tính nhanh:
A=(1-1/21).(1-1/28).(1-1/36). ... .(1-1/1326)
B=(1+1/1.3).(1+1/2.4).(1+1/3.5). ... .(1+1/99.100)
Giúp với
Tính:
\(A=\left(1-\frac{1}{21}\right)\left(1-\frac{1}{28}\right)\left(1-\frac{1}{36}\right)...\left(1-\frac{1}{1326}\right)\)
\(B=\left(1+\frac{1}{1.3}\right)\left(1+\frac{1}{2.4}\right)\left(1+\frac{1}{3.5}\right)...\left(1+\frac{1}{99.101}\right)\)
Mong các bạn giúp đỡ. Cảm ơn nhiều *cúi đầu*
\(A=xemlai\) chưa hưa hiểu Quy luật
\(B=\frac{\left(n.\left(n+2\right)+1\right)}{n\left(n+2\right)}=\frac{\left(n+1\right)^2}{n.\left(n+2\right)}\)
\(B=\frac{2.2}{1.3}.\frac{3.3}{2.4}.\frac{4.4}{3.5}.\frac{5.5}{4.5}...\frac{98.98}{97.99}\frac{99.99}{98.100}\frac{100.100}{99.101}\\\)
\(B=\frac{2.100}{1.101}=\frac{200}{101}\)
Tính các tích sau:
a)\(A=\frac{3}{4}.\frac{8}{9}.\frac{15}{16}.....\frac{9999}{10000}\)
b)\(B=\left(1-\frac{1}{21}\right).\left(1-\frac{1}{28}\right).\left(1-\frac{1}{36}\right)......\left(1-\frac{1}{1326}\right)\)
c)\(C=\left(1+\frac{1}{1.3}\right).\left(1+\frac{1}{2.4}\right).\left(1+\frac{1}{3.5}\right)....\left(1+\frac{1}{99.101}\right)\)
tinhs S=(`1+1/1.3).(1+1/2.4).(1+1/3.5)......(1+1/99.100)
S=2/1.3+2/2.4+2/3.5................2/99.100
=1-1/3+..........................1/99-1/100
=1-1/100
=99/100
VẬY S =99/100
\(B=(1-\frac{1}{21}).(1-\frac{1}{36})...(1-\frac{1}{1326})\)
\(C=(1+\frac{1}{1.3}).(1+\frac{1}{2.4}).(1+\frac{1}{3.5})...(1+\frac{1}{99.100})\)
\(D=(\frac{810}{167}-\frac{675}{225}):(\frac{810}{167}+\frac{675}{225})\)
\(E=(\frac{1648}{1751}+\frac{131313}{686868}):(\frac{1648}{1751}-\frac{131313}{686868})\)
\(F=(\frac{1248}{1391}+\frac{212121}{656565}):(\frac{27}{13}.3)\)
Ai nhanh cho full đúng ,đang cần gấp!!!!!!
ting gia tri cua bieu thuc :A=(1+1/1.3).(1+1/2.4).(1+1/3.5).....(1+1/99.100)
\(A=\left(1+\frac{1}{2^2-1}\right)\left(1+\frac{1}{3^2-1}\right)\left(1+\frac{1}{4^2-1}\right)\cdot...\cdot\left(1+\frac{1}{100^2-1}\right)\)
\(=\frac{2^2}{1\cdot3}\cdot\frac{3^2}{2\cdot4}\cdot\frac{4^2}{3\cdot5}\cdot...\cdot\frac{99^2}{98\cdot100}\cdot\frac{100^2}{99\cdot101}=\frac{200}{101}\)
\(A=\left(1+\frac{1}{1.3}\right)\left(1+\frac{1}{2.4}\right)\left(1+\frac{1}{3.5}\right)......\left(1+\frac{1}{99.100}\right)\)
\(=\left(1+\frac{1}{2^2-1}\right)\left(1+\frac{1}{3^2-1}\right)......\left(1+\frac{1}{100^2-1}\right)\)
\(=\frac{2^2}{1.3}.\frac{3^2}{2.4}..............\frac{100^2}{99.100}=\frac{200}{101}\)
T nha
Thu Gọn:
(1+1/1.3)(1+1/2.4)(1+1/3.5)...(1+1/99.100)
Các bn giúp mik nhé!Mik cần gấp nhớ giải chi tiết nữa nhé!thank you
Tính tích:
B= (1- 1/4).(1- 1/9).... (1- 1/1000)
C= 3/4 . 8/9 . 15/16 .... 99/100
D= (1+ 1/1.3) . (1+ 1/2.4) . (1+ 1/3.5).... (1+ 1/99.100)
Ai nhanh mình tích! ^_^
(1-1/21).(1-1/28).(1-1/36). ......... (1-1/1326) = ? Giúp mình nhanh với mình đang cần
Câu 1.Tính nhanh
A=(1+1/1.3).(1+1/2.4).(1+1/3.5).....(1+1/99.100)
dấu . là nhân
ai trả lời đúng và nhanh nhất mk tk cho nha