a; - \(\dfrac{10}{13}\) + \(\dfrac{5}{17}\) - \(\dfrac{3}{13}\) + \(\dfrac{12}{17}\) - \(\dfrac{11}{20}\)

= - (\(\dfrac{10}{13}\) + \(\dfrac{3}{13}\)) + (\(\dfrac{5}{17}\) + \(\dfrac{12}{17}\)) - \(\dfrac{11}{20}\)

= - 1 + 1  - \(\dfrac{11}{20}\)

=   0 - \(\dfrac{11}{20}\)

= - \(\dfrac{11}{20}\)

b; \(\dfrac{3}{4}\) + \(\dfrac{-5}{6}\) - \(\dfrac{11}{-12}\)

= \(\dfrac{9}{12}\) - \(\dfrac{10}{12}\) + \(\dfrac{11}{12}\)

= \(\dfrac{10}{12}\)

= \(\dfrac{5}{6}\)

c; [13.\(\dfrac{4}{9}\) + 2.\(\dfrac{1}{9}\)] - 3.\(\dfrac{4}{9}\)

= [\(\dfrac{52}{9}\) + \(\dfrac{2}{9}\)] - \(\dfrac{4}{3}\)

= \(\dfrac{54}{9}\) - \(\dfrac{4}{3}\)

= \(\dfrac{14}{3}\)

d; 1,25 : \(\dfrac{15}{20}\) + [25% - \(\dfrac{5}{6}\)] : 4.\(\dfrac{2}{3}\)

= 1,25  x \(\dfrac{20}{15}\) + [\(\dfrac{1}{4}\) - \(\dfrac{5}{6}\)] : 4.\(\dfrac{2}{3}\)

=  \(\dfrac{5}{3}\) - \(\dfrac{7}{12}\) : 4 x \(\dfrac{2}{3}\)

= \(\dfrac{5}{3}\) - \(\dfrac{7}{48}\).\(\dfrac{2}{3}\)

= \(\dfrac{5}{3}\) - \(\dfrac{7}{72}\)

= \(\dfrac{113}{72}\)

A) 1000000 - 107492 : 154 x 28 + 1000

= 1000000 - 19544 + 1000

= 981456

B) 8/15 + 4/7 + 14/30 + 12/21 + 5

= 15/7 + 5

= 50/7

C) 9/13 : 6/11 - 5/12 : 6/11

= 9/13 x 11/6 - 5/12 x 11/6

= (9/13 - 5/12) x 11/6

= 43/156 x 11/6

= 473/936

Bài 2

1) X x2 + X x 1/5 = 8/5 

X x (2 + 1/5 ) = 8/5

X x 11/5 = 8/5

X = 8/5 x 5/11

X = 8/11

2) X : 3/8 = 4/3 : 3/6 

X : 3/8 = 8/3

X = 8/3 x 3/8

X = 1

a) 1 000 000 - 107 492 : 154 x 28 + 1000

=  1 000 000 -            698     x 28 + 1000

=  1 000 000 -                    19544 + 1000

=                    980 456                 + 1000

=                                       981 456

b) 8/15 + 4/7 + 14/30 + 12/21 + 5

  = ( 8/15 + 14/30 ) + ( 4/7 + 12/21 ) + 5

  = ( 16/30 + 14/30 ) + ( 12/21 + 12/21 ) + 5

  =            30/30      +          24/21         + 5

  =               1          +         24/21          + 5

  =           ( 1 + 5 ) + 24/21

  =                6      + 24/21

  =                     150/21

 =                         50/7        

a, \(\frac{-3}{7}+\frac{5}{13}-\frac{4}{7}+\frac{8}{13}\)

\(=\frac{-3}{7}-\frac{4}{7}+\frac{5}{13}+\frac{8}{13}\)

\(=-\frac{7}{7}+\frac{13}{13}=-1+1=0\)

b, \(\frac{-5}{14}-\frac{2}{-14}+\frac{1}{8}+\frac{1}{8}\)

\(=\frac{-5}{14}+\frac{2}{14}+\frac{1}{8}+\frac{1}{8}\)

\(=-\frac{3}{14}+\frac{1}{4}=\frac{1}{28}\)

c,\(-\frac{5}{13}-\left(\frac{3}{5}+\frac{3}{13}-\frac{4}{10}\right)\)

\(=-\frac{5}{13}-\frac{3}{13}-\frac{3}{5}+\frac{4}{10}\)

\(=-\frac{8}{13}-\frac{3}{5}+\frac{4}{10}=-\frac{79}{65}+\frac{4}{10}=-\frac{53}{65}\)

d, \(\left[\left(\frac{1}{8}-\frac{9}{7}+\frac{4}{6}-\frac{12}{7}-\frac{1}{2}\right)+\frac{5}{9}\right]\)

\(=\left[\left(\frac{1}{8}-\frac{9}{7}+\frac{2}{3}-\frac{12}{7}-\frac{1}{2}\right)+\frac{5}{9}\right]\)

\(=\left[\left(\frac{1}{8}-\frac{1}{2}-\frac{9}{7}-\frac{12}{7}+\frac{2}{3}\right)+\frac{5}{9}\right]\)

\(=-\frac{65}{24}+\frac{5}{9}=-2\frac{11}{72}\)

a)-3/7+5/13-4/7+8/13

=-3/7-4/7+5/13+8/13

=-7/7+13/13

=-1+1

=0

a)15/8+3/4-5/12

=45+18-10/24

=53/24

b)11/24.12/33+5/6

=11.12/12.2.11.3+5/6

=1/6+5/6

=6/6=1

c)15/8+7/24:5/8

=15/8+7/24.8/5

=15/8+7.8/3.8.5

=15/8+7/15

=đề sai, nếu đúng thì như này

=8/15+7/15

=15/15=1

hbhvgvvggvgbhhgvbnj

a.75-(3.5^2-4.2^3)

=75-(-5)

=80

b.-/-12/+12-(-24)

= - 12 + 12 - 24

=0-24

=-24

c.17.85+15.17-120

=17.(85+15)-120

=17.100-120

=1700-120

=1580

bài 2: tìm x

a. 70-5.(x-3)=45

5.(x-3)=70-45=25

x-3=25:5=5

x=5+3=8

vậy x=8

ai giup minh lam voi 

a) 100 - 7.(x-5) = 68

 7.(x - 5) = 100 - 68 = 32

    x - 5 = \(\frac{32}{7}\)

     x = \(\frac{32}{7}+5=\frac{67}{7}\)

b) 2(x-6)+2227:17=151

2( x -6) + 131 = 151

2 (x - 6) = 20

x - 6 = 20 : 2 = 10

x = 10 + 6 = 16

a) 11

b) 16

c) 3

d) 5

e) 36

f) 54

g) 5

a)\(\dfrac{-6}{11}:\left(\dfrac{3}{5}.\dfrac{4}{11}\right)=\dfrac{-5}{2}\)

b)\(\dfrac{7}{12}+\dfrac{5}{12}:6-\dfrac{14}{30}=\dfrac{67}{370}\)

c)\(\left(\dfrac{4}{5}+\dfrac{1}{2}\right):\left(\dfrac{3}{13}-\dfrac{8}{13}\right)=-\dfrac{169}{50}\)

d)\(\left(\dfrac{2}{3}-\dfrac{1}{4}+\dfrac{5}{11}\right):\left(\dfrac{5}{12}+1-\dfrac{7}{11}\right)=\dfrac{115}{103}\)