Tìm x€ Z, biết:
1) 7/11 x -3/7< x< -1/5 :1/20 -(-2)3
2) tính tổng S= 1/1.3 + 1/2.4 + 1/3.5 +...+1/7.9 + 1/8.10
Cách làm
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Tính tổng S=1/1.3 +1/2.4+ 1/3.5+....+1/7.9 +1/8.10
S=(1/1.3+1/3.5+.....+1/7.9) + (1/2.4+1/4.6+....+1/8.10)
2S=1/2.(1-1/9+(1/2-1/10))
2S=1/2.(8/9 + 2/5)
2S=1/2.58/45
2S=29/45
S=29/45:2
S=29/90
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S=(1/1.3+1/3.5+.....+1/7.9) + (1/2.4+1/4.6+....+1/8.10)
2S=1/2.(1-1/9+(1/2-1/10))
2S=1/2.(8/9 + 2/5)
2S=1/2.58/45
2S=29/45
S=29/45:2
S=29/90
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S = (1/1.3 + 1/3.5 + ... + 1/7.9) + (1/2.4 + 1/4.6 + ... + 1/8.10)
S = 2(1/1 - 1/3 + 1/3 - 1/5 + ... + 1/7 - 1/9) + 1/2(1/2 - 1/4 + 1/4 - 1/6 + ... + 1/8 - 1/10)
S = 2.(1 - 1/9) + 1/2.(1/2 - 1/10)
S = 16/9 + 1/5 = 89/45
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tính tổng S= 1/1.3+ 1/2.4+ 1/3.5+........+ 1/7.9+1/8.10
S= 1/1.3+ 1/2.4+1/3.5+....+!/7.9+1/8.10
=1/2(1-1/3 +1/2-1/4 +1/3-1/5 +...+ 1/7-1/9 + 1/8-1/10)
=1/2(1+1/2-1/9-1/10)
=....
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\(S=\frac{1}{1.3}+.....+\frac{1}{8.10}\)
\(2S=\frac{2}{1.3}+....+\frac{2}{8.10}\)
\(2S=1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+....+\frac{1}{8}-\frac{1}{10}\)
\(2S=1-\frac{1}{10}\)
\(2S=\frac{9}{10}\)
\(S=\frac{9}{10}:2\)
\(S=\frac{9}{20}\)
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Xem thêm câu trả lời
Tính tổng S= 1/1.3 + 1/2.4 + 1/3.5+...+1/7.9 + 1/8.10
Tính tổng S= 1/1.3 + 1/2.4 + 1/3.5 + ...+1/7.9 + 1/8.10
B1:Tính nhanh:
a)M= -1/3 . 141/17 - 39/3 . -1/17
b)N= -9/16 . 13/3 - (-3/4)^2 . 19/3
c)P=(1+1/1.3) (1+1/2.4) (1+1/3.5)......(1+1/99.101)
B2:Tìm x,biết
a)1/2+3/2:x=1/4
b)3/4+1/4.x=7
c)1/2.4 + 1/4.6 +.........+1/(2x-2).2x = 11/48
B3:Tìm x,biết
a)(x-1/2)^2=1/81
b)x+x(1+1/x)+x(1+2/x)=1/3
c)2/x+4=3/x+5
1) A = 1/1.3 + 1/2.4 + 1/3.5 + ... + 1/7.9 + 1/8.10
2) Chứng minh:
3/1^2.2^2 + 5/2^2.3^2 + 5/3^2.4^2 + ... + 19/9^2.10^2 < 1
Help me, please!!!!!!!!!!!
Bạn nào biết đề khảo sát chất lượng đầu năm lớp 7 thì cho mình nha!
Tìm x: [12/11-(1/2+1/44].(x-0,2)=1/1.3+1/3.5+1/5.7+1/7.9+1/9.11
Mik giải phía dưới rồi đó. Câu lúc nãy bạn đăng ý
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Tìm x: [12/11-(1/2+1/44].(x-0,2)=1/1.3+1/3.5+1/5.7+1/7.9+1/9.11
\(\left[\frac{12}{11}-\left(\frac{1}{2}+\frac{1}{44}\right)\right].\left(x-0,2\right)=\frac{1}{1.3}+\frac{1}{3.5}+\frac{1}{5.7}+\frac{1}{7.9}+\frac{1}{9.11}\)
\(\frac{25}{44}.\left(x-0,2\right)=\frac{1}{2}.\left(\frac{1}{1.3}+\frac{1}{3.5}+...+\frac{1}{9.11}\right)\)
\(x-0,2=\frac{1}{2}.\left(1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+...+\frac{1}{9}-\frac{1}{11}\right):\frac{25}{44}\)
\(x-\frac{1}{5}=\frac{22}{25}.\left(1-\frac{1}{11}\right)=\frac{22}{25}.\frac{10}{11}=\frac{4}{5}\)
\(x=\frac{4}{5}+\frac{1}{5}\)
\(x=1\)
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Tính S = 1.3/3.5 + 2.4/5.7 + 3.5/7.9 + ... + ( n-1)( n+1) / (2n-1)(2n+1) + ... + 1002.1004/2005.2007
\(S=\frac{1.3}{3.5}+\frac{2.4}{5.7}+\frac{3.5}{7.9}+...+\frac{\left(n-1\right)\left(n+1\right)}{\left(2n-1\right)\left(2n+1\right)}+...+\frac{1002.1004}{2005.2007}\)
\(\Rightarrow S=\frac{\left(2-1\right)\left(2+1\right)}{\left(2.2-1\right)\left(2.2+1\right)}+\frac{\left(3-1\right)\left(3+1\right)}{\left(3.2-1\right)\left(3.2+1\right)}+...+\frac{\left(n-1\right)\left(n+1\right)}{\left(2n-1\right)\left(2n+1\right)}\)
\(+..+\frac{\left(1003-1\right)\left(1003+1\right)}{\left(1003.2-1\right)\left(1003.2+1\right)}\)
\(\Rightarrow S=\frac{1}{4}-\frac{3}{8}\left(\frac{1}{2.2-1}-\frac{1}{2.2+1}\right)+\frac{1}{4}-\frac{3}{8}\left(\frac{1}{3.2-1}-\frac{1}{3.2+1}\right)+...\)
\(+\frac{1}{4}-\frac{3}{8}\left(\frac{1}{2n-1}-\frac{1}{2n+1}\right)+...+\frac{1}{4}-\frac{3}{8}\left(\frac{1}{1003.2-1}-\frac{1}{1003.2+1}\right)\)
\(\Rightarrow S=1002.\frac{1}{4}-1002.\frac{3}{8}\left(\frac{1}{2.2-1}-\frac{1}{2.2+1}+\frac{1}{3.2-1}-...-\frac{1}{1003.2+1}\right)\)
\(\Rightarrow S=\frac{501}{2}-\frac{1503}{4}\left(\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+...+\frac{1}{2005}-\frac{1}{2007}\right)\)
\(\Rightarrow S=\frac{501}{2}-\frac{1503}{4}\left(\frac{1}{3}-\frac{1}{2007}\right)\)
\(\Rightarrow S=\frac{501}{2}-\frac{1503}{4}.\frac{668}{2007}\)
\(\Rightarrow S=\frac{501}{2}-\frac{27889}{223}\)
\(\Rightarrow S=125,4372197\)
\(\)
