Cho tam giac ABC can tai A hai duong trung tuyen BD va CE cat nhau tai G (trong doD thuocAC va E thuocAB). Cau a chung minh BE=DC va tam giac BEC= tam GIÁC CDB
Cau b chung minh tam giac BGC can
Cau c chung minh BC<4GD
cho tam giac ABC can tai A duong trung truc cua AB;AC cat nhau tai O va cat B;C lan luot tai E chung minh rang
a;OA la duong trung truc cua BC
b;BD=CE
c; tam giac ODE la tam giac can
cho tam giac abc, trung tuyen am. gio g la trong tam cua tam giac abc. qua g ke cac duong thang song song voi ab va ac, cat bc theo thu tu tai d va e. a, tinh va so sanh cac ti so bd/bm va ce/cm tu do suy ra bd=ce. b, chung minh bd=de=ce
cho tam giac abc, trung tuyen am. gio g la trong tam cua tam giac abc. qua g ke cac duong thang song song voi ab va ac, cat bc theo thu tu tai d va e. a, tinh va so sanh cac ti so bd/bm va ce/cm tu do suy ra bd=ce. b, chung minh bd=de=ce
Cho tam giac ABC can tai A co AD la duong trung tuyen
a)Chung minh tam giac ABD= tam gaic ACD va AD vuong goc voi BC
b)Cho AB=10cm,BC=16cm. Tinh do dai AD va so sanh cac goc cua tam giac ABC.
c) Ve duong trung tuyen CF cua tam giac ABC cat AD tai M. Tinh do dai AM.
d) Ve DH vuong goc AC tai H, tren canh AC va canh DC lan luot lay hai diem E,K sao cho AE=AD va DK=DH. Chung minh: EK vuong goc voi BC
A,
xét \(\Delta ABD\)và \(\Delta ACD\)
CÓ \(\hept{\begin{cases}AB=AC\\chungAD\\BD=DC\end{cases}}\)
SUY RA \(\Delta ABD\)=\(\Delta ACD\) (C.C.C) (1)
=> \(\widehat{BDA}\)=\(\widehat{CDA}\)
MÀ \(\widehat{BDA}\)+\(\widehat{CDA}\)=180
=> \(\widehat{BDA}\)=\(\widehat{CDA}\)=90
B, (1) => BC=DC=1/2 BC=8
ÁP DỤNG ĐỊNH LÍ PITAGO TA CÓ
\(AB^2=AD^2+BD^2\)
=> AD^2=36
=>AD=6
cho tam giac ABC can tai A. BD va CE la 2 duong phan giac cua tam giac ABC, chung cat nhau tai K.
Chung minh rang: AK di qua trung diem cua BC
1.cho tam giac ABC can tai dinh A, trung truc cua canh AC cat CB tai diem D (D nam ngoai doan BC). tren tia doi cua tia AD lay diem E sao cho AE= BD. chung minh tam giac DEC can.( goi y can chung minh CD = CE)
2. cho tam giac ABC co AB < AC, lay diem E tren canh CA sao cho CE=BA, cac duong trung truc cua cac doan thang BE va CA cat nhau tai I
a)chung minh tam giac AIB = tam giac CIE
b)chung minh AI la tia phan giac cua goc BAC
Cho tam giac ABC .Ke trung tuyen AM Tren tia doi cua tia MA lay diem E sao cho ME=MA
a,Chung minh tam giac AMB=tam giac ECM
b,Ke AH vuong goc voi BC. Ten tia doi cua tia HA lay diem D sao cho HD=HA.Chung minh :BCla tia phan giac cua goc ABD va BD=CE
c.Hai duong thang BD va CE cat nhau tai K. Chung minh :tam giac BCK can
Cho tam giac ABC can tai A .BM va CN la 2 duong trung tuyen BM cat CN tai K
a,Chung minh tm giac BNC =tam giac CMB
b,Chung minh tam giac BKC can tai K
c, Chung minh BC//MN
Ta có: Tam giác ABC cân tại A => AB = AC
=>AB/2 = AC/2
=> NB=MC
Xét tam giác BNC và tam giác CMB có
NB = MC ( cmt)
góc B = góc C
BC cạnh chung
=> tam giác BNC = tam giác CMB ( cạnh - góc - cạnh )
Mệt quá câu A thôi nha !
Cho tam giac ABC vuong tai A co duong phan giac BD,ke H vuong goc voi BC
a)chung minh :tam giac ABD=tam giac HAD
b)chung minh tam giac ABH can
c)so sanh AD va DC
d)tia HD cat tia BA tai K chung minh DC=DO
e)chung minh tam giac BKC can