tinh gia tri bieu thuc 1.5 + 1.8 +2.1 + ............................+4.5 +4.8
Tinh bang cach thuan tien
4.5+1.8+2.1+...+4.5+4.8
tinh gia tri cua bieu thuc sau :
A=1/199-1/199.198-1/198.197-1/197.196-.............-1/3.2-1/2.1
Ta có : \(A=\dfrac{1}{199}-\dfrac{1}{199.198}-\dfrac{1}{198.197}-\dfrac{1}{197.196}-...-\dfrac{1}{3.2}-\dfrac{1}{2.1}\)
\(=\dfrac{1}{199}-\left(\dfrac{1}{199.198}+\dfrac{1}{198.197}+\dfrac{1}{197.196}+...+\dfrac{1}{3.2}+\dfrac{1}{2.1}\right)\)
\(=\dfrac{1}{199}-\left(\dfrac{1}{1.2}+\dfrac{1}{2.3}+...+\dfrac{1}{196.197}+\dfrac{1}{197.198}+\dfrac{1}{198.199}\right)\)
\(=\dfrac{1}{199}-\left(1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+...-\dfrac{1}{198}+\dfrac{1}{198}-\dfrac{1}{199}\right)\)
\(=\dfrac{1}{199}-\left(1-\dfrac{1}{199}\right)\)
\(=\dfrac{1}{199}-\dfrac{198}{199}=\dfrac{-197}{199}\)
~ Học tốt ~
gia tri cua b bieu thuc
C=/3b+7.2/+/a-2.1/
dat gia tri nho nhat la
GTNN CUA BIEU THUC |x-1.3|-4.8+|y-2.1|
Đặt \(A=\left|x-1,3\right|+\left|y-2,1\right|-4,8\)
Vì \(\left|x-1,3\right|\ge0\forall x;\left|y-2,1\right|\ge0\forall y\)
\(\Rightarrow A\ge-4,8\forall x;y\)
Dấu "=" xảy ra \(\Leftrightarrow\hept{\begin{cases}x-1,3=0\\y-2,1=0\end{cases}\Leftrightarrow\hept{\begin{cases}x=1,3\\y=2,1\end{cases}}}\)
Vậy Amin = -4,8 khi và chỉ khi x = 1,3; y = 2,1
A=/x-1,3/-4,8+/y-2.1
gia tri nho nhat cua bieu thuc
Tinh gia tri bieu thuc [m + n ]:p neu m=5,n=19 va p=3 .Vay gia tri bieu thuc la:
cho a R b =a*b/ a+b . Tinh gia tri bieu thuc cua : 13R7 - 12r4 . TINH gia tri cua bieu thuc tren ( 30 giay )
\(\frac{31}{20}\)đáp số đúng 1000000000000000000000000000000000000000000000000000% đó nha
h and kb nhé
cho x+y =1 . tinh gia tri cua bieu thuc A=x^3+y^3+3xy
chox-y=1. tinh gia tri cua bieu thuc B=x^3-y^3-3xy
cho x+y=1 . tinh gia tri cua bieu thuc C=x^3+y^3+3xy(x^2+y^2)+6x^2*y^2(x+y)
Câu 1: Ta có: A = \(x^3+y^3+3xy=x^3+y^3+3xy\times1=x^3+y^3+3xy\left(x+y\right)\)
\(=\left(x+y\right)^3=1^3=1\)
Câu 2: Ta có: \(B=x^3-y^3-3xy=\left(x-y\right)\left(x^2+xy+y^2\right)-3xy\)
\(=x^2+xy+y^2-3xy=x^2-2xy+y^2=\left(x-y\right)^2=1^2=1\)
Câu 3: Ta có: \(C=x^3+y^3+3xy\left(x^2+y^2\right)-6x^2.y^2\left(x+y\right)\)
\(=x^3+y^3+3xy\left(x^2+2xy+y^2-2xy\right)+6x^2y^2\)
\(=x^3+y^3+3xy\left(x+y\right)^2-3xy.2xy+6x^2y^2\)
\(=x^3+y^3+3xy.1-6x^2y^2+6x^2y^3\)
\(=x^3+y^3+3xy\left(x+y\right)=\left(x+y\right)^3=1^3=1\)
cho bieu thuc A=2,45*(a+64,36)-45
a tinh gia tri bieu thuc A khi a=35,64
b tim gia tri cua A de bieu thuc A =126,5
b. Neu A =126.5 thì 126.5=2.45 x (a+64.36) -45
= 2.45 x (a+64.36) 126.5 + 45
= 2.45 x (a+64.36) = 171.5
= a+64.36 = 171.5 : 24.5
a+64.36 = 70
a = 70 - 64.36
a = 5.64
a,thay a=35,64vào bthuc đã cho ta đc:
A= 2,45x(35,64 +64,36)-45=2,45x100-45=200
b,để A=126,5 thì 2,45x(a+64,36)-45=126,5
=>2,45a+157,682-45=126,5
=>2,45a=13,818
=>a=5,64
cistian ronaldo