ta có A=\(\frac{20132013}{20142014}\)=\(\frac{2013.10001}{2014.10001}\)=\(\frac{2013}{2014}\)

B=\(\frac{131313}{141414}\)=\(\frac{13.10101}{14.10101}\)=\(\frac{13}{14}\)

xét 1-\(\frac{2013}{2014}\)=\(\frac{1}{2014}\);1-\(\frac{13}{14}\)=\(\frac{1}{14}\)

vì \(\frac{1}{2014}\)<\(\frac{1}{14}\) suy ra \(\frac{2013}{2014}\)>\(\frac{13}{14}\)suy ra A>B

Vậy ..................................

Ta có: 

\(A=\frac{20132013}{20142014}\)

\(A=\frac{20132013\div10001}{20142014\div10001}\)

\(A=\frac{2013}{2014}\)

và \(B=\frac{131313}{141414}\)

\(B=\frac{131313\div10101}{141414\div10101}\)

\(B=\frac{13}{14}\)

ta có: \(A=\frac{2013}{2014}=1-\frac{1}{2014}\)

và \(B=\frac{13}{14}=1-\frac{1}{14}\)

vì \(\frac{1}{14}>\frac{1}{2014}\)

Nên \(1-\frac{1}{14}< 1-\frac{1}{2014}\)

Hay A > B

\(A=\frac{2013.10001}{2014.10001}=\frac{2013}{2014}=1-\frac{1}{2014}\)A=(2013.10001)/(2014.10001)=2013/2014=1-1/2014

B=(13.10101)/(14.10101)=13/14=1-1/14

Ta thấy 1/14>1/2014 => 1-1/2014>1-1/14 => A>B

1/ Ta có : \(\frac{212121}{353535}=\frac{3.7.10101}{5.7.10101}=\frac{3}{5}=\frac{42}{70}\)

\(\frac{131313}{141414}=\frac{13.10101}{14.10101}=\frac{13}{14}=\frac{65}{70}\)

Vì 42 < 65 =>  \(\frac{42}{70}<\frac{65}{70}\)  =>  \(\frac{212121}{353535}<\frac{131313}{141414}\)

1)Ta có : 212121/353535 = 212121:10101/353535:10101 = 21/35 = 3/5

131313/141414 = 131313:10101/141414:10101 = 13/14

Ta có : 3/5 = 42/70 ; 13/14 = 65/70

Vì 42<65 => 42/70<65/70 => 212121/353535<131313/141414

2)Ta có : 2012/2013<1 

2013/2014<1

2014/2015<1

=> 2012/2013+ 2013/2014+ 2015/2012<1+1+1=3

Vậy 2012/2013+ 2013/2014+ 2015/2012<3

Ai chơi truy kích cấp cao thì kết bạn nha !!!!!!!!

212121/353535=21/35=3/5

131313/141414=13/14. 

b, 2012/2013<1; 2013/2014<1; 2014/2015<1 nên  2012/2013+2013/2014+ 2014/2015<3

\(a,\frac{20132013}{20142014}=\frac{2013.10001}{2014.10001}=\frac{2013}{2014}=1-\frac{1}{2014};\frac{131313}{141414}=\frac{13.10101}{14.10101}=\frac{13}{14}=1-\frac{1}{14}.\text{Vì: 14 bé hơn 2014 nên:}\frac{1}{14}>\frac{1}{2014}\Rightarrow\frac{20132013}{20142014}>\frac{131313}{141414}\)

\(C=2013^9+2013^9.2013=2013^9\left(2013+1\right)=2013^9.2014;D=2014^9.2014\text{ vì: 2013^9< 2014^9 nên: C bé thua D }\)

\(c,M=\frac{-7}{10^{2005}}+\frac{-15}{10^{2006}}=\frac{-7}{10^{2005}}+\frac{-7}{10^{2006}}+\frac{-8}{10^{2006}};N=\frac{-7}{10^{2005}}+\frac{-7}{10^{2006}}+\frac{-8}{10^{2005}}.Vì:10^{2006}>10^{2005}.Nên:\frac{-8}{10^{2006}}>\frac{-8}{10^{2005}}\Rightarrow M>N\)

\(\frac{3}{5}>\frac{4}{9}\)

\(\frac{13}{14}=\frac{131313}{141414}\)

\(91.\frac{99}{95}.95>1\)

\(35.\frac{35}{33}.37>1\)

hoa mắt quá, mk đang tính

kết quả = 1/13 đúng ko bn, k mk nha ( nếu đúng )