3/10 / 2/5
4/7 / 3/11
25 / 0.1
25 * 10
11 / 0.25
11 * 4
48 / 0.01
48 * 100
32 / 0.5
32 * 2
95 / 0.1
72 / 0.01
75 / 0.5
125 / 0.25
Tinh bang hai cach
7/11 / 3/5 + 4/11 / 3/5
(6.24+1.26)/ 0.75
a) 1125- ( 374+1125) + (-65 + 374) = ? 13-12+11+10-9+8-7-6+5-4+3+2-1 = ? Giải các bước giúp mình nhé Mình cảm ơn
1500 - {5^3 . 2^3 - 11. [(7^1011)^2 : 7^2020 - 6 . 2^3 + 8. (11^2 - 121)]}
a)58.75+58.50-58.25
b) 20:2^2-5^9:5^8
c.(5^19:5^17-4):7
d)_84:4+3^9:3^7+5^0
e)295-(31-2^2.5)^2
f) 11^25 :11^23 -3^5:(1^10)+2^3-60)
a) 58.75+58.50-58.25
=58.(75+50-25)
=58.100
=5800
b) \(20:2^2-5^9:5^8\)
\(20:4-5\)
\(5-5=0\)
c)\(\left(5^{19}:5^{17}-4\right):7\)
\(\left(5^2-4\right):7\)
\(\left(25-4\right):7\)
\(21:7\)
=\(3\)
d) \(84:4+3^9:3^7+5^0\)
\(=21+3^2+1\)
\(=21+9+1\)
\(30+1=31\)
e) \(295-\left(31-2^2.5\right)^2\)
\(295-\left(31-4.5\right)^2\)
\(295-\left(31-20\right)^2\)
\(295-\left(11\right)^2\)
\(295-121\)
\(=174\)
f) \(11^{25}:11^{23}-3^5:\left(1^{10}\right)+2^3-60\)
\(11^2-243:1+8-60\)
\(121-243+8-60\)
\(-122+8-60\)
\(-114-60\)
\(=-174\)
a) 1125-(374+1125)+(-65+374)
b)-23.65+23.21-58.23
c)-2003+(-21+75+2003)
d)942-2567+2563-1942
e)12-12+11+10-9_8-7+5-4+3+-1
a) 1125-(374+1125)+(-65+374)
= 1125 - 374 - 1125 - 65 + 374
= (-1125 + 1125)+(-374+374) - 65
= -65
b)-23.65+23.21-58.23
=23.(-65+21-23)
= 23.(-67)= -1541
c)-2003+(-21+75+2003)
= -2003 + 2057 = 54
d)942-2567+2563-1942
= -1625 + 621 = -1004
e)12-12+11+10-9_8-7+5-4+3+-1
= 0
a) 1125-(374+1125)+(-65+374)\
b)-23.65+23.21-58.23
c)-2003+(-21+75+2003)
d)942-2567+2563-1942
e)12-12+11+10-9_8-7+5-4+3+-1
a, -65
b, -2277
c, 54
d,-1004
e,0
mk nhanh nhất k mk nhé Vu duc manh
a) 1125 - ( 374 + 1125 ) + ( - 65 + 374 )
= 1125 - 374 - 1125 - 65 + 374
= ( - 1125 + 1125 ) + ( - 374 + 374 ) - 65
= - 65
b) - 23 . 65 + 23 . 21 - 58 . 23
= 23 . ( - 65 + 21 - 23 )
= 23 . ( - 67 )
= - 1541
c) - 2003 + ( - 21 + 75+ 2003 )
= - 2003 + 2057
= 54
d) 942 - 2567 + 2563 - 1942
= - 1625 + 621
= - 1004
e) 12 - 12 + 11 + 10 - 9 _ 8- 7 + 5 - 4 + 3 + -1
= 0
Bài 2(2 điểm): Tính hợp lý (nếu có thể):
a) 1125 – ( 374 + 1125) + (-65 +374)
b) -23 . 63 + 23 . 21 – 58 . 23
c) -2003 + (-21+75 + 2003)
d) 942 – 2567 + 2563 – 1942
e) 12 - 12 + 11 + 10 - 9 + 8 - 7 + 5 - 4 + 3 + 2 -1
tinh bang hai cach
