Tìm x biết \(\frac{29}{30}\)-(\(\frac{13}{23}\)+x)=\(\frac{7}{69}\)
Tìm x biết:
a ) x+\(\frac{7}{12}=\frac{17}{18}-\frac{1}{9}\) b) \(\frac{29}{30}-\left(\frac{13}{23}+x\right)=\frac{7}{69}\)
\(\frac{29}{30}-\left(\frac{13}{23}+x\right)=\frac{7}{69}\)
13/23+x=29/30-7/69
13/23+x=199/230
x=199/230-13/23
x=3/10
\(\dfrac{29}{30}-\left(\dfrac{13}{23}+x\right)=\dfrac{7}{69}\)
\(\dfrac{13}{23}+x=\dfrac{29}{30}-\dfrac{7}{69}\)
\(\dfrac{13}{23}+x=\dfrac{2001}{2070}-\dfrac{210}{2070}\)
\(\dfrac{13}{23}+x=\dfrac{1791}{2070}\)
\(x=\dfrac{1791}{2070}-\dfrac{13}{23}\)
\(x=\dfrac{1791}{2070}-\dfrac{1170}{2070}\)
\(x=\dfrac{621}{2070}=\dfrac{3}{10}\)
\(\dfrac{29}{30}-\left(\dfrac{13}{23}+x\right)=\dfrac{7}{69}\)
\(\dfrac{13}{23}+x=\dfrac{29}{30}-\dfrac{7}{69}\)
\(\dfrac{13}{23}+x=\dfrac{199}{230}\)
\(x=\dfrac{13}{23}-\dfrac{199}{230}\)
\(x=\dfrac{-3}{10}\)
Bài: Tìm x:
a) \(x+\frac{7}{12}=\frac{17}{18}-\frac{1}{9}\)
b) \(\frac{29}{30}-\left(\frac{13}{23}+x\right)=\frac{7}{69}\)
a) \(x+\frac{7}{12}=\frac{17}{18}-\frac{1}{9}\)
\(\Rightarrow x+\frac{7}{12}=\frac{5}{6}\)
\(\Rightarrow x=\frac{5}{6}-\frac{7}{12}\)
\(\Rightarrow x=\frac{1}{4}\)
b) \(\frac{29}{30}-\left(\frac{13}{23}+x\right)=\frac{7}{69}\)
\(\Rightarrow\frac{13}{23}+x=\frac{29}{30}-\frac{7}{69}\)
\(\Rightarrow\frac{13}{23}+x=\frac{199}{230}\)
\(\Rightarrow x=\frac{199}{230}-\frac{13}{23}\)
\(\Rightarrow x=\frac{3}{10}\)
a)\(x+\frac{7}{12}=\frac{17}{18}-\frac{1}{9}\)
\(x+\frac{7}{12}=\frac{5}{6}\)
\(x=\frac{5}{6}-\frac{7}{12}\)
\(x=\frac{1}{4}\)
b)\(\frac{29}{30}-\left(\frac{13}{23}+x\right)=\frac{7}{69}\)
\(\left(\frac{13}{23}+x\right)=\frac{29}{30}-\frac{7}{69}\)
\(\left(\frac{13}{23}+x\right)=\frac{199}{230}\)\(x=\frac{199}{230}-\frac{13}{23}\)
\(x=\frac{3}{10}\)
a.X+7/12=17/18-1/9
X+7/12=15/18
X=15/18-7/12
X=1/4
b.29/30-(13/23+X)=7/69
13/23+X=7/69+29/30
13/23+X=737/690
X=737/690-13/23
X=377/690
tìm x biết
\(\frac{x}{3}\)-\(\frac{3}{4}\)=\(\frac{1}{12}\)
\(\frac{29}{30}\)- (\(\frac{13}{23}\)+x) =\(\frac{7}{69}\)
bài 2 tính
\(\frac{1}{30}+\frac{1}{42}+\frac{1}{56}+\frac{1}{72}+\frac{1}{90}+\frac{1}{110}\)
\(\frac{1}{1\cdot2}+\frac{1}{2\cdot3}+\frac{1}{3\cdot4}+.........+\frac{1}{49\cdot50}\)
GIÚP MK NHANH NHA THỨ 7 NỘP RỒI
Tìm x biết:
\(\frac{x}{3}-\frac{3}{4}=\frac{1}{12}\)
\(\frac{x}{3}=\frac{1}{12}+\frac{3}{4}\)
\(\frac{x}{3}=\frac{5}{6}\)
\(x=\frac{5}{6}.3\)
\(x=\frac{5}{2}\)
Vậy \(x=\frac{5}{2}\)
\(\frac{29}{30}-\left(\frac{13}{23}+x\right)=\frac{7}{69}\)
\(\frac{13}{23}+x=\frac{29}{30}-\frac{7}{69}\)
\(\frac{13}{23}+x=\frac{199}{230}\)
\(x=\frac{199}{230}-\frac{13}{23}\)
\(x=\frac{3}{10}\)
Vậy \(x=\frac{3}{10}\)
Bài 2: tính
\(\frac{1}{30}+\frac{1}{42}+\frac{1}{56}+\frac{1}{72}+\frac{1}{90}+\frac{1}{110}\)
