\(A=\frac{2013}{2014}+\frac{2014}{2015}+\frac{2013}{2013}+\frac{1}{2013}+\frac{1}{2013}=\left(\frac{2013}{2014}+\frac{1}{2013}\right)+\left(\frac{2014}{2015}+\frac{1}{2013}\right)+1\)

Ta có: \(\frac{2013}{2014}+\frac{1}{2013}>\frac{2013}{2014}+\frac{1}{2014}=\frac{2014}{2014}=1\)

\(\frac{2014}{2015}+\frac{1}{2013}>\frac{2014}{2015}+\frac{1}{2015}=\frac{2015}{2015}=1\)

=> A > 1+ 1 + 1 = 3

A=\(\dfrac{2013+2014}{2014+2015}=\dfrac{2013}{2014+2015}+\dfrac{2014}{2014+2015}\)

B=\(\dfrac{2013}{2014}+\dfrac{2014}{2015}\)

Vì \(\dfrac{2013}{2014}>\dfrac{2013}{2014+2015}\); \(\dfrac{2014}{2015}>\dfrac{2014}{2014+2015}\) nên B>A

Ta có : 

\(\frac{2013}{2014}< 1\)( 1 )

\(\frac{2014}{2015}< 1\)( 2 )

\(\frac{2015}{2016}< 1\)( 3 )

từ ( 1 ) , ( 2 ) và ( 3 ) 

\(\Rightarrow\frac{2013}{2014}+\frac{2014}{2015}+\frac{2015}{2016}< 1+1+1=3\)

vậy A < 3

Có: 2013/2014<2014/2014

      2014/2015<2015/2015

      2015/2016<2016/2016

=>2013/2014+2014/2015+2015/2016<2014/2014+2015/015+2016/2016

=>A<3

Có: 2013/2014<2014/2014

      2014/2015<2015/2015

      2015/2016<2016/2016

=>2013/2014+2014/2015+2015/2016<2014/2014+2015/015+2016/2016

=>A<3

A<3 nha

\(\frac{2013}{2014}+\frac{2014}{2015}+\frac{2015}{2013}\)

= \(\frac{2013}{2014}+\frac{2014}{2015}+\frac{2013}{2013}+\frac{1}{2013}+\frac{1}{2013}\)

= \(\left(\frac{2013}{2014}+\frac{1}{2013}\right)+\left(\frac{2014}{2015}+\frac{1}{2013}\right)+1\)

Ta có :\(\frac{2013}{2014}+\frac{1}{2013}>\frac{2013}{2014}+\frac{1}{2014}=1\)

           \(\frac{2014}{2015}+\frac{1}{2013}>\frac{2014}{2015}+\frac{1}{2015}=1\)

=> A > 1 + 1 + 1 = 3

Vậy A > 3

A=3,00000074 và lớn hơn 3

tra loi

a>3

nha

\(B=\frac{2013-1}{2013}+\frac{2014-1}{2014}+\frac{2012+3}{2012}\)

\(B=1-\frac{1}{2013}+1-\frac{1}{2014}+1+\frac{3}{2012}=3+\frac{3}{2012}-\left(\frac{1}{2013}+\frac{1}{2014}\right)\)

Ta có

\(\frac{1}{2013}< \frac{1}{2012};\frac{1}{2014}< \frac{1}{2012}\Rightarrow\frac{1}{2013}+\frac{1}{2014}< \frac{2}{2012}\)

Mà \(\frac{3}{2012}-\frac{2}{2012}=\frac{1}{2012}>0\Rightarrow\frac{3}{2012}-\left(\frac{1}{2013}+\frac{1}{2014}\right)>0\)

=> B>3

\(B=\frac{2012}{2013}+\frac{2013}{2014}+\frac{2015}{2012}\)

\(B=\frac{2012}{2013}+\frac{2013}{2014}+\left(\frac{1}{2012}+\frac{1}{2012}+\frac{2013}{2012}\right)\)

\(B=\left(\frac{2012}{2013}+\frac{1}{2012}\right)+\left(\frac{2013}{2014}+\frac{1}{2012}\right)+\frac{2013}{2012}\)

\(3=1+1+1\)

\(\frac{2012}{2013}+\frac{1}{2012}>1\)

\(\frac{2013}{2014}+\frac{1}{2012}>1\)

\(\frac{2013}{2012}>1\)

vậy B > 3