A =9^9+1/9^10+1
B=10^9+1/10^10+1
so sanh a va b
cho A=10^7+1/10^8+1
B=10^8+1/10^9+1
so sanh A va B
các bạn giúp mình với nhanh lên nhé.Mình sẽ cho
Cac ban giup may.khong quy dong so sanh;A=-9/10^2010+-9/10^2011 va B=-9/10^2011+-19/10^2010
\(A=\frac{-9}{10^{2011}}+\frac{-9}{10^{2010}}\)
\(B=\frac{-9}{10^{2011}}+\frac{-19}{10^{2010}}\)
\(\frac{-9}{10^{2010}}>\frac{-19}{10^{2010}}\)
\(\Rightarrow\frac{-9}{10^{2011}}+\frac{-9}{10^{2010}}>\frac{-9}{10^{2011}}+\frac{-19}{10^{2010}}\)
\(\Rightarrow A>B\)
1so sanh cac phan so sau
a,2/3 va -1/4
b -7/10 va 7/-8
c 6/7 va 3/5
d -14/21 va 60/-72
e 16/9 va24/13
g 27/82 va 26/75
ko quy dong mau so hay so sanh: A=-9/10^2015+-19/10^2016 va -9/10^2016+-19/10^2015
So sanh A va B
A = 1 + 1/2 + 1/3 + 1/4 + 1/5 + 1/6 + 1/7 +1/8 + 1/9 +1/10
B = 23/10
Tính giúp em với ạ
so sanh A=9^10;B=8^9+7^9+.......+2^9+1^9
so sanh : 2001/2004 va 39/40
so sanh : A = 1/6 + 1/7 + 1/8 + 1/9 + 1/10 voi B = 1
\(A< \frac{1}{5}+\frac{1}{5}+\frac{1}{5}+\frac{1}{5}+\frac{1}{5}=\frac{5}{5}=1=B\)
a/
\(\frac{2001}{2004}=\frac{2004-3}{2004}=1-\frac{3}{2004}=1-\frac{1}{668}.\)
\(\frac{39}{40}=\frac{40-1}{40}=1-\frac{1}{40}\)
Ta có \(40< 668\Rightarrow\frac{1}{40}>\frac{1}{668}\Rightarrow1-\frac{1}{40}< 1-\frac{1}{668}\Rightarrow\frac{39}{40}< \frac{2001}{2004}\)
b/
\(A< \frac{1}{5}+\frac{1}{5}+\frac{1}{5}+\frac{1}{5}+\frac{1}{5}=1=B\)
bai 1: so sanh luy thua sau :
a, 2^100 va 1024^9
b, 125^80 va 20^118
c, 9^12 va 27^10
a)1024^9=(2^10)^9=2^90
2^100>2^90
b)125^80>20^118
c)9^12=(3^2)^12=3^24
27^10=(3^3)^10=3^30
3^24<3^30=9^12<27^10
tích nha
cho A=1/1*2+1/3*4+...+1/9*10 va B=1/6*10+1/7*9+1/8*8+1/9*7+1/10*6 tinh A/B