đâu đó sẽ là dấu x

1x2x3x4x5x6x7x8x9=100

thỏa mãn yêu cầu bài ra

1+2+3+4+5+6+7+8.9=100

1+2+3+4+5+6+7+8x9=100

10 x 9 x 8 x 7 x 6 : ( 5 + 4x3 - 2 ) + 1 = 2017 nhe

\(\frac{2}{3}:\frac{5}{6}=\frac{4}{5}\)

\(\frac{4}{5}\cdot\frac{2}{3}=\frac{8}{15}\)

Vậy : \(\frac{2}{3}:\frac{5}{6}< \frac{4}{5}x\cdot\frac{2}{3}\)nên \(\frac{4}{5}< \frac{8}{15}\)

Mình làm câu A

\(\frac{1}{2}\cdot\frac{3}{4}=\frac{3}{8}\)\(;\frac{5}{8}:\frac{6}{8}=\frac{5}{6}\)

Vậy \(\frac{1}{2}\cdot\frac{3}{4}< \frac{5}{8}:\frac{6}{8}\)

Nên : \(\frac{3}{8}< \frac{5}{6}\)

\(\frac{1}{4}+\frac{3}{8}+\frac{5}{16}=\frac{5}{8}+\frac{5}{16}=\frac{15}{16}\)

\(\frac{3}{5}-\frac{1}{3}-\frac{1}{6}=\frac{4}{15}-\frac{1}{6}=\frac{1}{10}\)

\(\frac{4}{7}\cdot\frac{5}{8}\cdot\frac{7}{12}=\frac{4.5.7}{7.8.12}=\frac{140}{672}=\frac{5}{24}\)

\(\frac{25}{28}:\frac{15}{14}\cdot\frac{6}{7}=\frac{5}{6}\cdot\frac{6}{7}=\frac{5}{7}\)

\(\frac{1}{4}+\frac{3}{8}+\frac{5}{16}=\frac{15}{16}\)

\(\frac{3}{5}-\frac{1}{3}-\frac{1}{6}=\frac{1}{10}\)

\(\frac{4}{7}\times\frac{5}{8}\times\frac{7}{12}=\frac{5}{24}\)

\(\frac{25}{28}:\frac{15}{14}\times\frac{6}{7}=\frac{5}{7}\)

cam on ban

Tui chơi bang bang trao đổi acc không

A.\(\frac{12}{15}>\frac{8}{15}\)

B.\(\frac{3}{8}< \frac{5}{6}\)

C.\(\frac{6}{7}< \frac{14}{3}\)

D.\(\frac{143}{144}>\frac{99}{100}\)

Nhớ k mình nha

a)\(\dfrac{x}{60}=-\dfrac{3}{4}\)

\(\Rightarrow x\cdot4=60\cdot\left(-3\right)\)

   \(x\cdot4=-180\)

  x=45

b)\(\dfrac{2}{5}=\dfrac{12}{x}\)

   \(\Rightarrow2x=5\cdot12\)

      \(2x=60\)

       x=30

c)\(x-\dfrac{5}{7}=\dfrac{6}{21}\)

      \(x=\dfrac{2}{7}+\dfrac{5}{7}\)

      x=1

d)\(x+\dfrac{7}{8}=\dfrac{63}{24}\)

     \(x=\dfrac{21}{8}-\dfrac{7}{8}\)

     \(\dfrac{14}{8}\)

a)\(\dfrac{x}{60}=\dfrac{-3}{4}\Rightarrow x=\dfrac{-3.60}{4}=-45\)

b)\(\dfrac{2}{5}=\dfrac{12}{x}\Rightarrow x=\dfrac{5.12}{2}=30\)