25 - x / 56 = 6/16

( 25 - x ) : 56 = 6/16

25 - x = 6/16 x 56

25 - x = 21

      x = 25 - 21

      x = 4

\(\frac{25-x}{56}=\frac{6}{16}\)

\(\frac{x}{56}=25-\frac{6}{16}\)

\(\frac{x}{56}=24\frac{5}{8}\)

\(\frac{x}{56}=24\frac{35}{56}\)

\(\frac{x}{56}=\frac{24\cdot56+35}{56}\)

\(\frac{x}{56}=\frac{1379}{56}\)

Vậy số cần tìm là  \(1379\)

25-X= 6x56:16

25-X=21

    X=25-21

    X=4
K cho mình nhé, ai có facebook thì kb với mình luôn nha <3
 

\(\left(x-2011\right)\left(\frac{1}{12}+\frac{1}{20}+\frac{1}{30}+\frac{1}{42}+\frac{1}{56}+\frac{1}{72}\right)=\frac{16}{9}\)

\(\left(x-2011\right)\cdot\frac{2}{9}=\frac{16}{9}\)

\(x-2011=8\)

\(x=2019\)

\(\frac{x-2011}{12}+\frac{x-2011}{20}+\frac{x-2011}{30}+\frac{x-2011}{42}+\frac{x-2011}{56}+\frac{x-2011}{72}=\frac{16}{9}\)

\(\left(x-2011\right)\left(\frac{1}{12}+\frac{1}{20}+\frac{1}{30}+\frac{1}{42}+\frac{1}{56}+\frac{1}{72}\right)=\frac{16}{9}\)

\(\left(x-2011\right)\left(\frac{1}{3.4}+\frac{1}{4.5}+\frac{1}{5.6}+\frac{1}{6.7}+\frac{1}{7.8}+\frac{1}{8.9}\right)=\frac{16}{9}\)

\(\left(x-2011\right)\left(\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+...+\frac{1}{8}-\frac{1}{9}\right)=\frac{16}{9}\)

\(\left(x-2011\right)\left(\frac{1}{3}-\frac{1}{9}\right)=\frac{16}{9}\)

\(\left(x-2011\right)\frac{2}{9}=\frac{16}{9}\)

\(x-2011=8\Rightarrow x=2019\)

\(\frac{25-x}{56}=\frac{6}{16}\)

\(\frac{25-x}{56}=\frac{3}{8}\)

\(\frac{25-x}{56}=\frac{21}{56}\)

\(\Rightarrow25-x=21\)

\(\Rightarrow x=25-21\)

\(\Rightarrow x=4\)

Vậy x=4

=>(25-x)16=6x56=280

25-x=17.5

x=7.5=15/2

vậy x=15/2

ta giản ước : 6/16 = 3/8 như vậy, ta có :

\(\frac{25-x}{56}=\frac{3}{8}\)

quy đồng 2 phân số cho nhau : ( mẫu số chung ) = 56

ta có : 56 : 8 = 7

\(\frac{3x7}{8x7}=\frac{21}{56}\)

bây giờ, bài toán sẽ như sau :

\(\frac{25-x}{56}=\frac{21}{56}\)

vậy, x = 25 - 21 = 4

k mk nha

chúc bạn học giỏi

Theo đề ta có: \(\frac{25-x}{56}=\frac{6}{16}\)

Ta rút gọn: \(\frac{25-x}{56}=\frac{3}{8}\)

\(\Leftrightarrow\)25 -x . 8 = 56 . 3

\(\Rightarrow\)25 - x . 8 = 168​

\(\Rightarrow\)25 - x      = 168 : 8​

\(\Rightarrow\)25 - x      = 21

\(\Rightarrow\)     - x     = 21 - 25

\(\Rightarrow\)     - x     =  -4

\(\Rightarrow\)       x = 4

Vậy x = 4.

