Tính:

\(\dfrac{10}{21}-1\cdot251+\dfrac{11}{21}+2\cdot251\\ 251\cdot\left(\dfrac{10}{21}+\dfrac{11}{21}\right)+\left(2-1\right)\\ 251\cdot1+1=252\)

Tìm x

c,\(\left(3x-1\right)^2:7=7\\ \left(3x-1\right)^2=7\cdot7=14\\ \left(3x-1\right)^2=\left(\pm7\right)^2\\ \Rightarrow\left[{}\begin{matrix}3x-1=7\\3x-1=-7\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}3x=7+1=8\\3x=-7+1=-6\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=\dfrac{8}{3}\\x=-\dfrac{6}{3}=-2\end{matrix}\right.\)

Vậy x={8/3;-2}

d; \(\left(7-2x\right)^3=\left(\dfrac{1}{2}\right)^2\cdot\left(-\dfrac{1}{2}\right)\\ \left(7-2x\right)^3=\left(-\dfrac{1}{2}\right)^3\\ 7-2x=-\dfrac{1}{2}\\ 2x=7--\dfrac{1}{2}=\dfrac{15}{2}\\ x=\dfrac{15}{2}:2=\dfrac{15}{4}\)

giúp với mn ơiii

A = \(\dfrac{10}{21}\) - 1.251 + \(\dfrac{11}{21}\) + 2.251

A = (\(\dfrac{10}{21}\) + \(\dfrac{11}{21}\)) - 1.251 + 2.251

A = \(\dfrac{21}{21}\) + 251

A = 1 + 251

A = 252

C, (3\(x\) - 1)²: 7 = 7

     (3\(x\) -1)²     = 7 x  7

     (3\(x\) -1)² = 49

    \(\left[{}\begin{matrix}3x-1=7\\3x-1=-7\end{matrix}\right.\)

    \(\left[{}\begin{matrix}3x=8\\3x=-6\end{matrix}\right.\)

   \(\left[{}\begin{matrix}x=\dfrac{8}{3}\\x=-2\end{matrix}\right.\)

Vậy \(x\) \(\in\){-2;\(\dfrac{8}{3}\)}

d, (7 - 2\(x\))³ = (\(\dfrac{1}{2}\))² \(\times\) (- \(\dfrac{1}{2}\))

    (7- 2\(x\))³ =  (- \(\dfrac{1}{2}\))³

    7 - 2\(x\)   = - \(\dfrac{1}{2}\)

       2\(x\)     = 7 + \(\dfrac{1}{2}\)

       2\(x\)     = \(\dfrac{15}{2}\)

          \(x\)     = \(\dfrac{15}{2}\): 2

         \(x\)     =   \(\dfrac{15}{4}\)

Các bạn giúp mình với ạ

a) \(2.\left(x+\frac{2}{5}\right)+1\frac{1}{4}=\frac{11}{20}\)

\(2.\left(x+\frac{2}{5}\right)+\frac{5}{4}=\frac{11}{20}\)

\(2.\left(x+\frac{2}{5}\right)=\frac{-7}{10}\)

\(x+\frac{2}{5}=\frac{-7}{20}\)

\(x=\frac{-13}{20}\)

Vậy \(x=\frac{-13}{20}\)

b)\(x-1\frac{1}{8}-\frac{2}{3}x-\frac{5}{6}x=75\%\)

  \(\left(x-\frac{2}{3}x-\frac{5}{6}x\right)-\frac{9}{8}=\frac{3}{4}\)

\(\frac{-1}{2}x-\frac{9}{8}=\frac{3}{4}\)

\(\frac{-1}{2}x=\frac{15}{8}\)

\(x=\frac{-15}{4}\)

Vậy \(x=\frac{-15}{4}\)

\(a,2.\left(x+\frac{2}{5}\right)+1\frac{1}{4}=\frac{11}{20}\)

\(2.\left(x+\frac{2}{5}\right)+\frac{5}{4}=\frac{11}{20}\)

\(2.\left(x+\frac{2}{5}\right)=\frac{11}{20}-\frac{5}{4}\)

\(2.\left(x+\frac{2}{5}\right)=\frac{-7}{10}\)

\(x+\frac{2}{5}=\frac{-7}{10}:2\)

\(x+\frac{2}{5}=\frac{-7}{20}\)

\(x=\frac{-7}{20}-\frac{2}{5}\)

\(x=\frac{-3}{4}\)

A)  7/38 x 9/11 +7/38 x 4/11 -7/38 x 2/11

=7/38.(9/11+4/11-2/11)

=7/38

B) 5/31 x 21/25 + 5/31 x -7/10 - 5/31 x 9/20

=5/31.(21/25-7/10-9/20)

=5/31.(-31/100)

=-1/20

a) x= \(\frac{-5}{12}\)

b) x = \(\frac{2}{5}\)

c) x =\(\frac{-87}{140}\)

d) x = \(\frac{109}{140}\)

e) x = \(\frac{13}{63}\)

Làm đầy đủ nha , mk thick cho , đừng viết kết quả 

a) \(\frac{11}{13}\)-  (\(\frac{5}{42}\)- X ) = -(\(\frac{15}{28}\)-\(\frac{11}{13}\))

    \(\frac{5}{42}\)- X =\(\frac{11}{13}\)+\(\frac{15}{28}\)-\(\frac{11}{13}\)

   \(\frac{5}{42}\)- X =\(\frac{15}{28}\)

                X = \(\frac{5}{42}\)-\(\frac{15}{28}\)

                X = \(\frac{-5}{12}\)

b) X + \(\frac{1}{3}\)= \(\frac{2}{5}\)- ( \(\frac{-1}{3}\))

    X +\(\frac{1}{3}\) = \(\frac{11}{15}\)

   X               = \(\frac{11}{15}\)-\(\frac{1}{3}\)

   X               = \(\frac{2}{5}\)

c) \(\frac{2}{3}\)X +\(\frac{5}{7}\)=\(\frac{3}{10}\)

    \(\frac{2}{3}\)X            = \(\frac{3}{10}\)-\(\frac{5}{7}\)

    \(\frac{2}{3}\)X            =\(\frac{-29}{70}\)

             X            = \(\frac{-29}{70}\): \(\frac{2}{3}\)

            X             = \(\frac{-87}{140}\)

d) \(\frac{3}{7}\)- X =\(\frac{1}{4}\)- (\(\frac{-3}{-5}\))

               X  = \(\frac{3}{7}\)-\(\frac{1}{4}\)+\(\frac{3}{5}\)

               X  = \(\frac{109}{140}\)

e) \(\frac{-21}{-13}\)X +\(\frac{1}{3}\)=\(\frac{-2}{-3}\)

   \(\frac{-21}{-13}\)X              = \(\frac{-2}{-3}\)-\(\frac{1}{3}\)

    \(\frac{-21}{-13}\)X            =\(\frac{1}{3}\)

                   X             = \(\frac{1}{3}\):\(\frac{-21}{-13}\)

                   X             = \(\frac{13}{63}\)

Hk tốt

ai giúp mình sẽ kb với k