a) 3/4 - x = 1                                  c) x - 1/5 = 2

            x = 3/4 - 1                              x          = 2 + 1/5

            x = -1/4                                  x          = 11/5

Vậy x = -1/4                                   Vậy x = 11/5                                

b) x+4 = 1/5                                  d) x + 5/3 = 1/81

    x      = 1/5 -4                                 x           = 1/81 -5/3

    x     =  -19/5                                  x           = -134/81

Vậy x = -19/5

a) 3/4 - x = 1

\(x=\frac{3}{4}-1\)

\(x=\frac{-1}{4}\)

b) x + 4 = 1/5

\(x=\frac{1}{5}-4\)

\(x=\frac{-19}{5}\)

c) x - 1/5 = 2

\(x=2+\frac{1}{5}\)

\(x=\frac{11}{5}\)

d) x + 5/3 = 1/81

\(x=\frac{1}{81}-\frac{5}{3}\)

\(x=\frac{-134}{81}\)

chúc bạn học tốt

a)\(\left(\frac{3}{5}\right)^5\times x=\left(\frac{3}{7}\right)^7\)

\(\Leftrightarrow\frac{3^5}{5^5}\times x=\frac{3^7}{7^7}\)

\(\Leftrightarrow x=\frac{3^7}{7^7}:\frac{3^5}{5^5}\)

\(\Leftrightarrow x=\frac{3^7\times5^5}{7^7\times3^5}\)

\(\Leftrightarrow x=\frac{3^2\times5^5}{7^7}\)

b)\(\left(\frac{-1}{3}\right)^3\times x=\frac{1}{81}\)

\(\Leftrightarrow\frac{\left(-1\right)^3}{3^3}\times x=\frac{1}{3^4}\)

\(\Leftrightarrow x=\frac{1}{3^4}:\frac{-1}{3^3}\)

\(\Leftrightarrow x=\frac{1\times3^3}{3^4\times\left(-1\right)}\)

\(\Leftrightarrow x=\frac{1}{-3}\)

c)\(\Leftrightarrow\left(x-\frac{1}{2}\right)^3=\left(\frac{1}{3}\right)^3\)

\(\Leftrightarrow x-\frac{1}{2}=\frac{1}{3}\)

\(\Leftrightarrow x=\frac{1}{3}+\frac{1}{2}\)

\(\Leftrightarrow x=\frac{5}{6}\)

d)\(\Leftrightarrow\left(x+\frac{1}{2}\right)^4=\left(\frac{2}{3}\right)^4\)

\(\Leftrightarrow x+\frac{1}{2}=\frac{2}{3}\)

\(\Leftrightarrow x=\frac{2}{3}-\frac{1}{2}\)

\(\Leftrightarrow x=\frac{1}{6}\)

a) \(x=\frac{7}{25}+\frac{-1}{5}\)

\(\Rightarrow x=\frac{2}{25}\)

Vậy \(x=\frac{2}{25}\)

b) \(x=\frac{5}{11}+\frac{4}{-9}\)

\(\Rightarrow x=\frac{1}{99}\)

Vậy \(x=\frac{1}{99}\)

c) \(\frac{5}{9}+x=\frac{-1}{3}\)

\(\Rightarrow x=\frac{-1}{3}-\frac{5}{9}\)

\(\Rightarrow x=\frac{-8}{9}\)

Vậy \(x=\frac{-8}{9}\)

d) \(\frac{3}{4}-x=-1\)

\(\Rightarrow x=\frac{3}{4}-\left(-1\right)\)

\(\Rightarrow x=\frac{7}{4}\)

Vậy \(x=\frac{7}{4}\)

e) \(x+4=\frac{1}{5}\)

\(\Rightarrow x=\frac{1}{5}-4\)

\(\Rightarrow x=\frac{-19}{5}\)

Vậy \(x=\frac{-19}{5}\)

f) \(x-\frac{1}{5}=2\)

\(\Rightarrow x=2+\frac{1}{5}\)

\(\Rightarrow x=\frac{11}{5}\)

Vậy \(x=\frac{11}{5}\)

g) \(x+\frac{5}{3}=\frac{1}{81}\)

\(\Rightarrow x=\frac{1}{81}-\frac{5}{3}\)

\(\Rightarrow x=\frac{-134}{81}\)

Vậy \(x=\frac{-134}{81}\)