(6/11+5/11) * 3/7
(6/7-4/7) : 2/5
3/5 * 7/9 - 3/5 *2/9
8/15 : 2/11 + 7/15 :2/11
a ,b
cách 1 : cộng 2 số trong ngặc rồi tính bình thường
cách 2 : nhân phân phối ra rồi tính nhân chia trước cộng trừ sau
c,d
cách 1 : tính bình thường, nhân chia trc cộng trừ sau
cách 2 : đặt nhân tử ( thừa số ) chung
Cách 1 : \((\frac{6}{11}+\frac{5}{11})\cdot\frac{3}{7}=1\cdot\frac{3}{7}=\frac{3}{7}\)
Cách 2 : \(\frac{6}{11}\cdot\frac{3}{7}+\frac{5}{11}\cdot\frac{3}{7}=\frac{18}{77}+\frac{15}{77}=\frac{33}{77}=\frac{3}{7}\)
Cách 1 dễ rồi nha
Cách 2 : \(\frac{6}{7}:\frac{2}{5}-\frac{4}{7}:\frac{2}{5}=\frac{15}{7}-\frac{10}{7}=\frac{5}{7}\)
Cách 1 tự làm
Cách 2 : \(\frac{3}{5}\cdot(\frac{7}{9}-\frac{2}{9})=\frac{3}{5}\cdot\frac{5}{9}=\frac{1}{3}\)
Cách 1 : ...
Cách 2 : \((\frac{8}{15}+\frac{7}{15}):\frac{2}{11}=1:\frac{2}{11}=\frac{2}{11\cdot1}=\frac{2}{11}\)
A=[(3/11+1-3/7)/(3+9/11-9/7)]-[(1/3+0.25-1/5+0.125)/(7/6+7/8-0.7+7/16)]
B=1/3+1/6*(1+2)+1/9(1+2+3)+...+1/6045*(1+2+3+..+2015)
giúp vs cần gấp
Tính hợp lý nếu có thể:
a) 1125-(374+1125) +(-65+374)
b) -23. 63+23. 21- 58. 23
c)-2003 +(-21+75+2003)
d)942-2567+2563-1942
e)12-12+11+10-9+8-7+5-4+3+2-1
a) 1125 - (374 + 1125) + (-65 + 374)
= 1125 - 374 - 1125 + (-65) + 374
= (1125 - 1125) + (-374 + 374) + (-65)
= 0 + 0 + (-65)
= -65
b) -23. 63 + 23 . 21 - 58 . 23
= 23 .(-63) + 23 . 21 - 58 . 23
= 23 . [(-63) + 21 - 58]
= 23 . (-100)
= -2300
c) -2003 + (-21 + 75 + 2003)
= -2003 + (-21) + 75 + 2003
= (-2003 + 2003) + (-21) + 75
= 0 + 54
= 54
d) 942 - 2567 + 2563 - 1942
= (942 - 1942) + (-2567 + 2563)
= -1000 + (-4)
= -1004
e) 12 - 12 + 11 + 10 - 9 + 8 - 7 + 5 - 4 + 3 + 2 - 1
= 0 + 11 + 1 + 1 + 1 + 3 + 1
= 18
\(\frac{0.125-\frac{1}{5}+\frac{1}{7}}{0.375-\frac{3}{5}+\frac{3}{7}}+\frac{\frac{1}{2}+\frac{1}{3}-\frac{1}{5}}{\frac{3}{4}+\frac{1}{2}-\frac{3}{10}}\)
\(\frac{0,125-\frac{1}{5}+\frac{1}{7}}{0,375-\frac{3}{5}+\frac{3}{7}}+\frac{\frac{1}{2}+\frac{1}{3}-\frac{1}{5}}{\frac{3}{4}+\frac{1}{2}-\frac{3}{10}}\)
\(=\frac{0,125-\frac{1}{5}+\frac{1}{7}}{3\left(0,125-\frac{1}{5}+\frac{1}{7}\right)}+\frac{\frac{1}{2}+\frac{1}{3}-\frac{1}{5}}{\frac{3}{2}\left(\frac{1}{2}+\frac{1}{3}-\frac{1}{5}\right)}\)
\(=\frac{1}{3}+\frac{1}{\frac{3}{2}}\)
\(=\frac{1}{3}+\frac{2}{3}\)
\(=1\)