1+2+4+8+.........+256+512=1023

k mk nha

làm bạn nha

Tự nghĩ nha con

Nhớ tk đó

^_^

đáp số là 1023 nha bạn

Đặt \(A=\dfrac{1}{2}+\dfrac{1}{4}+\dfrac{1}{8}+...+\dfrac{1}{256}+\dfrac{1}{512}\)

\(\Rightarrow2A=1+\dfrac{1}{2}+\dfrac{1}{4}+...+\dfrac{1}{128}+\dfrac{1}{256}\)

\(\Rightarrow A=2A-A=1+\dfrac{1}{2}+\dfrac{1}{4}+...+\dfrac{1}{128}+\dfrac{1}{256}-\dfrac{1}{2}-\dfrac{1}{4}-\dfrac{1}{8}-...-\dfrac{1}{256}-\dfrac{1}{512}\)

\(\Rightarrow A=1-\dfrac{1}{512}=\dfrac{511}{512}\)

Đặt ⇒2A=1+12+14+...+1128+1256⇒2A=1+12+14+...+1128+1256

⇒A=1−1512=511512

1/2 + 1/4 + 1/8 + 1/16 + ... + 1/256 + 1/512

= 256/512 + 128/512 + 64/512 + ... + 2/512 + 1/512

= 256 + 128 + 64 + .. + 2 + 1 / 512

= ???????

s=1/2+1/4+1/8+1/16+.....+1/256+1/512

sx2=(1/2+1/4+1/8+1/16+....+1/256+1/512)x2

sx2=1+1/2+1/4+1/8+......+1/126+1/256

sx2-s=(1+1/2+1/4+1/8+......+1/256)-(1/2+1/4+1/8+1/16++.....+1/256+1/512)

1+1/2+1/4+1/8+......+1/256-1/2-1/4-1/8-1/16-.....1/256-1/512

=1-1/512=511/512

có ai bik B=1/4+1/8+1/16+1/...+1/256 ko (nếu bik thì giải tử tế nhé mik cảm ơn)

 Ta có: A =1/2+1/4+1/8+1/16+....+1/256+1/512 

=> 2A = 1 + 1/2 + 1/4 + 1/8 + ...+ 1/128 + 1/256

=> 2A - A = (1 + 1/2 + 1/4 + 1/8 + ...+ 1/128 + 1/256 -(1/2+1/4+1/8+1/16+....+1/256+1/512 )

         A =  1 - 1/512 = 511/512

*Tham khảo 

bằng 0,9990234375

1023/1024

a) đề sai

1/4 + 1/8 + 1/16 + 1/32 + 1/64 + 1/128 + 1/256 + 1/512

A x 2 = 1/4 ( 1/4 + 1/8 + 1/16 + .......... + 1/512 ) - 1/512

A x 2 = 1/4 - A - 1/512

A x 2 - A = 1/4 - 1/512

A = 1/4 - 1/512

A = 127/512

1/4 + 1/8 + 1/16 + 1/32 + 1/64 + 1/128 + 1/256 + 1/512

= 1/2 - 1/4 + 1/4 - 1/8 + ... + 1/256 - 1/512

= 1/2 - 1/512

= 255/512

1/4 + 1/8 + 1/16 + 1/32 + 1/64 + 1/128 + 1/256 + 1/512

= 1/2 - 1/4 + 1/4 - 1/8 + ... + 1/256 - 1/512

= 1/2 - 1/512

= 255/512

 A = 1/2 + 1/4 + 1/8 + ... + 1/1024

2A = 1 + 1/2 + 1/4 + ... + 1/512

2A - A = (1 + 1/2 + 1/4 + ... + 1/512) - (1/2 + 1/4 + 1/8 + ... + 1/1024)

A = 1 - 1/1024

A = 1023/1024

\(A=\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+....+\frac{1}{1024}\)

\(\Rightarrow2A=1+\frac{1}{2}+\frac{1}{4}+......+\frac{1}{512}\)

\(\Rightarrow A=2A-A=1-\frac{1}{1024}\)

\(A=\frac{1023}{1024}\)

A=\(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+...+\frac{1}{512}+\frac{1}{1024}\)

2 x A=\(1+\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+...+\frac{1}{512}\)

2 x A - A = \(\left(1+\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+...+\frac{1}{512}\right)-\left(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+...+\frac{1}{512}+\frac{1}{1024}\right)\)

A=\(1-\frac{1}{1024}\)

A=\(\frac{1023}{1024}\)