_Chúc bạn học tốt_

a) (2^x)⁵ : 4³ = 8¹⁵ => 2^5x = 8¹⁵.4³ = (2³)¹⁵.(2²)³ = 2⁴⁵.2⁶ = 2⁵¹ => 5x = 51 => x = 10,2 

b) (3²)^x .9³ = 243⁹ => 3^2x = 243⁹ : 9³ = (3⁵)⁹ : (3²)³ = 3⁴⁵ : 3⁶ = 3³⁹ => 2x = 39 => x = 19,5

c) (1/125)³.5^x = 25⁵ => 5^x = 25⁵ : (1/125)³ = (5²)⁵ : (1/5³)³ = 5¹⁰ : (5^-3)³ = 5¹⁰ : 5^-9 = 5¹⁹ => x = 19

d) 1/81 : 3^x = 1/729 => 3^x = 1/81 : 1/729 = 1/3⁴.729 = 3^-4.3⁶ = 3² => x = 2

e) (5x - 2)⁴ = 16⁸ = (16²)⁴ = 256⁴

=> 5x - 2 = -256 ; 256 => 5x = -254 ; 258 => x = -50,8 ; 51,6

P/S : Thay x = 10,2 vào câu a , x = 19,5 vào câu b sẽ thấy điều hư cấu : 2^10,2 và 9^19,5.Ko thể tính được giá trị của 2 lũy thừa này.

692157

Bài 1:

a; (\(\dfrac{1}{4}\)\(x\) - \(\dfrac{1}{8}\)) x \(\dfrac{3}{4}\) = \(\dfrac{1}{4}\)

     \(\dfrac{1}{4}x\) - \(\dfrac{1}{8}\) = \(\dfrac{1}{4}\) : \(\dfrac{3}{4}\)

      \(\dfrac{1}{4}\)\(x\) - \(\dfrac{1}{8}\) = \(\dfrac{1}{4}\) x \(\dfrac{4}{3}\)

    \(\dfrac{1}{4}x\) - \(\dfrac{1}{8}\) =  \(\dfrac{1}{3}\)

      \(\dfrac{1}{4}x\) = \(\dfrac{1}{3}\) + \(\dfrac{1}{8}\)

       \(\dfrac{1}{4}\) \(x\)=  \(\dfrac{8}{24}\) + \(\dfrac{11}{24}\)

          \(\dfrac{1}{4}x=\dfrac{11}{24}\)

           \(x=\dfrac{11}{24}:\dfrac{1}{4}\)

           \(x=\dfrac{11}{24}\times4\)

           \(x=\dfrac{11}{6}\) 

b; \(\dfrac{12}{5}:x\) = \(\dfrac{14}{3}\) x \(\dfrac{4}{7}\)

     \(\dfrac{12}{5}\) : \(x\) = \(\dfrac{8}{3}\)

            \(x\) = \(\dfrac{12}{5}\) : \(\dfrac{8}{3}\)

            \(x\) = \(\dfrac{12}{5}\) x \(\dfrac{3}{8}\)

             \(x\) = \(\dfrac{9}{10}\)

c; \(x+\dfrac{2}{3}\) = 8:4 - 1

   \(x+\dfrac{2}{3}\) = 2 - 1

   \(x+\dfrac{2}{3}\) = 1

  \(x=1-\dfrac{2}{3}\)

  \(x\) = \(\dfrac{1}{3}\)

a) \(\left(x+5\right)^3=64\)

\(\Leftrightarrow\left(x+5\right)^3=4^3\)

\(\Leftrightarrow x+5=4\)

\(\Leftrightarrow x=-1\)

Vậy x = - 1

b) \(x:\left(-\frac{3}{5}\right)^2=-\frac{3}{5}\)

\(\Leftrightarrow x=\left(-\frac{3}{5}\right)^2.\left(-\frac{3}{5}\right)\)

\(\Leftrightarrow x=\left(-\frac{3}{5}\right)^3\)

\(\Leftrightarrow x=-0,216\)

Vậy x = - 0, 216

c) \(\left(\frac{4}{7}\right)^4.x=\left(\frac{4}{7}\right)^6\)

\(\Leftrightarrow x=\left(\frac{4}{7}\right)^6:\left(\frac{4}{7}\right)^4\)

\(\Leftrightarrow x=\left(\frac{4}{7}\right)^2\)

\(\Leftrightarrow\text{x}=\frac{16}{49}\)

Vậy x = 16/49

d) \(\left(-\frac{1}{3}\right)^3x=\frac{1}{81}\)

\(\Leftrightarrow-\frac{1}{27}x=\frac{1}{81}\)

\(\Leftrightarrow x=\frac{1}{81}:\left(-\frac{1}{27}\right)\)

\(\Leftrightarrow x=-\frac{1}{3}\)

Vậy x = - 1/3