giải giúp với 35 – 3(x + 2) = 5
Bài 2. Tìm x, biết:
1) 48 - 3(x + 5) = 24 2) 2x - 20 = 35 : 33 | 3) 1230 : 3(x - 20) = 10 4) 390 - (x - 7) = 169 :13 |
giải giúp em với ạ
35 - 3|x| = 5.(2^3-4)
Giải giúp mk nha
\(35-3\left|x\right|==5.\left(2^3-4\right)\)
\(35-3\left|x\right|=5.4\)
\(35-3\left|x\right|=20\)
\(3\left|x\right|=35-20\)
\(3\left|x\right|=15\)
\(\left|x\right|=5\)
\(\Rightarrow\orbr{\begin{cases}x=5\\x=-5\end{cases}}\)
vậy \(\orbr{\begin{cases}x=5\\x=-5\end{cases}}\)
học vui Trần Diệp Anh
35 - 3|x| = 5.(2^3-4) .
35 - 3|x| = 5.4 .
35 - 3|x| = 20 .
3|x| = 35 - 20 .
3|x| = 15 .
|x| = 15 : 3 .
|x| = 5 .
Nên x = 5 hoặc x = -5 .
35 - 3 |x| = 5 * ( 2^3 - 4 )
=> 35 - |x| = 5 * ( 8 - 4 )
=> 35 - 3 |x| = 5 * 4
=> 3 |x| = 35 - 20
=> |x| = 15 / 3
=> |x| = 5
=> x = 5 hoặc x = -5
2/3 = 2 x 4/ 3 x 4 =......../.........
8/14 = 8 : 2/ 8 : 2/ 14 : 2 =........./..........
5/9 = 5 x......./ 9 x 3 =......../.........
35/ 40 = 35 : 5/ 40 : ............. =......./...........
giúp mình với trả lời mình tick cho nhé
2/3 = 2 x 4/ 3 x 4 =8/12
8/14 = 8 : 2/ 14 : 2 =4/7
5/9 = 5 x3/ 9 x 3 =15/37
35/ 40 = 35 : 5/ 40 : 5=7/8
a)(\(\dfrac{31}{35}\)-\(\dfrac{4}{7}\)) x \(\dfrac{8}{7}\) : 2
b)(1 - \(\dfrac{1}{2}\)) x ( 1- \(\dfrac{1}{3}\)) x (1-\(\dfrac{1}{4}\)) x ( 1-\(\dfrac{1}{5}\))
nhanh giúp mik với!!
lời giải chi tiết ạ!!!
\(a,\left(\dfrac{31}{35}-\dfrac{4}{7}\right)\times\dfrac{8}{7}:2\\ =\left(\dfrac{31}{35}-\dfrac{4\times5}{35}\right)\times\dfrac{8}{7}:2\\ =\dfrac{11}{35}\times\dfrac{8}{7}:2\\ =\dfrac{88}{245}:2\\ =\dfrac{44}{245}\\ b,\left(1-\dfrac{1}{2}\right)\times\left(1-\dfrac{1}{3}\right)\times\left(1-\dfrac{1}{4}\right)\times\left(1-\dfrac{1}{5}\right)\\ =\left(\dfrac{2-1}{2}\right)\times\left(\dfrac{3-1}{3}\right)\times\left(\dfrac{4-1}{4}\right)\times\left(\dfrac{5-1}{5}\right)\\ =\dfrac{1}{2}\times\dfrac{2}{3}\times\dfrac{3}{4}\times\dfrac{4}{5}\\ =\dfrac{1}{3}\times\dfrac{3}{4}\times\dfrac{4}{5}\\ =\dfrac{1}{4}\times\dfrac{4}{5}=\dfrac{1}{5}\)
a, ( \(\dfrac{31}{35}\) - \(\dfrac{4}{7}\)) \(\times\) \(\dfrac{8}{7}\): 2
= \(\left(\dfrac{31}{35}-\dfrac{20}{35}\right)\) \(\times\) \(\dfrac{8}{7}\) : 2
= \(\dfrac{11}{35}\) \(\times\) \(\dfrac{8}{7}\) \(\times\) \(\dfrac{1}{2}\)
= \(\dfrac{44}{35}\) \(\times\) \(\dfrac{4}{7}\)
= \(\dfrac{44}{245}\)
b, ( 1 - \(\dfrac{1}{2}\)) \(\times\) ( 1 - \(\dfrac{1}{3}\)) \(\times\) ( 1 - \(\dfrac{1}{4}\)) \(\times\) ( 1 - \(\dfrac{1}{5}\))
= \(\dfrac{1}{2}\) \(\times\) \(\dfrac{2}{3}\) \(\times\) \(\dfrac{3}{4}\) \(\times\) \(\dfrac{4}{5}\)
= \(\dfrac{1}{5}\) \(\times\) \(\dfrac{2\times3\times4}{2\times3\times4}\)
= \(\dfrac{1}{5}\)
5/9:3/x+2=5/3.
