ko quy dong mau so hay so sanh: A=-9/10^2015+-19/10^2016 va -9/10^2016+-19/10^2015
Không quy đồng mẫu hãy so sánh:
\(A=\frac{-9}{10^{2015}}+\frac{-19}{10^{2016}}và\frac{-9}{10^{2016}}+\frac{-19}{10^{2015}}\)
KO QUY DONG MAU HAY SO SANH
\(A=\frac{-9}{10^{2010}}+\frac{-19}{10^{2011}}\)
\(B=\frac{-9}{10^{2011}}+\frac{-19}{10^{2010}}\)
\(\text{Không quy đồng mẫu hãy so sánh: }A=\frac{-9}{10^{2015}}+\frac{-19}{10^{2016}}với\)\(B=\frac{-9}{10^{2016}}+\frac{-19}{10^{2015}}\)
so sanh A= -9/ 10^2016 + -19/ 10^2017; B = -9/10^2017+-19/10^2016
khong quy dong mau so hay so sanh;
A= \(\frac{-9}{10^{2010}}+\frac{-19}{10^{2011}};\) B= \(\frac{-9}{10^{2011}}+\frac{-19}{10^{2010}}\)
hay quy dong mau so so sanh sau : A=\(\dfrac{-9}{10^{2010}}\)+\(\dfrac{-19}{10^{2011}}\)
B =\(\dfrac{-9}{10^{2011}}\)+\(\dfrac{-19}{10^{2010}}\)
giup minh nhanh nha . cam on nhiu
\(A=\dfrac{-9}{10^{2010}}+\dfrac{-19}{10^{2011}}=\dfrac{-90}{10^{2011}}+\dfrac{-19}{10^{2011}}=\dfrac{\left(-90\right)+\left(-19\right)}{10^{2011}}=\dfrac{-109}{10^{2011}}\)\(B=\dfrac{-9}{10^{2011}}+\dfrac{-19}{10^{2010}}=\dfrac{-9}{10^{2011}}+\dfrac{-190}{10^{2011}}=\dfrac{\left(-9\right)+\left(-190\right)}{10^{2011}}=\dfrac{-199}{10^{2011}}\)\(\text{Vì }\dfrac{-109}{10^{2011}}>\dfrac{-199}{10^{2011}}\text{ nên }A>B\)
Cac ban giup may.khong quy dong so sanh;A=-9/10^2010+-9/10^2011 va B=-9/10^2011+-19/10^2010
\(A=\frac{-9}{10^{2011}}+\frac{-9}{10^{2010}}\)
\(B=\frac{-9}{10^{2011}}+\frac{-19}{10^{2010}}\)
\(\frac{-9}{10^{2010}}>\frac{-19}{10^{2010}}\)
\(\Rightarrow\frac{-9}{10^{2011}}+\frac{-9}{10^{2010}}>\frac{-9}{10^{2011}}+\frac{-19}{10^{2010}}\)
\(\Rightarrow A>B\)
so sanh
\(\frac{-2015}{2016}va\frac{-2016}{2017}\)(khong quy dong mau so)
Ta có:
\(\frac{-2015}{2016}=-1+\frac{1}{2016}\)
\(\frac{-2016}{2017}=-1+\frac{1}{2017}\)
Vì \(\frac{1}{2016}>\frac{1}{2017}\) nên \(-1+\frac{1}{2016}>-1+\frac{1}{2017}\)
\(\Rightarrow\frac{-2015}{2016}>\frac{-2016}{2017}\)
khong quy dong hay so sanh
A=-9/102010+-19/102011 ; B-9/102011+ -19/102010