\(P=\left(1-\frac{1}{1+2}\right)\cdot\left(1-\frac{1}{1+2+3}\right)...\left(1-\frac{1}{1+2+3+...+2014}\right)\)Khi đó \(\frac{2014}{2016}\).P=

Cho \(P=\left(1-\frac{1}{1+2}\right)+\left(1-\frac{1}{1+2+3}\right)...\left(\frac{1}{1+2+..+2014}\right)\). Khi đó \(\frac{2014}{2016}P=\)

Cho \(P=\left(1-\frac{1}{1+2}\right).\left(1-\frac{1}{1+2+3}\right)....\left(1-\frac{1}{1+2+...+2014}\right)\)

Khi đó \(\frac{2014}{2016}P=...\)

Cho \(P=\left(1-\frac{1}{1+2}\right).\left(1-\frac{1}{1+2+3}\right)...\left(1-\frac{1}{1+2+...+2014}\right)\)

Khi đó \(\frac{2014}{2016}P\)

\(A=\frac{\left(1-2\right).\left(1+2\right)}{2^2}.\frac{\left(1-3\right).\left(1+3\right)}{3^2}.......\frac{\left(1-2013\right).\left(1+2013\right)}{2013^2}.\frac{\left(1-2014\right).\left(1+2014\right)}{2014^2}\)

Tính A = \(\left(1-\frac{1}{2}\right)\left(1-\frac{1}{3}\right)\left(1-\frac{1}{4}\right)...\left(1-\frac{1}{2014}\right)\left(1-\frac{1}{2015}\right)\left(1-\frac{1}{2016}\right)\)

\(choP=\left(1-\frac{1}{1+2}\right).\left(1-\frac{1}{1+2+3}\right)...\left(1-\frac{1}{1+2+3+...+2014}\right)\) thì \(\frac{2014}{2016}P=\)

tính tích:

\(\left(1-\frac{1}{2014}\right).\left(1-\frac{2}{2014}\right).\left(1-\frac{3}{2014}\right)...\left(1-\frac{2015}{2014}\right)\)

\(M=1+\frac{1}{2}.\left(1+2\right)+\frac{1}{3}.\left(1+2+3\right)+\frac{1}{4}.\left(1+2+3+4\right)+...+\frac{1}{2014}.\left(1+2+3+...+2014\right)\)