đây là toán lớp 6 nè

lớp 5 mà

\(\frac{25-x}{56}=\frac{6}{16}\)

\(\Rightarrow\frac{25-x}{56}=\frac{3}{8}\)

\(\Rightarrow\left(25-x\right).8=56.3\)

\(\Rightarrow25.8-8x=168\)

\(\Rightarrow200-8x=168\)

\(\Rightarrow8x=200-168\)

\(\Rightarrow8x=32\)

\(\Rightarrow x=32:8\)

\(\Rightarrow x=4\)

Tham khảo nha !!! 

Cách này dễ hơn nèk : 

\(\frac{25-x}{56}=\frac{6}{16}\)

\(\Leftrightarrow\)\(\frac{25-x}{56}=\frac{3}{8}\)

\(\Leftrightarrow\)\(\frac{25-x}{56}=\frac{21}{56}\)

\(\Leftrightarrow\)\(25-x=21\)

\(\Leftrightarrow\)\(x=25-21\)

\(\Leftrightarrow\)\(x=4\)

Vậy \(x=4\)

Chúc bạn học tốt ~ 

Nhân chéo là ra mà

56 x 6 = 25 - X x16

=56 x 6 : 16 = 21

25 - 21 = 4

Vậy X bằng 4

\(\frac{8}{23}\cdot\frac{46}{24}-x=\frac{1}{3}\)

=> \(\frac{2}{3}-x=\frac{1}{3}\)

=> \(x=\frac{1}{3}\)

\(\frac{10}{12}\div x=\frac{28}{9}\cdot\frac{3}{56}\)

=> \(\frac{10}{12}\div x=\frac{1}{6}\)

=> \(x=\frac{60}{12}=5\)

\(\frac{x-12}{4}=\frac{1}{2}\)

=> \(\left(x-12\right)\cdot2=4\cdot1\)

=> \(2x-24=4\)

=> \(2x=28\)

=> \(x=14\)

x=291

x=21

x.84=252.97

x=24444:84

x=291

x.24=9.56

x=504:24

x=21

k nha

1/ x=291

2/ x=21

CHÚC BẠN HỌC GIỎI

TK MÌNH NHÉ

\(\frac{x-3}{2013}+\frac{x-4}{2012}=\frac{x-5}{2011}+\frac{x-6}{2010}\)

\(\Leftrightarrow\frac{x-3-2013}{2013}+\frac{x-2-2012}{2012}=\frac{x-5-2011}{2011}+\frac{x-6-2010}{2010}\)(mỗi vế trừ đi 2)

\(\Leftrightarrow\frac{x-2016}{2013}+\frac{x-2016}{2012}-\frac{x-2016}{2011}-\frac{x-2016}{2010}=0\)

\(\Leftrightarrow\left(x-2016\right)\left(\frac{1}{2013}+\frac{1}{2012}-\frac{1}{2011}-\frac{1}{2010}\right)=0\)

Mà \(\frac{1}{2013}+\frac{1}{2012}-\frac{1}{2011}-\frac{1}{2010}\ne0\)

\(\Rightarrow x-2016=0\Leftrightarrow x=2016\)

Cộng mỗi vế cho 1 

Ta có: \(\frac{x-3-2013}{2013}+\frac{x-4-2012}{2012}=\frac{x-5-2011}{2011}+\frac{x-6-2010}{2010}\)

\(=>\left(\frac{x-2016}{2013}+\frac{x-2016}{2012}\right)-\left(\frac{x-2016}{2011}+\frac{x-2016}{2010}\right)=0\)

\(=>\left(x-2016\right).\left(\frac{1}{2013}+\frac{1}{2012}+\frac{1}{2011}+\frac{1}{2010}\right)\)

Mà \(\frac{1}{2013}+\frac{1}{2012}+\frac{1}{2011}+\frac{1}{2010}\ne0\)

\(=>x-2016=0\\ =>x=2016\)