53/18 nha 

=> 49/9 + x = ( 1. 63/4) + 133/18 = 833/36

=> x = 833/36 - 49/9 = 637/36

1-(49/9+x-133/18):63/4=0

<=>49/9+x-133/18=1

<=>49/9+x=151/18

<=>x=53/18

Do mình làm hơi tắt nên khi trình bày bạn nên làm đầy đủ nhé

Chúc bạn học tốt ^-^

Thanks nha 

1-(49/9+x-133/18)=0(mình ko viết 0 nhân 63/4 được)

49/9+x-133/18=1

49/9+x=1+133/18

49/9+x=151/18

         x=151/18-49/9

         x=53/18

a) \(\frac{1}{4}+\frac{1}{3}:2x=-5\)

\(\frac{1}{3}:2x=\frac{-21}{4}\)

\(2x=\frac{-4}{63}\)

\(x=\frac{2}{63}\)

b) \(\left(3x-\frac{1}{4}\right)\left(x+\frac{1}{2}\right)=0\)

\(\Rightarrow\orbr{\begin{cases}3x-\frac{1}{4}=0\\x+\frac{1}{2}=0\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=\frac{1}{12}\\x=\frac{-1}{2}\end{cases}}\)

Vậy.........

c) \(\left|x+\frac{1}{5}\right|-\frac{1}{2}=\frac{9}{10}\)

\(\left|x+\frac{1}{5}\right|=\frac{7}{5}\)

\(\Rightarrow\orbr{\begin{cases}x+\frac{1}{5}=\frac{7}{5}\\x+\frac{1}{5}=\frac{-7}{5}\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=\frac{6}{5}\\x=\frac{-8}{5}\end{cases}}\)

Vậy.........

Chứng minh rằng (9^2n+1994^93)chia heets cho 5

a) \(x\cdot\frac{1}{2}+x\cdot\frac{1}{4}+x\cdot\frac{1}{8}=\frac{21}{24}\)

\(x\cdot\left(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}\right)=\frac{7}{8}\)

\(x\cdot\frac{7}{8}=\frac{7}{8}\)

\(\Rightarrow x=\frac{7}{8}\div\frac{7}{8}=1\)

b) \(\left(x+4\right)+\left(x+9\right)+\left(x+14\right)+.....+\left(x+44\right)+\left(x+49\right)=1430\)

\(\left(x+x+x+....+x+x\right)+\left(4+9+14+...+44+49\right)=1430\)

\(10x+265=1430\)

\(10x=1430-265\)

\(10x=1165\)

\(\Rightarrow x=\frac{1165}{10}=116,5\)

c) \(x\cdot0,25-0,5=1\)

\(x\cdot0,25=1+0,5\)

\(x\cdot0,25=1,5\)

\(\Rightarrow x=1,5\div0,25=6\)