tim x y z thoa man x2+y2+z2-xy-3y-2z+4=0
Những câu hỏi liên quan
tim x;y;z thoa man :5x-3y/4=2z-3x/5=9y-10z/7;2y-z=132
tim x;y;z thoa man :x+3y/19=3y+9z/114=5z+15x;x+y+2z=-31
tim x,y,z thuoc Zduong thoa man
x^2+y^2+z^2<xy+3y+2z
a) x4+x3+2x2+x+1=(x4+x3+x2)+(x2+x+1)=x2(x2+x+1)+(x2+x+1)=(x2+x+1)(x2+1)
b)a3+b3+c3-3abc=a3+3ab(a+b)+b3+c3 -(3ab(a+b)+3abc)=(a+b)3+c3-3ab(a+b+c)
=(a+b+c)((a+b)2-(a+b)c+c2)-3ab(a+b+c)=(a+b+c)(a2+2ab+b2-ac-ab+c2-3ab)=(a+b+c)(a2+b2+c2-ab-ac-bc)
c)Đặt x-y=a;y-z=b;z-x=c
a+b+c=x-y-z+z-x=o
đưa về như bài b
d)nhóm 2 hạng tử đầu lại và 2hangj tử sau lại để 2 hạng tử sau ở trong ngoặc sau đó áp dụng hằng đẳng thức dề tính sau đó dặt nhân tử chung
e)x2(y-z)+y2(z-x)+z2(x-y)=x2(y-z)-y2((y-z)+(x-y))+z2(x-y)
=x2(y-z)-y2(y-z)-y2(x-y)+z2(x-y)=(y-z)(x2-y2)-(x-y)(y2-z2)=(y-z)(x2-2y2+xy+xz+yz)
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1). x2y2(y-x)+y2z2(z-y)-z2x2(z-x)
2)xyz-(xy+yz+xz)+(x+y+z)-1
3)yz(y+z)+xz(z-x)-xy(x+y)
4)2a2b+4ab2-a2c+ac2-4b2c+2bc2-4abc
5)y(x-2z)2+8xyz+x(y-2z)2-2z(x+y)2
6)8x3(y+z)-y3(z+2x)-z3(2x-y)
7) (x2+y2)3+(z2-x2)3-(y2+z2)3
1). x2y2(y-x)+y2z2(z-y)-z2x2(z-x)
2)xyz-(xy+yz+xz)+(x+y+z)-1
3)yz(y+z)+xz(z-x)-xy(x+y)
4)2a2b+4ab2-a2c+ac2-4b2c+2bc2-4abc
5)y(x-2z)2+8xyz+x(y-2z)2-2z(x+y)2
6)8x3(y+z)-y3(z+2x)-z3(2x-y)
7) (x2+y2)3+(z2-x2)3-(y2+z2)3
bn gõ bài trong công thức trực quan ik, khó nhìn lắm, ko làm đc
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1) \(x^2y^2\left(y-x\right)+y^2z^2\left(z-y\right)-z^2x^2\left(z-x\right)\)
\(=x^2y^3-x^3y^2+y^2z^3-y^3z^2-z^2x^2\left(z-x\right)\)
\(=\left(y^2z^3-x^3y^2\right)-\left(y^3z^2-x^2y^3\right)-z^2x^2\left(z-x\right)\)
\(=y^2\left(z^3-x^3\right)-y^3\left(z^2-x^2\right)-z^2x^2\left(z-x\right)\)
\(=y^2\left(z-x\right)\left(z^2+zx+x^2\right)-y^3\left(z-x\right)\left(z+x\right)-z^2x^2\left(z-x\right)\)
\(=\left(z-x\right)\left[y^2\left(z^2+zx+x^2\right)-y^3\left(z+x\right)-z^2x^2\right]\)
\(=\left(z-x\right)\left[\left(y^2z^2+xy^2z+x^2y^2\right)-\left(y^3z+xy^3\right)-z^2x^2\right]\)
\(=\left(z-x\right)\left(y^2z^2+xy^2z+x^2y^2-y^3z-xy^3-z^2x^2\right)\)
\(=\left(z-x\right)\left[\left(y^2z^2-y^3z\right)-\left(x^2z^2-x^2y^2\right)+\left(xy^2z-xy^3\right)\right]\)
\(=\left(z-x\right)\left[y^2z\left(z-y\right)-x^2\left(z^2-y^2\right)+xy^2\left(z-y\right)\right]\)
\(=\left(z-x\right)\left[y^2z\left(z-y\right)-x^2\left(z-y\right)\left(z+y\right)+xy^2\left(z-y\right)\right]\)
