The last digit of the product 2x4x6x.....x78 is ?
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The last digit of the product : 2x4x6x......x78 is?
The last digit of the product 2x4x6x.....x78 is ?
The last digit of the product 2x4x6x...x78 is ...........
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The last digit of the product 2x4x6x8x...x78 is
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1. How many integer numbers n such that n^2+3 is divisible by n-1?
2.Caculator A=4+2^2+2^3+...+2^20
3. The last digit of the value of A= 2x4x6x...x48 - 1x3x5x...x49
\(a,n^2+3⋮n-1\)
\(\Rightarrow n\left(n-1\right)+3+n⋮n-1\)
\(\Rightarrow n+3⋮n-1\)
\(\Rightarrow n-1+4⋮n-1\)
\(\Rightarrow4⋮n-1\)
...........You make the table, If i make the table, it will spent my times
That is answer:6 intergers
\(b,A=4+2^2+2^3+...+2^{20}\)
Put \(B=2^2+2^3+...+2^{20}\)
\(\Rightarrow2B=2^3+2^4+...+2^{21}\)
\(\Rightarrow2B-B=\left(2^3+2^4+...+2^{21}\right)-\left(2^2+2^3+...+2^{20}\right)\)\(\Rightarrow B=2^{21}-4\)
`\(\Rightarrow A=2^{21}-4+4=2^{21}\)
c,Consider the range of values
Put B=2.4.6.8...48
Because of B=2.4.6...10....48
=> The last digit of B is 0
Put C=1.3.5...49
Because of C= 1.3.5...49
=> The last digit of C is 5
=> B-C will have the last digit is 5
=> A have the last digit ís 5
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The last digit of the product 11x22x33x...x99 is .........
The last digit of the product is ..... ?
The last digit of the product: 1*3*5....*999 is
tất nhiên vì số lẻ nhan 5 có tận cùng là 5 rồi khỏi nói cũng bít bài này xàm quá!!!
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The last digit of the product 11x22x33x...x99 is
