234}{35}\)

b)\(\frac{x}{5}+\frac{9}{2}=\frac{6}{7}\cdot\frac{36}{49}\)

\(\Rightarrow\frac{x}{5}+\frac{9}{2}=\frac{216}{343}\)

\(\Rightarrow\frac{x}{5}=\frac{216}{343}-\frac{9}{2}=\frac{-2655}{686}\)

\(\Rightarrow x=\frac{-2655}{686}\cdot5=\frac{-13275}{686}\)

        x/2 - 11/5 = 7/8 . 64/49

        x/2 - 11/5 = 8/7

        x/2          =8/7 + 11/5

        x/2          = 117/35

        x             = 2.117/35 ( tính chất phân số bằng nhau)

        x             = 234/35 

       x/5 + 9/2 = 6/7 . 36/49

       x/5 + 9/2 = 216/343

        x/5         = 216/343 - 9/2

        x/5         = -2655/686

        x           = 5.(-2655)/686

        x           = -13275/686 

tui trả lời trước mà ko tk

1)

a) 21/23 x 5/11 x 4/35

= \(\frac{21.5.4}{23.11.35}\)

= \(\frac{7.3.5.4}{23.11.5.7}\)

= \(\frac{3.4}{23.11}\)    ( ta đã rút gọc 7 và 5 )

= \(\frac{12}{253}\)

b) 26 x 13/42 : 13

= \(\frac{26.13}{42.13}\)

= \(\frac{13.2.13}{21.2.13}\)

= \(\frac{13}{21}\)

c) 5/9 : 2/9 + 4/9 : 2/3

= \(\frac{5.9}{9.2}+\frac{4.3}{9.2}\)

= \(\frac{5}{2}+\frac{2.2.3}{3.3.2}\)

= \(\frac{5}{2}+\frac{2}{3}\)

= \(\frac{19}{6}\)

2 ) tìm x

a ) 2 - x = 1/3 + 1/6

      2 - x = 1/2

      x = 2 - 1/2 

    x = 3/2

b ) x + 5/8 = 1 + 3/4

     x + 5/8 = 7/4 

      x = 7/4 - 5/8 

       x = 9/8

3) 

a)  x < 3/4 + 4/5

=> x < 31/20 

=> x = 1

b) 1/2 + 3/5 < x < 5/4

  => 11/10   < x < 5/4

ta quy đồng phân số 11/10 và 5/4

\(\frac{11}{10}=\frac{11.4}{10.4}=\frac{44}{40}\)

\(\frac{5}{4}=\frac{5.10}{4.10}=\frac{50}{40}\)

=> 44/40 < x <  50/40

=> x không thỏa mãn 

plp]l]

A=1/1.2+1/2.3+...1/x =49/50

A=1-1/2+1/2-1/3+...+1/x-1-1/x=49/50

A=1-1/x=49/50

A=50/50-1=x=49/50

x=1/50

\(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+...+\frac{1}{x}=\frac{49}{50}\)

\(\Rightarrow\frac{1}{1\cdot2}+\frac{1}{2\cdot3}+\frac{1}{3\cdot4}+...+\frac{1}{x\left(x-1\right)}=\frac{49}{50}\)

\(\Rightarrow1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{x-1}-\frac{1}{x}=\frac{49}{50}\)

\(\Rightarrow1-\frac{1}{x}=\frac{49}{50}\)

\(\Rightarrow\frac{1}{x}=\frac{1}{50}\)

\(\Rightarrow x=50\)

\(A=\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+...+\frac{1}{x}\)

\(A=\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{\left(n-1\right)n}\) với \(\left(n-1\right)n=x\)

\(A=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{n-1}-\frac{1}{n}\)

\(A=1-\frac{1}{n}\)

Mà \(A=\frac{49}{50}\)

\(\Rightarrow1-\frac{1}{n}=\frac{49}{50}\)

              \(\frac{1}{n}=1-\frac{49}{50}\)

              \(\frac{1}{n}=\frac{1}{50}\)

\(\Rightarrow n=50\)

Có \(x=\left(n-1\right)n\)

\(\Rightarrow x=\left(50-1\right)50\)

    \(x=49.50\)

    \(x=2450\)

\(\left(\frac{2}{3}+\frac{1}{3}:\frac{3}{4}+\frac{5}{9}\right).y-3=25\%+\frac{7}{4}\)

\(\Rightarrow\left(\frac{2}{3}+\frac{4}{9}+\frac{5}{9}\right).y-3=\frac{1}{4}+\frac{7}{4}\)

\(\Rightarrow\left(\frac{2}{3}+1\right).y-3=2\)

\(\Rightarrow\frac{5}{3}.y-3=2\)

\(\Rightarrow y-3=2:\frac{5}{3}\)

\(\Rightarrow y-3=\frac{6}{5}\)

\(\Rightarrow y=\frac{6}{5}+3\)

\(\Rightarrow y=\frac{21}{5}\)

x/120=-7/24*-6/11

x/120=7/44

x=7*120:44

x=210/11

\(\frac{a}{b}+\frac{1}{6}=\frac{5}{3}\)

=> \(\frac{a}{b}=\frac{5}{3}-\frac{1}{6}=\frac{3}{2}\)

\(\frac{a}{b}-\frac{1}{3}=\frac{3}{4}\)

=> \(\frac{a}{b}=\frac{3}{4}+\frac{1}{3}=\frac{13}{12}\)

Ta có:

\(\frac{x}{3}=\frac{y}{5}=\frac{x+y}{3+5}=\frac{16}{8}=2\)

=> \(x=2.3=6\)

=> \(y=2.5=10\)

X là

16:(3+5)x3=6

Y là

16-6=10

k nhé

Ta có:

x/3 =y/5 =x+y/3+5 =16/8 =2

=> x=2.3=6

=> y=2.5=10

vậy x=6

       y=10