\(=\frac{1}{5.6}+\frac{1}{6.7}+\frac{1}{7.8}+\frac{1}{8.9}+\frac{1}{9.10}+\frac{1}{10.11}\)
\(=\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}+\frac{1}{7}-\frac{1}{8}+\frac{1}{8}-\frac{1}{9}+\frac{1}{9}-\frac{1}{10}+\frac{1}{10}-\frac{1}{11}\)
\(=\frac{1}{5}-\frac{1}{11}\)
\(=\frac{6}{55}\)
\(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{49.50}\)
\(=\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{49}-\frac{1}{50}\)
\(=\frac{1}{1}-\frac{1}{50}\)
\(=\frac{49}{50}\)
Bài 2:
1/30+1/42+1/56+1/72+1/90+1/110
=1/5.6+1/6.7+1/7.8+1/8.9+1/9.10+1/10.11
=1/5-1/6+1/6-1/7+1/7-1/8+1/8-1/9+1/9-1/10+1/10-1/11
=1/5-1/11=6/55
b)1/1.2+1/2.3+...+1/49.50
=1-1/2+1/2-1/3+...+1/49-1/50
=1-1/50
=49/50
Tìm x, biết:
a) \(\frac{29}{30}\)-\((\frac{13}{23}\)+x\()\)=\(\frac{7}{69}\)
b) \(\frac{1}{2}\)+\(\frac{1}{6}\)+\(\frac{1}{12}\)+...+\(\frac{1}{x\left(x+1\right)}\)=\(\frac{2011}{2012}\)
a) \(\frac{29}{30}\)- (\(\frac{13}{23}\)+X)=\(\frac{7}{69}\)
\(\frac{13}{23}\)+X=\(\frac{29}{30}\)-\(\frac{7}{69}\)
\(\frac{13}{23}\)+X=\(\frac{199}{230}\)
X=\(\frac{199}{230}\)-\(\frac{13}{23}\)
X=\(\frac{3}{10}\)
b)1/2+1/6+1/12+...+1/x(x+1)=2011/2012
=>1/1.2+1/2.3+1/3.4+...+1/x(x+1)=2011/2012
=>1-1/2+1/2-1/3+1/3+1/4+...+1/x+1/x+1=2011/2012
=>1-1/x+1=2011/2012
=>1/x+1=1-2011-2012
=>1/x+1=2012/2012-2011/2012
1/x+1=1/2012
=>x+1=2012
=>x=2011
Tìm x , biết :
a) \(x+\frac{7}{12}=\frac{17}{18}-\frac{1}{9}\)
b) \(\frac{29}{30}-\left(\frac{13}{23}+x\right)=\frac{7}{69}\)
c) \(\frac{-5}{6}.\frac{125}{25}< x< \frac{-7}{15}.\frac{9}{14}\) (\(x\) thuộc Z)
d) \(\left(\frac{-5}{3}^3\right)< x< \frac{-24}{35}.\frac{-5}{6}\) ( \(x\) thuộc Z ) \(\)ththu
bài 1 : tìm x, biết
1) \(x+\frac{7}{12}=\frac{17}{18}-\frac{1}{9}\) 2) \(\frac{29}{30}-\left(\frac{13}{23}+x\right)=\frac{7}{69}\)
bài 2 : tìm x thuộc Z , biết
1) \(\frac{-5}{6}.\frac{120}{25}< x< \frac{-7}{15}.\frac{9}{14}\) 2) \(\left(\frac{-5}{3}\right)^3< x< \frac{-24}{25}.\frac{-5}{6}\)
Bài 1: Tìm x biết:
1) x +\(\frac{7}{12}\)= \(\frac{17}{18}\)- \(\frac{1}{9}\) 2) \(\frac{29}{30}\)- (\(\frac{13}{23}\)+ x) = \(\frac{7}{69}\)
x +\(\frac{7}{12}\)= \(\frac{15}{18}\) \(\frac{13}{23}\)+ x = \(\frac{29}{30}\)- \(\frac{7}{69}\)
x = \(\frac{15}{18}\)- \(\frac{7}{12}\) \(\frac{13}{23}\)+ x = \(\frac{199}{230}\)
x = \(\frac{1}{4}\) x = \(\frac{3}{10}\)
Timf x,y
1) x+\(\frac{7}{12}\)=\(\frac{17}{18}\)-\(\frac{1}{9}\)
2)\(\frac{29}{30}\)-(\(\frac{13}{23}\)+x)=\(\frac{7}{69}\)
3)\(\frac{x}{15}=\frac{4}{10}\)
4)\(\frac{x-3}{49}=\frac{-2}{7}\)
5)\(\frac{x}{3}=\frac{1}{y}\)
tìm x biết
a)x+7/12=17/18-1/9
b)29/30-(13/23+x)=7/69
a, x + 7/12 = 17/18 - 1/9
x + 7/12 = 15/18
x = 15/18 - 7/12
x = 1/4
b, 29/30 - ( 13/23 + x ) = 7/69
( 13/23 + x ) = 29/30 - 7/69
13/23 + x = 199/230
x = 199/230 - 13/23
x = 3/10
hok tốt