Chứng minh rằng : \(\frac{1}{112^2}+\frac{1}{112^2}+\frac{1}{113^2}+\frac{1}{114^2}+\frac{1}{115^2}<\frac{1}{2.5.11.23}\)
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Chứng minh rằng : \(\frac{1}{112^2}+\frac{1}{112^2}+\frac{1}{113^2}+\frac{1}{114^2}+\frac{1}{115^2}<\frac{3}{2.5.11.23}\)
Tính A=112×113×114....×112016×112017A=1\frac{1}{2}\times1\frac{1}{3}\times1\frac{1}{4}....\times1\frac{1}{2016}\times1\frac{1}{2017}A=121×131×141....×120161×120171
Cho A=\(\frac{50}{111}+\frac{50}{112}+\frac{50}{113}+\frac{50}{114}\)
CMR 1<A<2
\(\frac{50}{111}>\frac{1}{4};\frac{50}{112}>\frac{1}{4};\frac{50}{113}>\frac{1}{4};\frac{50}{114}>\frac{1}{4}\)
\(A=\frac{50}{111}+\frac{50}{112}+\frac{50}{113}+\frac{50}{114}>\frac{1}{4}+\frac{1}{4}+\frac{1}{4}+\frac{1}{4}=1\)(1)
\(\frac{50}{111}< \frac{1}{2};\frac{50}{112}< \frac{1}{2};\frac{50}{113}< \frac{1}{2};\frac{50}{114}< \frac{1}{2}\)
\(\Rightarrow A=\frac{50}{111}+\frac{50}{112}+\frac{50}{113}+\frac{50}{114}< \frac{1}{2}+\frac{1}{2}+\frac{1}{2}+\frac{1}{2}=2\)(2)
từ (1) và (2) \(\Rightarrow1< A< 2\)
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Chứng minh rằng:
1/(111^2) + 1/(112^2) + 1/(113^2) + 1/(114^2) + 1/(115^2) < 3/(2.5.11.23)
Cho A=\(\frac{50}{111}+\frac{50}{112}+\frac{50}{113}+\frac{50}{114}\). Chứng tơ \(1< A< 2\)
Ta có :
\(\frac{50}{111}>\frac{50}{200}\)
\(\frac{50}{112}>\frac{50}{200}\)
\(\frac{50}{113}>\frac{50}{200}\)
\(\frac{50}{114}>\frac{50}{200}\)
\(\Rightarrow A>\frac{50}{200}+\frac{50}{200}+\frac{50}{200}+\frac{50}{200}\)hay \(A>\frac{50}{200}.4\left(1\right)\)
Mặt khác :
\(\frac{50}{111}< \frac{50}{100}\)
\(\frac{50}{112}< \frac{50}{100}\)
\(\frac{50}{113}< \frac{50}{100}\)
\(\frac{50}{114}< \frac{50}{100}\)
\(\Rightarrow A< \frac{50}{100}+\frac{50}{100}+\frac{50}{100}+\frac{50}{100}\)hay \(A< \frac{50}{100}.4\left(2\right)\)
Từ \(\left(1\right)\)và \(\left(2\right)\Rightarrow1< A< 2\left(đpcm\right)\)
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Tính: \(A=2\frac{1}{113}.\frac{1}{115}-\frac{3}{113}.3\frac{114}{115}-\frac{4}{113.115}+\frac{12}{113}\)
Cho A = \(\frac{50}{111}\)+\(\frac{50}{112}\)+\(\frac{50}{113}\)+\(\frac{50}{114}\). Chứng tỏ 1<a<2
50/111 < 50/100
50/112 < 50/100
50/113 < 50/100
50/114 < 50/100
=> A < 200/100 => A < 2
50/111 > 50/200
50/112 > 50/200
50/113 > 50/200
50/114 > 50/200
=> A > 200/200 => A > 1
Vậy 1 < A < 2
AI THẤY OK ỦNG HỘ NHÉ
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Cho A = \(\frac{50}{111}+\frac{50}{112}+\frac{50}{114}+\frac{50}{114}\)
Chứng tỏ 1<A<2
1)Tinh
a)\(A=\left(\frac{112}{13.20}+\frac{112}{20.27}\frac{112}{27.34}+...+\frac{112}{62.69}\right):\left(-\frac{5}{9.13}-\frac{7}{9.25}-\frac{13}{19.15}-\frac{31}{19.69}\right)\)
b)\(B=\frac{2.2012}{1+\frac{1}{1+2}+\frac{1}{1+2+3}+\frac{1}{1+2+3+4}+...+\frac{1}{1+2+3+...+2012}}\)