x=8 ; y =5 nhé

x= 5                                   ; x=8

y=1                                    ; y=5   

x=8;y=5 bạn nhé

17/5=3.4

31/4=7.75

x={+-4.+-5.+-6]

Tai sao?

x=8

y=5

Nhớ t..i..c..k nha

có thể trả lời rõ hơn đc k cách làm để ra kết quả đó ấy

Lời giải:

$x^2=4.4.4.4=16.16=(-16)(-16)=16^2=(-16)^2$

$\Rightarrow x=16$ hoặc $x=-16$.

nhanh giúp mình với 

\(\Rightarrow-3x=\dfrac{6}{7}-\dfrac{30}{21}\\ \Rightarrow-3x=\dfrac{18}{21}-\dfrac{30}{21}\\\Rightarrow-3x=\dfrac{-12}{21}\\ \Rightarrow x=\dfrac{-12}{21}:3\\ \Rightarrow x=\dfrac{-12}{63}=\dfrac{-4}{21} \)

-3x+\(\dfrac{30}{21}=\dfrac{6}{7}\)

=>-3x=\(\dfrac{6}{7}-\dfrac{30}{21}\)

=>-3x=\(\dfrac{18-30}{21}\)

=>-3x=\(\dfrac{-12}{21}\)

=>x=\(\dfrac{-12}{21}.\dfrac{1}{3}\)

=>x=\(\dfrac{-12}{63}=\dfrac{-4}{21}\)

Vậy ......

\(\Leftrightarrow y^2=x^2+4x+5\left(y\ge0\right)\\ \Leftrightarrow y^2-\left(x+2\right)^2=1\\ \Leftrightarrow\left(y-x-2\right)\left(y+x+2\right)=1\)

Vì \(x,y\in Z\Leftrightarrow\left(y-x-2\right)\left(y+x+2\right)=1\cdot1=\left(-1\right)\left(-1\right)\)

\(\left\{{}\begin{matrix}y-x-2=1\\y+x+2=1\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}y-x=3\\y+x=-1\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=-2\\y=1\end{matrix}\right.\left(tm\right)\)

\(\left\{{}\begin{matrix}y-x-2=-1\\y+x+2=-1\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}y-x=1\\y+x=-3\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=-2\\y=-1\end{matrix}\right.\left(ktm\right)\)

Vậy \(\left(x;y\right)=\left(-2;1\right)\)