lớp 7 ko bít giải bài lớp 2 

1+2-2+4×5+6-7+8:12 nhỏ hơn 100 nha

điền dấu  < bạn nhé 

1 + 2 - 2 + 4 x 5 + 6 - 7 x 8 : 12 = 22,3 

22,3 < 100

nên điên đầu < bạn nhé 

chuc ban  học giỏi  

419 bn nha 

= 419^^

         HT

lớp 6 ai chơi được

không biết làm bài này hả

a. \(8x\left(x-2007\right)-2x+4034=0\)

\(\Rightarrow\left(x-2017\right)\left(4x-1\right)\)

\(\Rightarrow\left[{}\begin{matrix}x-2017=0\\4x-1=0\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=2017\\4x=1\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=2017\\x=\dfrac{1}{4}\end{matrix}\right.\)

Vậy x=2017 hoặc x=1/4

b.\(\dfrac{x}{2}+\dfrac{x^2}{8}=0\)

\(\Rightarrow\dfrac{x}{2}\left(1+\dfrac{x}{4}\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}\dfrac{x}{2}=0\\1+\dfrac{x}{4}=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=0\\\dfrac{x}{4}=-1\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=0\\x=-4\end{matrix}\right.\)

Vậy x=0 hoặc x=-4

c.\(4-x=2\left(x-4\right)^2\)

\(\Rightarrow\left(4-x\right)-2\left(x-4\right)^2=0\)

\(\Rightarrow\left(4-x\right)\left(2x-7\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}4-x=0\\2x-7=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=4\\x=\dfrac{7}{2}\end{matrix}\right.\)

Vậy x=4 hoặc x=7/2

d.\(\left(x^2+1\right)\left(x-2\right)+2x=4\)

\(\Rightarrow\left(x-2\right)\left(x^2+3\right)=0\)

Nxet: (x²+3)>0 với mọi x

=> x-2=0 <=>x=2

Vậy x=2

a, 8\(x\).(\(x-2007\)) - 2\(x\) + 4034 = 0

     4\(x\)(\(x\) - 2007) - \(x\) + 2017 = 0

     4\(x^2\) - 8028\(x\) - \(x\) + 2017 = 0

     4\(x^2\) - 8029\(x\) + 2017 = 0

     4(\(x^2\) - 2. \(\dfrac{8029}{8}\) \(x\) +( \(\dfrac{8029}{8}\))²) - (\(\dfrac{8029}{4}\))²  + 2017 = 0

    4.(\(x\) + \(\dfrac{8029}{8}\))² = (\(\dfrac{8029}{4}\))² - 2017

       \(\left[{}\begin{matrix}x=-\dfrac{8029}{8}+\dfrac{1}{2}.\sqrt{\left(\dfrac{8029}{4}\right)^2-2017}\\x=-\dfrac{8029}{8}-\dfrac{1}{2}.\sqrt{\left(\dfrac{8029}{4}\right)^2-2017}\end{matrix}\right.\) 

a) \(\left(x-1\right)^3+3\left(x+1\right)^2=\left(x^2-2x+4\right)\)

\(\Leftrightarrow x^3+9x+2=x^3+8\)

\(\Leftrightarrow x^3+9x=x^3+8-2\)

\(\Leftrightarrow x^3+9x=x^3+6\)

\(\Leftrightarrow x^3+9x=x^3+6x-x^3\)

\(\Leftrightarrow\frac{2}{3}\)

b) \(x^2-4=8\left(x-2\right)\)

\(\Leftrightarrow x^2-4=8x-16\)

\(\Leftrightarrow x^4-4=8x-16+16\)

\(\Leftrightarrow x^2+12=8x\)

\(\Leftrightarrow x^2+12=8x-8x\)

\(\Leftrightarrow x^2-8x+12=0\)

\(\Rightarrow\orbr{\begin{cases}x=2\\x=6\end{cases}}\)

Chắc là bằng 166 600.

\(A=2\times4+4\times6+...+98\times100\)

\(A=2.2+2.12+...+2.149\)

\(A=2.\left(2+12+...+149\right)\)

Tự làm nốt( dấu x = dấu chấm )

a,A = 2 x 4 + 4 x 6 + 6 x 8 +...+ 98 x 100

6 x A = 2 x 4 x 6 + 4 x 6 x 6 + 6 x 8 x 6 +...+ 98 x 100 x 6

6 x A = 2 x 4 x 6 + 4 x 6 x (8 - 2) + 6 x 8 x (10 - 98) + 98 x 100 x (102 - 96)

6 x A = 2 x 4 x 6 + 4 x 6 x 8 - 4 x 6 x 2 + 6 x 8 x 10 - 6 x 8 x 2 +...+ 98 x 100 x 102 - 98 x 100 x 96

6 x A = 2 x 4 x 6 + 4 x 6 x 2 + 98 x 100 x 102

6 x A = 48 + 48 + 999 600

6 x A = 999 696

      A = 999 696 : 3

      A = 333 232