AM, BN, CP la cac duong trung tuyen cua tam giac abc cmr (AB+AC+BC)<3/4AM+BN+CP
Cho tam giac ABC co AB=24cm,AC=30cm,BC=36cm.Cac duong trung tuyen AM va BN cat nhau tai G.Goi O la giao diem cua cac duong phan giac AD va BE.Tinh AE,EC,BD,DC,OG?
Cho tam giac ABC co 3 duong trung tuyen AM,BN,CP.Qua N ke duong thang song song voi PC cat BC tai F , duong thang qua F song song voi PN va duong thang qua B song song voi CP cat nhau tai D . Goi G la trong tam cua tam giac ABC .CMR : \(S_{ABG}=S_{GBC}=S_{GCA}\)
cho tam giac ABC co AM la trung tuyen. tren AM lay diem d sao cho M la trung diem cua AD.Tren BC lay diem K SAO CHO C la trung diem cua BK.
CMR: a,KM trung tuyen cua tam giac ADK
b, M la trong tam cua tam giac ADK
c, so sanh cac canh cua tam giac ABC voi dg trung tuyen cua tam giac ADK.
Cho tam giac Goi AM,BN ,CP la cac duong phan giac trong.tinh ti so dien tich tam giac MNP va dien tich tam giac ABC theo AB,AC,BC
Cho tam giac ABC co 3 duong cao AD,BE,CF dong quy tai H . M,M,P lan luot la cac diem doi xung cua H qua BC, AC va AB. Tinh AM/AD+BN/BE+CP/CF= ?
Tam giac ABC co AB=a,AC=b AD la duong phan giac,AM la duong trung tuyen,D la trung diem MN, N thuoc BC.Tinh BN/NC
Cho tam giac abc nhon. goi h la truc tam cua tam giac abc. biet ah=bc. tinh bac
cho tam giac abc vuong tai a co c =150 trung tuyen am. duong trung truc cua bc cat cac duong thang ab va ac tai n va p
tinh k=\(\frac{AP}{PC}\)
goi i la giao diem cua bp va nc so sanh ma va mi
ai giai dc tich 20 like
Cho tam giac ABC can tai A co AD la duong trung tuyen
a)Chung minh tam giac ABD= tam gaic ACD va AD vuong goc voi BC
b)Cho AB=10cm,BC=16cm. Tinh do dai AD va so sanh cac goc cua tam giac ABC.
c) Ve duong trung tuyen CF cua tam giac ABC cat AD tai M. Tinh do dai AM.
d) Ve DH vuong goc AC tai H, tren canh AC va canh DC lan luot lay hai diem E,K sao cho AE=AD va DK=DH. Chung minh: EK vuong goc voi BC
A,
xét \(\Delta ABD\)và \(\Delta ACD\)
CÓ \(\hept{\begin{cases}AB=AC\\chungAD\\BD=DC\end{cases}}\)
SUY RA \(\Delta ABD\)=\(\Delta ACD\) (C.C.C) (1)
=> \(\widehat{BDA}\)=\(\widehat{CDA}\)
MÀ \(\widehat{BDA}\)+\(\widehat{CDA}\)=180
=> \(\widehat{BDA}\)=\(\widehat{CDA}\)=90
B, (1) => BC=DC=1/2 BC=8
ÁP DỤNG ĐỊNH LÍ PITAGO TA CÓ
\(AB^2=AD^2+BD^2\)
=> AD^2=36
=>AD=6
cho tam giac ABC(AB<AC),duong cao AH,trung tuyen AM.Tren AH lay K sao cho BC la duong trung truc cua AK.Tren AM lay N sao cho AN=2AM.Chung minh tu giac BKNC la hinh thang can