a:2/11-2/15+2/15-2/19+2/19-2/23.....+2/51-2/55

a : 2/11-2/55

a:8/55

Đúng thì k hộ mik nha

a=2/4(4/11x15+4/15x19+4/19x23+..........+4/51x55

a=2/4(1/11-1/15+1/15-1/19+1/19-1/23+........+1/51-1/55)

a=2/4(1/11-1/55)

a=2/4x4/55

a=2/55

\(A=\frac{2}{11.15}+\frac{2}{15.19}+...+\frac{2}{51.55}\)

\(A=\frac{1}{2}.\left(\frac{4}{11.15}+\frac{4}{15.19}+...+\frac{4}{51.55}\right)\)

\(A=\frac{1}{2}.\left(\frac{1}{11}-\frac{1}{15}+\frac{1}{15}-\frac{1}{19}+...+\frac{1}{51}-\frac{1}{55}\right)\)

\(A=\frac{1}{2}.\left(\frac{1}{11}-\frac{1}{55}\right)\)

\(A=\frac{1}{2}.\frac{4}{55}\)

\(A=\frac{2}{55}\)

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chiu thoi

\(\left(\frac{2}{11\times13}+\frac{2}{13\times15}+\frac{2}{15\times17}+\frac{2}{17\times19}+\frac{2}{19\times21}\right)\times462-x=19\)

\(\left(\frac{1}{11}-\frac{1}{13}+\frac{1}{13}-\frac{1}{15}+...+\frac{1}{19}-\frac{1}{21}\right)\times462-x=19\)

\(\left(\frac{1}{11}-\frac{1}{21}\right)\times462-x=19\)

\(\frac{10}{231}\times462-x=19\)

\(20-x=19\)

\(\Rightarrow x=20-19=1\)

chịu thôi làm sao được chết mất

nhiều thế

sfdhg 

Ta có $\sqrt{x^2-7x+19}-\sqrt{x^2-7x+15}=2$

$=>2M=(\sqrt{x^2-7x+19}-\sqrt{x^2-7x+15})(\sqrt{x^2-7x+19}+\sqrt{x^2-7x+15})$

$=>2M=\sqrt{x^2-7x+19}^2-\sqrt{x^2-7x+15}^2$

$=>2M=(x^2-7x+19)-(x^2-7x+15)=4$

$=>M=2$

\(2.M=\left(x^2-7x+19\right)-\left(x^2-7x+15\right)=4\Rightarrow M=2\)

Đặt \(\sqrt{x^2-7x+19}-\sqrt{x^2-7x+15}=B\)  = B

   Xét tích \(AB=\left(\sqrt{x^2-7x+19}-\sqrt{x^2-7x+15}\right)\left(\sqrt{x^2-7x+19}+\sqrt{x^2-7x+15}\right)\)

                   \(=x^2-7x+19-\left(x^2-7x+15\right)=x^2-7x+19-x^2+7x-15\)

                     \(=4\)

     Mà \(B=2\Leftrightarrow A=2\)

`(2/(11.13)+2/(13.15)+....+2/(19.21)).462-[0,04/(x+1,05):0,12=19`

`=>(1/11-1/13+1/13-1/15+....+1/19-1/21).462-(2/(50(x+1,05)).25/3=19`

`=>(1/11-1/21).462-1/(3(x+1,05))=19`

`=>10/231. 462-1/(3x+3,15)=19`

`=>20-1/(3x+3,15)=19

`=>1/(3x+3,15)=1`

`=>3x+3,15=1`

`=>3x=-2,15`

`=>x=-43/60`

Vậy `x=-43/60`

Giải: 

\(\left(\dfrac{2}{11.13}+\dfrac{2}{13.15}+...+\dfrac{2}{19.21}\right).462-\left[\dfrac{0,04}{x+1,05}:0,12\right]=19\) 

\(\left(\dfrac{1}{11}-\dfrac{1}{13}+\dfrac{1}{13}-\dfrac{1}{15}+...+\dfrac{1}{19}-\dfrac{1}{21}\right).462-\left[\dfrac{1}{\dfrac{25}{x+\dfrac{21}{20}}}:\dfrac{3}{25}\right]=19\) 

\(\left(\dfrac{1}{11}-\dfrac{1}{21}\right).462-\left[\dfrac{1}{25.\left(x+\dfrac{21}{20}\right)}:\dfrac{3}{25}\right]=19\) 

                             \(20-\left[\dfrac{25.1}{3.25.\left(x+\dfrac{21}{20}\right)}\right]=19\) 

                                              \(\dfrac{1}{3.\left(x+\dfrac{21}{20}\right)}=20-19\) 

                                               \(\dfrac{1}{3.x+\dfrac{63}{20}}=1\) 

                                      \(1:\left(3.x+\dfrac{63}{20}\right)=1\) 

                                                \(3.x+\dfrac{63}{20}=1:1\) 

                                                \(3.x+\dfrac{63}{20}=1\) 

                                                         \(3.x=1-\dfrac{63}{20}\) 

                                                         \(3.x=\dfrac{-43}{20}\) 

                                                            \(x=\dfrac{-43}{20}:3\) 

                                                            \(x=\dfrac{-43}{60}\)

b)Tận cùng=5 hoặc 0 nhưng mình ngại viết lắm,thông cảm nha