\(\dfrac{3x4x7}{12x8x9}\) =.................................
Tính:
3x4x7
------------
12x8x9
\(\dfrac{3.4.7}{3.4.8.9}=\dfrac{7}{72}\)
\(\dfrac{3\times4\times7}{12\times8\times9}\)
\(=\dfrac{12\times7}{12\times8\times9}\)
\(=\dfrac{7}{72}\)
`(3xx4xx7)/(12xx8xx9)=(3xx4xx7)/(3xx4xx8xxx9)= 7/(8xx9)=7/72`
3x4x7
---------- =
3x10x8
\(\dfrac{3x4x7}{3x10x8}=\dfrac{84}{240}\)
\(\dfrac{3\times4\times7}{3\times10\times8}=\)\(\dfrac{3\times4\times7}{3\times10\times2\times4}=\dfrac{3\times7}{10\times2}=\dfrac{21}{20}\)
2x3x4-2x3x4x9+2x3x4x11-2x3x4x13/3x4x7-3x4x7x9+3x4x7x11-3x4x7x13
\(=\frac{2.3.4.\left(1-9+11-13\right)}{3.4.7.\left(1-9+11-13\right)}=\frac{2}{7}\)
1.rút gọn các số sau. 121/111. 1313/1717. 3x4x7/12x3x4. 2x3x5x9/4x3x7x18
Rút gọn:
121/111=(mik k bt nha)
1313/1717=13/17
3.4.7/12.3.4=7/12
2.3.5.9/4.3.7.18=5/14
Tính nhanh :
a) \(\frac{3x4x7}{5x3x4}\) b) \(\frac{2x5x6x8}{6x2x8x9}\) c) \(\frac{4x5x6}{3x10x8}\)
a)
\(\frac{3\times4\times7}{5\times3\times4}=\frac{7}{5}\)
b)
\(\frac{2\times5\times6\times8}{6\times2\times8\times9}=\frac{5}{9}\)
c)
\(\frac{4\times5\times6}{10\times3\times8}=\frac{4\times5\times3\times2}{5\times2\times3\times4\times2}=\frac{1}{2}\)
\(a,\frac{3\times4\times7}{5\times3\times4}=\frac{7}{5}\)
\(b,\frac{2\times5\times6\times8}{6\times2\times8\times9}=\frac{5}{9}\)
\(c,\frac{4\times5\times6}{10\times3\times8}\)
\(=\frac{4\times5\times3\times2}{5\times2\times3\times4\times2}\)
\(=\frac{1}{2}\)
bài 77: tính bằng cách thuận tiện:
a) 4x25x7/5x10x21 b) 2x5x11/3x11x5
c3x4x7/12x8x9 d) 4x5x6/12x10x8
e)12/25+3/5+13/25 f) 3/2+2/3+4/3
giúp mình với
\(\dfrac{\dfrac{\dfrac{9}{9}}{\dfrac{9}{9}}}{\dfrac{\dfrac{9}{9}}{\dfrac{9}{9}}}+\dfrac{\dfrac{\dfrac{9}{9}}{\dfrac{9}{9}}}{\dfrac{\dfrac{9}{9}}{\dfrac{9}{9}}}=\)
\(\dfrac{\dfrac{\dfrac{9}{9}}{\dfrac{9}{9}}}{\dfrac{\dfrac{9}{9}}{\dfrac{9}{9}}}\) + \(\dfrac{\dfrac{\dfrac{9}{9}}{\dfrac{9}{9}}}{\dfrac{\dfrac{9}{9}}{\dfrac{9}{9}}}\) = 1 + 1 = 2
Giúp mk với
Câu 1:
Cho A = \(\dfrac{1}{\dfrac{99}{\dfrac{1}{2}+}}+\dfrac{2}{\dfrac{98}{\dfrac{1}{3}+}}+\dfrac{3}{\dfrac{97}{\dfrac{1}{4}+....}}+...+\dfrac{99}{\dfrac{1}{\dfrac{1}{100}}}\).
B =\(\dfrac{92}{\dfrac{1}{45}+}-\dfrac{1}{\dfrac{9}{\dfrac{1}{50}+}}-\dfrac{2}{\dfrac{10}{\dfrac{1}{55}+}}-\dfrac{3}{\dfrac{11}{\dfrac{1}{60}+....}}-...\dfrac{92}{\dfrac{100}{\dfrac{1}{500}}}\). Tính \(\dfrac{A}{B}\)
\(\dfrac{\dfrac{2}{5}-\dfrac{2}{9}+\dfrac{2}{11}}{\dfrac{7}{5}-\dfrac{7}{9}+\dfrac{7}{11}}-\dfrac{\dfrac{1}{3}-}{1\dfrac{1}{6}-}\dfrac{\dfrac{1}{4}}{\dfrac{7}{8}+}\dfrac{+\dfrac{1}{5}}{0,7}\)
\(\dfrac{\dfrac{2}{5}-\dfrac{2}{9}+\dfrac{2}{11}}{\dfrac{7}{5}-\dfrac{7}{9}+\dfrac{7}{11}}-\dfrac{\dfrac{1}{3}-\dfrac{1}{4}+\dfrac{1}{5}}{1\dfrac{1}{6}-\dfrac{7}{8}+0,7}\\ =\dfrac{2\left(\dfrac{1}{5}-\dfrac{1}{9}+\dfrac{1}{11}\right)}{7\left(\dfrac{1}{5}-\dfrac{1}{9}+\dfrac{1}{11}\right)}-\dfrac{\dfrac{2}{6}-\dfrac{2}{8}+\dfrac{2}{10}}{\dfrac{7}{6}-\dfrac{7}{8}+\dfrac{7}{10}}\\ =\dfrac{2}{7}-\dfrac{2\left(\dfrac{1}{6}-\dfrac{1}{8}+\dfrac{1}{10}\right)}{7\left(\dfrac{1}{6}-\dfrac{1}{8}-\dfrac{1}{10}\right)}\\ =\dfrac{2}{7}-\dfrac{2}{7}=0\)