tìm các số nguyên x thoả mãn:
5/1.6+5/6.11+...+5/(5x+1)(5x+6)=2010/2011
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Tìm x biết 5/1.6+5/6.11+...+5/(5x+1)(5x+6)=2010/2011
Ta có:
\(\frac{5}{1.6}+\frac{5}{6.11}+...+\frac{5}{\left(5x+1\right).\left(5x+6\right)}\)
\(=1-\frac{1}{6}+\frac{1}{6}-\frac{1}{11}+...+\frac{1}{5x+1}-\frac{1}{5x+6}\)
\(=1-\frac{1}{5x+6}\)
\(=\frac{5x+5}{5x+6}=\frac{2010}{2011}\)
\(\Rightarrow5x+5=2010\)
\(\Rightarrow5x=2010-5=2005\)
\(\Rightarrow x=2005:5=401\)
Vậy x=401
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Tìm số tự nhiên x thỏa mãn:
a) 5/1.6 + 5/6.11 +...+ 5/(5x + 1).(5x + 6) = 2010/2011
b) 1/3.5 + 1/5.7 + 1/7.9 +...+ 1/(2x + 1).(2x + 3) = 15/93
Tìm số tự nhiên x thỏa mãn: 5/1.6 + 5/6.11 +...+ 5/(5x+1).(5x+6) =2010/2011. b) 1/3.5+1/5.7+.,.+ 1/(2x+1).(2x+3) =15/93.
1-1/6+1/6-1/11+....+1/(5x+1)-1/(5x+2)=2010/2011 <=>1-1/(5x+2)=2010/2011 <=>1/2011=1/(5x+2) <=>x=401
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=2/3.5+2/5.7+2/7.9+........+2/(2x+1).(2x+3)=15/93.2
=1/3-1/5+1/5-1/7+.........+1/(2x+1)-1/(2x+3)=30/93
=1/3-1/(2x+3)=30/93
=1/(2x+3)=1/3-30/93
1/(2x+3)=31/93-30/93
1/(2x+3)=1/93
(2x+3).1=1.93
2x+3=93
2x=93-3
2x=90
x=90:2
x=45
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tìm x,y thỏa mãn
a.\(\frac{5}{1.6}+\frac{5}{6.11}+...+\frac{5}{\left(5x+1\right).\left(5x+6\right)}=\frac{2010}{2011}\)
\(\frac{5}{1.6}+\frac{5}{6.11}+...+\frac{5}{\left(5x+1\right).\left(5x+6\right)}=\frac{2010}{2011}\)
\(\Rightarrow1-\frac{1}{6}+\frac{1}{6}-\frac{1}{11}+...+\frac{1}{5x+1}-\frac{1}{5x+6}=\frac{2010}{2011}\)
\(\Rightarrow1-\frac{1}{5x+6}=\frac{2010}{2011}\)
\(\Rightarrow\frac{1}{5x+6}=1-\frac{2010}{2011}\)
\(\Rightarrow\frac{1}{5x+6}=\frac{1}{2011}\)
\(\Rightarrow5x+6=2011\)
\(\Rightarrow5x=2011-6\)
\(\Rightarrow5x=2005\)
\(\Rightarrow x=401\)
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tìm x biết
5/1.6 + 5/6.11 + 5/11.16 + .... + 5/5x+1.5x+6 = 2010/2011
giải cụ thể nha
=> 1 - 1/6 + 1/6 - 1/11 +.......+1/5x+1 - 1/5x+6=2010/2011
=> 1 - 1/5x+6 = 2010/2011
=> 1/5x+6 = 1/2011
=> 5x + 6 = 2011
=> 5x = 2005
=> x = 401(tm)
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Tìm số nguyên x thỏa mãn :
1. -1/4 : -3/4 + 1/2 < x < 7/8 - 1/2 : -5/6
2. 5/1.6 + 5/6.11 +...+ 5/(5x+1).(5x+6)
Bạn nào trả lời nhanh và đúng nhất, trc 8h15 thì có thưởng 1 đúng nhé. Nhưng làm ơn nghiêm túc. Xin cảm ơn !
Tim x thuoc N biet 5/ 1.6 +5/ 6.11+....+5/ (5x+1).(5x+6)=2005/2006
\(\frac{5}{1.6}+\frac{5}{6.11}+...+\frac{5}{\left(5x+1\right).5x+6}=\frac{2005}{2006}\)
\(1-\frac{1}{6}+\frac{1}{6}-\frac{1}{11}+....+\frac{1}{5x+1}-\frac{1}{5x+6}=\frac{2005}{2006}\)
\(1-\frac{1}{5x+6}=\frac{2005}{2006}\)
\(\frac{1}{5x+6}=1-\frac{2005}{2006}\)
\(\frac{1}{5x+6}=\frac{1}{2006}\)
=>5x+6 = 2006
=>5x = 2000
=>x = 400
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Bài làm :
Ta có :
\(\frac{5}{1.6}+\frac{5}{6.11}+...+\frac{5}{\left(5x+1\right).\left(5x+6\right)}=\frac{2005}{2006}\)
\(\Leftrightarrow\frac{6-1}{1.6}+\frac{11-6}{6.11}+...+\frac{5x+6-5x-1}{\left(5x+1\right).\left(5x+6\right)}=\frac{2005}{2006}\)
\(\Leftrightarrow1-\frac{1}{6}+\frac{1}{6}-\frac{1}{11}+....+\frac{1}{5x+1}-\frac{1}{5x+6}=\frac{2005}{2006}\)
\(\Leftrightarrow1-\frac{1}{5x+6}=\frac{2005}{2006}\)
\(\Leftrightarrow\frac{1}{5x+6}=1-\frac{2005}{2006}\)
\(\Leftrightarrow\frac{1}{5x+6}=\frac{1}{2006}\)
\(\Leftrightarrow1.2006=\left(5x+6\right).1\)
\(\Leftrightarrow2006=5x+6\)
\(\Leftrightarrow5x=2006-6\)
\(\Leftrightarrow5x=2000\)
\(\Leftrightarrow x=2000\div5=400\)
Vậy x=400
Chúc bạn học tốt !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
tìm x
d) \(\frac{5}{1.6}+\frac{5}{6.11}+\frac{5}{11.16}+...+\frac{5}{\left(5x+1\right)\left(5x+6\right)}=\frac{2005}{2006}\)
1-1/6+1/6-1/11+...+1/5x+1-1/5x+6=2005/2006
1-1/5x+6=1-1/2006
5x+6=2006
5x=2000
x=400
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\(1-\frac{1}{5x+6}=\frac{2005}{2006}\Leftrightarrow5x+6=2006\Leftrightarrow x=400\)
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Timx
5/1.6+5/6.11+.........+5/(5x+1).(5x+6)=2005/2006
