Bang:  454545⁹⁴⁰¹⁷⁸

x= 202020

466 657 nha bạn

tk mình nha bạn

thank you bạn

12112+454545=466657

k mình nha Haibara Ai

12112+454545=466657

k minh nhe

mình chúc bạn vui!

\(\dfrac{989898}{454545}-\dfrac{31313131}{15151515}=\dfrac{98\cdot10101}{45\cdot10101}-\dfrac{31\cdot1010101}{15\cdot1010101}\\ =\dfrac{98}{45}-\dfrac{31}{15}=\dfrac{98-31\cdot3}{45}=\dfrac{5}{45}=\dfrac{1}{9}\)

\(\dfrac{1}{9}\)

453583663

\(\frac{131313}{151515}+\frac{131313}{353535}+\frac{131313}{636363}+\frac{131313}{999999}\)

\(=\frac{13}{15}+\frac{13}{35}+\frac{13}{63}+\frac{13}{99}\)

\(=13.\left(\frac{1}{15}+\frac{1}{35}+\frac{1}{63}+\frac{1}{99}\right)\)

\(=13.\left(\frac{1}{3.5}+\frac{1}{5.7}+\frac{1}{7.9}+\frac{1}{9.11}\right)\)

\(=13.\)\(\frac{1}{2}.\left(\frac{2}{3.5}+\frac{2}{5.7}+\frac{2}{7.9}+\frac{2}{9.11}\right)\)

\(=\frac{13}{2}.\left(\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-...-\frac{1}{11}\right)\)

\(=\frac{13}{2}.\left(\frac{1}{3}-\frac{1}{11}\right)\)

\(=\frac{13}{2}.\frac{8}{33}\)

\(=\frac{52}{33}\)

!

52/33

bài trên edu

202020/454545

= 20/45

= 4/9

~~tk mk nha m.n và Trần Thị Anh Thư ~^^

Ai Tk mK ThÌ mK tK LạI NhA ~~~~~~~~~~~~~~~~~~~~~~~~~~~~^^

= 4 / 15 nha

bằng 4/9 nhớ k cho mình nhé