3/7+x/35=4/5
giúp mình với. Thank you
5/9 : 3/x+2 = 5/3 ( Câu này mình để x + 2 dưới mẫu nhé còn nếu tách chuyển vế âm lớp 4 chưa học ! )
<=> 3/x+2 = 5/9 : 5/3
<=> 3/x+2 = 1/3
<=> x + 2 = 9 <=> x = 7
3/7 + x/35 = 4/5
<=> x/35 = 4/5 - 3/7 = 13/35
<=> x = 13
<=>15/35 + x/35=28/35
<=>28/35-15/35=x/35
<=>8/35=x/35
<=>8
a) 165-(35:x+3)*15=15
b) (1*3/10-x):(19/10-1-2/5)+4/5=1
giúp mk giải câu này nhé!!!
a) => (35:x+3)*15 = 165-15=150
=> 35:x+3 = 150:15=10
=> 35:x = 10-3 = 7
=> x = 35:7 = 5
b) => 1*3/10x :1/2 +4/5 =1
=> 1*3/10x:1/2 =1-4/5=1/5
=> 1*3/10x = 1/5 *1/2 =1/10
=> 3/10-x = 1/10
=> x = 3/10 - 1/10 = 2/10 = 1/5
Giúp mình nha
A) 320:x-10=50×4,8-24
B) 12/35 : ( 3/2 - x ) = 3/5
Nhớ giải ra giúp mình nha :)
13/14+13/35+13/65+13/104+...+13/1274-x+2 1/5=0
các bạn giải giúp mình với
Bạn nào giúp mik giải bài toán này với:
* ( 3/10 - 4/15 - 7/20 ) x 5/19 tất cả trên ( 1/14 + 1/7 - âm 3/35 ) x âm 4/3
*( 1+2+3+...+100) x (1/3 -1/5 -1/7 -1/9) x (6,3 x 12 - 21 x 3,6) tất cả trên 1/2 + 1/3 + 1/4 +....+1/100
*\(\frac{\left(\frac{3}{10}-\frac{4}{15}-\frac{7}{20}\right).\frac{5}{19}}{\left[\frac{1}{14}+\frac{1}{7}-\left(-\frac{3}{35}\right)\right].\frac{4}{3}}=\frac{\left(\frac{18}{60}-\frac{16}{60}-\frac{21}{60}\right).\frac{5}{19}}{\left(\frac{5}{70}+\frac{10}{70}+\frac{6}{70}\right).\frac{4}{3}}=\frac{\frac{-19}{60}.\frac{5}{19}}{\frac{21}{70}.\frac{4}{3}}=\frac{\frac{-1}{12}}{\frac{14}{35}}=-\frac{1}{12}.\frac{35}{14}=\frac{-35}{168}\)
*\(\frac{\left(1+2+3+...+100\right).\left(\frac{1}{3}-\frac{1}{5}-\frac{1}{7}-\frac{1}{9}\right).\left(6,3.12-21.3,6\right)}{\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{100}}\)
=\(\frac{\left(1+2+3+...+100\right)\left(\frac{1}{3}-\frac{1}{5}-\frac{1}{7}-\frac{1}{9}\right).\left(\frac{63}{10}.12-21.\frac{18}{5}\right)}{\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{100}}\)
=\(\frac{\left(1+2+3+...+100\right)\left(\frac{1}{3}-\frac{1}{5}-\frac{1}{7}-\frac{1}{9}\right).\left(\frac{378}{5}-\frac{378}{5}\right)}{\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{100}}\)
=\(\frac{\left(1+2+3+...+100\right)\left(\frac{1}{3}-\frac{1}{5}-\frac{1}{7}-\frac{1}{9}\right).0}{\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{100}}=0\)