\(=\frac{\frac{1}{3}-\frac{1}{4}+1}{\frac{1}{2}-\frac{3}{7}}\)

\(=\frac{\frac{4}{12}-\frac{3}{12}+\frac{12}{12}}{\frac{7}{14}-\frac{6}{14}}\)

\(=\frac{\frac{13}{12}}{\frac{1}{14}}\)

\(=\frac{13}{12}\times\frac{14}{1}\)

\(=\frac{13}{6}\times7\)

\(=\frac{91}{6}\)

Sai đề rồi đó bạn, phải là 1+4/13 thay vì 1+4/3 chứ

Sai thì ai giải đc, sửa đi rồi mik giải cho

Cao Ngọc Phương Trang đề đúg nha pợn

Xem nha nếu đề thế này thì mik hỗ trợ đc nhé :D

A=\(\frac{\frac{2}{4}-\frac{2}{5}+\frac{2}{7}+\frac{2}{13}}{\frac{17}{4}-\frac{17}{5}+\frac{17}{7}+\frac{17}{13}}\)

A=\(\frac{2\left(\frac{1}{4}-\frac{1}{5}+\frac{1}{7}+\frac{1}{13}\right)}{17\left(\frac{1}{4}-\frac{1}{5}+\frac{1}{7}+\frac{1}{13}\right)}\)

A=\(\frac{2}{7}\)

Easy thế đó bạn nhá :D

còn đề đó thì mik chịu. ai giải đc mik bái làm thầy :))

\(A=\frac{1.\left(0,125-\frac{1}{5}+\frac{1}{7}\right)}{3.\left(0,125-\frac{1}{5}+\frac{1}{7}\right)}+\frac{-\frac{247}{6}}{0,95}\)

\(=\frac{1}{3}+\frac{-130}{3}\)

\(=\frac{1-130}{3}=-\frac{129}{3}=-43\)

(lớp 6 HKI chưa học số nguyên âm!)

\(\frac{\frac{1}{8}-\frac{1}{5}+\frac{1}{7}}{\frac{3}{8}-\frac{3}{5}+\frac{3}{7}}+\frac{\frac{1}{2}+\frac{1}{3}-\frac{1}{5}}{\frac{3}{4}+\frac{1}{2}-\frac{3}{10}}\)\(=\frac{\frac{1}{8}-\frac{1}{5}+\frac{1}{7}}{3\left(\frac{1}{8}-\frac{1}{5}+\frac{1}{7}\right)}+\frac{60.\left(\frac{1}{2}+\frac{1}{3}-\frac{1}{5}\right)}{60.\left(\frac{3}{4}+\frac{1}{2}-\frac{3}{10}\right)}\)

\(=\frac{1}{3}+\frac{30+20-12}{45+30-18}\)\(=\frac{1}{3}+\frac{38}{57}=1\)

\(\frac{0,125-\frac{1}{5}+\frac{1}{7}}{0,375-\frac{3}{5}+\frac{3}{7}}+\frac{\frac{1}{2}+\frac{1}{3}-0,2}{\frac{3}{4}+0,5-\frac{3}{10}}\)

= \(\frac{\frac{1}{8}-\frac{1}{5}+\frac{1}{7}}{\frac{3}{8}-\frac{3}{5}+\frac{3}{7}}+\frac{\frac{2}{4}+\frac{2}{6}-\frac{2}{10}}{\frac{3}{4}+\frac{3}{6}-\frac{3}{10}}\)

= \(\frac{\frac{1}{8}-\frac{1}{5}+\frac{1}{7}}{3.\left(\frac{1}{8}-\frac{1}{5}+\frac{1}{7}\right)}+\frac{2.\left(\frac{1}{4}+\frac{1}{6}-\frac{1}{10}\right)}{3.\left(\frac{1}{4}+\frac{1}{6}-\frac{1}{10}\right)}\)

= \(\frac{1}{3}+\frac{2}{3}\)

= \(\frac{3}{3}\)

= 1

=1 nhé bạn

câu trả lơì là 1

\(\Rightarrow A=\frac{\frac{1}{2}-\frac{1}{5}+\frac{1}{7}}{\frac{3}{8}-\frac{3}{5}+\frac{3}{7}}+\frac{\frac{1}{2}+\frac{1}{3}-\frac{1}{5}}{\frac{3}{4}+\frac{1}{2}+\frac{3}{10}}\)

\(\Rightarrow A=\frac{\frac{1}{2}-\frac{1}{5}+\frac{1}{7}}{3.\left(\frac{1}{2}-\frac{1}{5}+\frac{1}{7}\right)}+\frac{\frac{1}{2}+\frac{1}{3}-\frac{1}{5}}{\frac{3}{2}.\left(\frac{1}{2}+\frac{1}{3}-\frac{1}{5}\right)}\)

\(\Rightarrow A=\frac{1}{3}+\frac{2}{3}\)

\(\Rightarrow A=1\)

92/57

\(\left(\frac{7}{5}-x\right)^3+\frac{3}{2}=0,5\)

\(\left(\frac{7}{5}-x\right)^3=\frac{1}{2}-\frac{3}{2}\)

\(\left(\frac{7}{5}-x\right)^3=-1=\left(-1\right)^3\)

\(\frac{7}{5}-x=-1\)

\(x=-1-\frac{7}{5}\)

\(x=-\frac{12}{5}\)

Vậy x = -12/5

=))

\(\left(\frac{7}{5}-x\right)^3+\frac{3}{2}=0,5\)

\(\left(\frac{7}{5}-x\right)^3=0,5-\frac{3}{2}\)

\(\left(\frac{7}{5}-x\right)^3=-1=\left(-1\right)^3\)

\(\Rightarrow\frac{7}{5}-x=-1\)

\(\Rightarrow x=\frac{8}{5}\)

Trả lời :

X = \(\frac{8}{5}\)

#Mập

Hok tốt Thần Xạo Lìn