Xx3+:4=5
Tìm x:(Viết dưới dạng phân số tối giản)
a) X:1/2=4
b) Xx3/5=15
a) \(x:\frac{1}{2}=4\)
\(x=4\times\frac{1}{2}\)
\(x=2\)
b)\(x\times\frac{3}{5}=15\)
\(x=15:\frac{3}{5}\)
\(x=25\)
a) \(\text{X}\div\frac{1}{2}=4\)
\(\text{X}=4\times\frac{1}{2}\)
\(\text{X}=2\)
b) \(\text{X}\times\frac{3}{5}=15\)
\(\text{X}=15\div\frac{3}{5}\)
\(\text{X}=25\)
Giải đáp
a) x = 4 x 1/2
x = 2
b) x = 15 : 3/5
x = 75/3
x = 25
Học tốt
a,x:3,5+3/8=15/5
b,xx3/4=12/5
c,[x+3,75]x2,7=17,55
d,x:2,3-12,4=0,94
a)x=9.1875
b)x=3.2
c)x=2.75
d)x=30.682
X:0,1-X:4-Xx3/4=2,25
X : 0,1 - X : 4 - X x 3 / 4 = 2 , 25
X x 10 - X x 1 / 4 - X x 3 / 4 = 2 , 25
X ( 10 - 1 / 4 - 3 / 4 ) = 2 , 25
X x 9 = 2 , 25
X = 0 , 25
Xx3+x/4=26
X x 3+ X : 4 =26
X x 3 + X x 1/4 = 26
X x ( 3 + 1/4 ) = 26
X x 13/4 = 26
X = 26 : 13/4
X = 8
\(x\) \(\times\) 3 + \(\dfrac{x}{4}\) = 26
\(x\times3+x\times\dfrac{1}{4}\)=26
\(x\times\left(3+\dfrac{1}{4}\right)\) = 26
\(x\times\dfrac{13}{4}\) = 26
\(x=26:\dfrac{13}{4}\)
\(x=8\)
Xx3/7=1-5/8
$x\times\dfrac{3}{7}=1-\dfrac{5}{8}$
$=>x\times\dfrac{3}{7}=\dfrac{3}{8}$
$=>x=\dfrac{3}{8}:\dfrac{3}{7}$
$=>x=\dfrac{7}{8}$
X:0,1-X:4-Xx3/4=2,25
x:0.1-x:4-xx3/4=2.25
118,24-(X:5+Xx3)=54,24
118,24-(X:5+Xx3)=54,24
118,24-x:(5+1/3)=54,24
118,24-x:16/3=54,24
x:16/3=64
x=1024/3
Vậy x=1024/3
\(118,24-\left(x:5+x.3\right)=54,24\)
\(\Rightarrow118,24-\left(x.0,2+x.3\right)=54,24\)
\(\Rightarrow118,24-\left[x.\left(0,2+3\right)\right]=54,24\)
\(\Rightarrow118,24-3,2x=54,24\)
\(\Rightarrow3,2x=118,24-54,24\)
\(\Rightarrow3,2x=64\)
\(\Rightarrow x=64:3,2\)
\(\Rightarrow x=20\)
Vậy x=20
Chúc bn học tốt
118,24 - \(x\times\frac{1}{5}\)+ \(x\times3\)= 54,24
\(x\times\frac{1}{5}\)+ 3 = 54,24
\(x\times\frac{16}{5}\) = 64
\(x\) = 64 : \(\frac{16}{5}\)
\(x\) = 20
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1/2+Xx3/4=2
1/2 + X x 3/4 = 2
X x 3/4 = 2 - 1/2
X x 3/4 = 3/2
X = 3/2 : 3/4
X = 1/2
1/2+x*3/4=2
1/2+x=2*4/3
1/2+x=8/3
x=8/3-1/2=16/6-3/6
x=13/6
1/2 + X x 3/4 = 2
X x 3/4 = 2 - 1/2
X x 3/4 = 3/2
X = 3/2 : 3/4
X = 2