\(x^3-4x^2+12x-27\)

\(=x^3-3x^2-x^2+3x+9x-27\)

\(=x^2\left(x-3\right)-x\left(x-3\right)+9\left(x-3\right)\)

\(=\left(x-3\right)\left(x^2-x+9\right)\)

tu de bai suy ra: 3x(x^3+4x+4)=3x(x+2)^2

3x^3+12x^2+12x=3x(x^2+4x+4)=3x(x+4)^2

cái này dễ mà

= (2x)^3-3(2x)^2*1+2*3x*1^2-1^3

= (2x-1)^3

\(16y^2-4x^2-12x-9=16y^2-\left(4x^2+12x+9\right)=\left(4y\right)^2-\left(2x+3\right)^2\)\(=\left[4y-\left(2x+3\right)\right]\left(4y+2x+3\right)=\left(4y-2x-3\right)\left(4y+2x+3\right)\)

bạn đăng ít  thôi dc ko

đăng ít thôi thế này ai làm đc

A,          m²-7m+12=m²-3m+12-4m=m(m-3)-4(m-3)=(m-4)(m-3)

B,           2x⁴-x³+27-54x=x³(2-x)-27(2-x)=(x³-27)(2-x)=(x-3)(x²+3x+9)(2-x)

a) m^2 -7m +12 = m^2 -3m -4m +12

=m(m -3)-4 (m- 3)

=(m-4)(m-3)

b) 2x^4-x^3 -54x+ 27

=(2m^4-x^3)- (54x - 27)

=x^3(2x-1)-27(2x-1)

=(x^3-27)(2x-1)

a,(m-4)(m-3)

b,(x-3)(2x-1)(x^2-3x+9)

\(=6x^2+5x-3xy\)

\(=x\left(6x+5-3y\right)\)

x⁸+64

=(x⁴)²+16x⁴+8²-16x⁴

=(x⁴+8)²-(4x²)²

=(x⁴+8-4x²)(x⁴+8+4x²)