Bài 2 : Tính
\(D=\left(\frac{6}{8}+1\right).\left(\frac{6}{30}+1\right)....\left(\frac{6}{10700}+1\right)\)
HÃY CỐ GẮNG GIÚP MÌNH NHA CÁC P
Tính :
\(C=\left(\frac{6}{8}+1\right).\left(\frac{6}{18}+1\right).\left(\frac{6}{30}+1\right).....\left(\frac{6}{10700}+1\right)\)
Giúp mình với mình cần gấp
Bài 1 : Tính
\(A=\left(\frac{1}{3}-1\right).\left(\frac{1}{6}-1\right).\left(\frac{1}{10}-1\right).\left(\frac{1}{15}-1\right).\left(\frac{1}{21}-1\right).\left(\frac{1}{28}-1\right).\left(\frac{1}{36}-1\right)\)
HÃY CỐ GẮNG GIÚP MÌNH NHA CÁC P !!!
A = ( 1/3 - 1).( 1/6 - 1).( 1/10 - 1).( 1/15 - 1).( 1/21 - 1).( 1/28 - 1).( 1/36 - 1)
A = -2/3 . ( -5/6) . ( -9/10) . ( -14/15) . ( -20/21) . ( -27/28) . ( -35/36)
Do tích A có lẻ thừa số, mỗi thừa số đều mang dấu âm nên A mang dấu âm
A = -[ 2/3 . 5/6 . 9/10 . 14/15 . 20/21 . 27/28 . 35/36]
Đặt B = 2/3 . 5/6 . 9/10 . 14/15 . 20/21 . 27/28 . 35/36
B = 4/6 . 10/12 . 18/20 . 28/30 . 40/42 . 54/56 . 70/72
B = 1.4/2.3 . 2.5/3.4 . 3.6/4.5 . 4.7/5.6 . 5.8/6.7 . 6.9/7.8 . 7.10/8.9
B = 1.2.3.4.5.6.7/3.4.5.6.7.8.9 . 4.5.6.7.8.9.10/2.3.4.5.6.7.8
B = 2/8.9 . 9.10/2.3
B = 5/12
A = -5/12
cÓ ĐÚNG KO VẬY P NẾU ĐÚNG THÌ CHO MIK THANK Y NHA
Tính :
\(A=\left(\frac{6}{8}+1\right)\left(\frac{6}{18}+1\right)\left(\frac{6}{30}+1\right)...\left(\frac{6}{10700}+1\right)\)
Giúp cái !!!
Tính nhanh:
F=\(\left(\frac{6}{8}+1\right)\left(\frac{6}{18}+1\right)\left(\frac{6}{30}+1\right).....\left(\frac{6}{10700}+1\right)\)
F=(6/8+1)(6/18+1)(6/30+1)...(6/10700+1)
14.24.36...10706
F= ---------------------------
8.18.30....10700
7.2.8.3.9.4...106.101
F= -----------------------------------
8.1.9.2.10.3...107.100
(7.8.9....106)(2.3.4...101)
F= ----------------------------------------
(8.9.10...107)(2.3.4...100)
7.101
F= ----------
107
F=1
Mình nhầm nhé! Bạn để nguyên:
F =707/101 là được rồi
K mình nhé!
Tính: A=\(\left(\frac{6}{8}+1\right)\cdot\left(\frac{6}{18}+1\right)\cdot\left(\frac{6}{30}+1\right)\cdot...\cdot\left(\frac{6}{10700}+1\right)\)
Tính giá trị biểu thức sau :
\(B=\left(\frac{6}{8}+1\right)\left(\frac{6}{18}+1\right)\left(\frac{6}{30}+1\right)...\left(\frac{6}{10700}+1\right)\)
\(\left(\frac{6}{8}+1\right)\)\(+\left(\frac{6}{18}+1\right)+\left(\frac{6}{30}+1\right)+...+\left(\frac{6}{10700}+1\right)\)
Tính B = \(\left(\frac{6}{8}+1\right)\)x \(\left(\frac{6}{18}+1\right)\)x \(\left(\frac{6}{30}+1\right)\)x ... x \(\left(\frac{6}{10700}+1\right)\)
TÍNH:
a. \(\frac{\left(\frac{1}{9}\right)^6.\left(\frac{3}{8}\right)^7}{\left(\frac{1}{3}\right)^{13}.\left(\frac{1}{2}\right)^{22}.3^6}\)
b. \(\frac{5^{-6}.\left(\frac{1}{2}\right)^{13}}{\left(\frac{1}{5}\right)^7.\left(\frac{1}{8}\right)^4}\)
Giúp mik vs các bạn nha!!!
a, \(\frac{\left(\frac{1}{9}\right)^6\cdot\left(\frac{3}{8}\right)^7}{\left(\frac{1}{3}\right)^{13}\cdot\left(\frac{1}{2}\right)^{22}.3^6}\)
\(=\frac{\left(\frac{1}{\left(3^2\right)^6}\right)\cdot\left(\frac{1}{2}\cdot\frac{1}{2}\cdot\frac{1}{2}\cdot3\right)^7}{\left(\frac{1}{3}\right)^{13}.\left(\frac{1}{2}\right)^{22}.3^6}=\frac{\frac{1}{3^{12}}\cdot\left(\frac{1}{2}\right)^{21}\cdot3^7}{\frac{1}{3^{13}}\cdot\left(\frac{1}{2}\right)^{22}.3^6}\)
\(=\frac{3}{\frac{1}{3}\cdot\frac{1}{2}}=3\div\frac{1}{6}=3.6=18\)
b, Làm tương tự nha bn