I=\(\frac{2^2}{1.3}\).\(\frac{3^2}{2.4}\).\(\frac{4^2}{3.5}\).\(\frac{5^2}{4.6}\).................\(\frac{999^2}{998.1000}\)=?
\(\frac{2^2}{1.3}.\frac{3^2}{2.4}.\frac{4^2}{3.5}.....\frac{999^2}{998.1000}\)
tính hợp lý
\(\frac{2^2}{1.3}.\frac{3^2}{2.4}.\frac{4^2}{3.5}...\frac{999^2}{998.1000}\)
Các bạn giúp mình nha mình đang cần gấp
\(A=\frac{2^2}{1.3}\cdot\frac{3^2}{2.4}....\frac{999^2}{998.1000}\)
\(A=\frac{2^2.3^2....999^2}{1.3.2.4.998.100}=\frac{\left(2.3.....999\right)\left(2.3....999\right)}{\left(1.2....998\right)\left(3.4....1000\right)}\)
\(A=999\cdot\frac{1}{500}=\frac{999}{500}\)( khúc này mk làm tắt, bn bỏ dấu ở trên rồi bỏ từng tử)
=?????????????????????????????????????????????????????????????????????????????????????????????????????????????????
ai choi freefire thi kb voi minh
\(A=\frac{2^2}{1.3}.\frac{3^2}{2.4}.\frac{4^2}{3.5}\)... \(\frac{999^2}{998.1000}\)=?
\(A=\frac{2^2.3^2.4^2............99^2}{1.3.2.4.3.5................998.1000}\)
\(A=\frac{1.2.3.4.5................999.1.2.3.4................999}{1.2.3.4.5.6.7..........1000.1.2.3.4..............998}\)
\(A=\frac{999.999}{1000.998}\)
\(Ko\) \(\text{chắc lắm}\)
TÍNH:\(\frac{2^2}{1.3}.\frac{3^2}{2.4}.\frac{4^2}{3.5}.\frac{5^2}{4.6}\).
\(A=\frac{2^2}{1.3}\cdot\frac{2^2}{2.4}\cdot\frac{2^2}{3.5}\cdot\frac{2^2}{4.6}\)
\(A=\frac{4}{3}\cdot\frac{1}{2}\cdot\frac{4}{15}\cdot\frac{1}{6}\)
\(A=\frac{4.1.4.1}{3.2.15.6}\)
\(A=\frac{4}{135}\)
\(\frac{2^2}{1.3}.\frac{3^2}{2.4}.\frac{4^2}{3.5}.\frac{5^2}{4.6}\)
\(=\frac{2.2}{1.3}.\frac{3.3}{2.4}.\frac{4.4}{3.5}.\frac{5.5}{4.6}\)
\(=\frac{2.3.4.5}{1.2.3.4}.\frac{2.3.4.5}{3.4.5.6}\)
\(=\frac{5}{1}.\frac{2}{6}\)
\(=\frac{5}{1}.\frac{1}{3}\)
\(=\frac{5}{3}\)
\(\frac{2^2}{1.3}.\frac{3^2}{2.4}.\frac{4^2}{3.5}.....\frac{992^2}{998.1000}\)
Giúp mình với :D Mình vote cho :))
tính
A=\(\frac{2^2}{1.3}+\frac{3^2}{2.4}+\frac{4^2}{3.5}+\frac{5^2}{4.6}+\frac{6^2}{5.7}\)
= \(\frac{2.2}{1.3}+\frac{3.3}{2.4}+\frac{4.4}{3.5}+\frac{5.5}{4.6}+\frac{6.6}{5.7}\)
= \(\frac{2.3.4.5.6}{1.2.3.4.5}+\frac{2.3.4.5.6}{3.4.5.6.7}\)
= \(\frac{2}{1}+\frac{6}{7}\)
= 2\(\frac{6}{7}\)
Mình nghĩ zậy !!!!!!!!!!!!!!!!!!
bài đó cũng có trong đề cương thi của mih
Tính hợp lí:
A=\(\frac{2^2}{1.3}.\frac{3^2}{2.4}.\frac{4^2}{3.5}.....\frac{999^2}{998.1000}\)
B,Tìm hai phân soduog có tử bằng 1 biết tổng hai phân số cộng \(\frac{1}{6}\)tích hai phần bằng\(\frac{1}{6}\)
a, \(A=\frac{2^2}{1.3}.\frac{3^2}{2.4}.\frac{4^2}{3.5}...\frac{999^2}{998.1000}\)
\(=\frac{2.2}{1.3}.\frac{3.3}{2.4}.\frac{4.4}{3.5}...\frac{999.999}{998.1000}\)
\(=\frac{2.3.4...999}{1.2.3...998}.\frac{2.3.4...999}{3.4.5...1000}\)
\(=\frac{999}{1}.\frac{2}{1000}\)
\(=\frac{999.2}{1000.1}=\frac{999.2}{500.2.1}\)
\(=\frac{999}{500}\)
Vậy \(A=\frac{999}{500}\)
chúc bạn học giỏi
Tính \(C=\frac{2^2}{1.3}.\frac{3^2}{2.4}.\frac{5^2}{3.5}.\frac{4^2}{4.6}\)
C=2.2.3.3.4.4.5.5/1.3.2.4.3.5.4.6
C=(2.3.4.5).(2.3.4.5)/(1.2.3.4).(3.4.5.6)
C=2.5/6
C=5/3
C=2^2/1.3.3^2/2.4.5^2/3.5.4^2/4.6
C= 2.2.3.3.5.5.4.4/1.3.2.4.3.5.4.6
C=(2.3.4.5).(2.3.4.5)/(1.2.3.4).(3.4.5.6)
C=5.2/6
C=5/3
\(\frac{2^2}{1.3}.\frac{3^2}{2.4}.\frac{5^2}{3.5}.\frac{4^2}{4.6}\)
\(=\frac{2^2.3^2.5^2.4^2}{1.3.2.4.3.5.4.6}\)
\(=\frac{2^2.3^2.4^2.5^2}{1.2.3^2.4^2.5.6}\)
\(=\frac{2.5}{6}\)
\(=\frac{10}{6}=\frac{5}{2}\)
Tính
F = \(\frac{2^2}{1.3}.\frac{3^2}{2.4}.\frac{4^2}{3.5}.\frac{5^2}{4.6}.\frac{6^2}{5.7}.\frac{7^2}{6.8}.\frac{8^2}{7.9}\)
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