\(=\left(z-x\right)\left(z-y\right)\left[y^2z-x^2\left(z+y\right)+xy^2\right]\)
\(=\left(z-x\right)\left(z-y\right)\left(y^2z-x^2z-x^2y+xy^2\right)\)
\(=\left(z-x\right)\left(z-y\right)\left[\left(y^2z-x^2z\right)-\left(x^2y-xy^2\right)\right]\)
\(=\left(z-x\right)\left(z-y\right)\left[z\left(y^2-x^2\right)-xy\left(x-y\right)\right]\)
\(=\left(z-x\right)\left(z-y\right)\left[z\left(y-x\right)\left(y+x\right)+xy\left(y-x\right)\right]\)
\(=\left(z-x\right)\left(z-y\right)\left(y-x\right)\left[z\left(y+x\right)+xy\right]\)
\(=\left(z-x\right)\left(z-y\right)\left(y-x\right)\left(yz+xz+xy\right)\)
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2) \(xyz-\left(xy+yz+xz\right)+\left(x+y+z\right)-1\)
\(=xyz-xy-yz-xz+x+y+z-1\)
\(=\left(xyz-xy\right)-\left(yz-y\right)-\left(xz-x\right)+\left(z-1\right)\)
\(=xy\left(z-1\right)-y\left(z-1\right)-x\left(z-1\right)+\left(z-1\right)\)
\(=\left(z-1\right)\left(xy-y-x+1\right)\)
\(=\left(z-1\right)\left[\left(xy-y\right)-\left(x-1\right)\right]\)
\(=\left(z-1\right)\left[y\left(x-1\right)-\left(x-1\right)\right]\)
\(=\left(z-1\right)\left(x-1\right)\left(y-1\right)\)
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Tim x y z thoa man x^2+2y^2+z^2-2(xy+2y+2z+8)=0 can rat gap
Cho (I): 4
x
2
+ 4x – 9
y
2
+ 1 (2x + 1 + 3y)(2x + 1 – 3y)(II): 5
x
2
– 10xy + 5
y
2
– 20
z
2
5(x + y + 2z)(x + y – 2z). A. (I) đúng, (II) sai B. (I) sai, (II) đúng C. (I), (II) đều sai D. (I), (II) đều đúng
Đọc tiếp
Cho (I): 4 x 2 + 4x – 9 y 2 + 1 = (2x + 1 + 3y)(2x + 1 – 3y)
(II): 5 x 2 – 10xy + 5 y 2 – 20 z 2 = 5(x + y + 2z)(x + y – 2z).
A. (I) đúng, (II) sai
B. (I) sai, (II) đúng
C. (I), (II) đều sai
D. (I), (II) đều đúng
Ta có
(I): 4 x 2 + 4 x – 9 y 2 + 1 = ( 4 x 2 + 4 x + 1 ) – 9 y 2 = ( 2 x + 1 ) 2 – ( 3 y ) 2
= (2x + 1 + 3y)(2x + 1 – 3y) nên (I) đúng
Và
(II):
5 x 2 – 10 x y + 5 y 2 – 20 z 2 = 5 ( x 2 – 2 x y + y 2 – 4 z 2 ) = 5 [ ( x – y ) 2 – ( 2 z ) 2 ]
= 5(x – y – 2z)(x – y + 2z) nên (II) sai
Đáp án cần chọn là: A
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Tim bo ba x y z thoa man
X^2+2y^2+2^2-2(xy+2y+2z+8)=0
Cho x,y,z là các số thực dương thoả mãn x2-y2+z2=xy+3yz+zx
Tìm Max P=\(\dfrac{x}{(2y+z)^{2}}+\dfrac{1}{xy(y+2z)}\)
Tim bo ba x y z thoa man
X^2+2y^2+2^2-2(xy+2y+2z+8)=0
Giup Minh nha can gap lam