4. C

6. B

c

b

c

b

0,35A=350mA
0,5V=500mV
6kV=6000V

0,35A=350mA
0,5V=500mV
6kV=6000V

bấm máy bạn ơi

0,8x 1 +3/4 -7/6 +0,25

=0,8  +3/4 -7/6+1/4

=4/5 +3/4-7/6+1/4

=(3/4 + 1/4) +4/5 - 7/6

=1+4/5 - 7/6

=9/5-7/6

=19/30

                                                                                         Bài Làm

1) 0,8 x 1 = 0,8

2) \(\frac{3}{4}-\frac{7}{6}+0,25=-\frac{1}{6}\)

Chúc bạn học tốt có j cần tư vấn cứ nói mình

( 2x + 3 ) ³ = -125

( 2x + 3 ) ³ = ( -5 ) ³

=> 2x + 3 = -5

     2 x      = -8

        x      = -4

( x + 1 / 4 ) ⁴ = 625 / 256

( x + 1 / 4 ) ⁴ = ( 5 / 4 ) ⁴

=> x + 1 / 4  = 5/4

     x             = 4 / 4

     x             = 1

cảm ơn bạn

`3/4-(2/3+3/4)+2/3+2022/2023`

`=3/4 - 2/3 - 3/4 +2/3 +2022/2023`

`= (3/4 -3/4 ) + (-2/3 +2/3) +2022/2023`

`= 0+0+2022/2023`

`=2022/2023`

\(\dfrac{3}{4}-\left(\dfrac{2}{3}+\dfrac{3}{4}\right)+\dfrac{2}{3}+\dfrac{2022}{2023}\)

\(=\dfrac{3}{4}-\left(\dfrac{8}{12}+\dfrac{9}{12}\right)+\dfrac{2}{3}+\dfrac{2022}{2023}\)

\(=\dfrac{3}{4}-\dfrac{17}{12}+\dfrac{2}{3}+\dfrac{2022}{2023}\)

\(=\dfrac{9}{12}-\dfrac{17}{12}+\dfrac{8}{12}+\dfrac{2022}{2023}\)

\(=\dfrac{9-17+8}{12}+\dfrac{2022}{2023}=\dfrac{0}{12}+\dfrac{2022}{2023}=0+\dfrac{2022}{2023}\)

\(=\dfrac{2022}{2023}\)

#YTVA